(大学物理()一质点做半径为200米的匀加速圆周运动，已知当t=0s时质点速 大学物理题目：1．质点沿半径为R的圆周运动，运动方程为θ＝3...
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t=2s时质点的速度v=a₁t=0.08×2m/s=0.16m/s
法向加速度a₂=v²/r=0.16²/0.4 m/s²=0.064m/s²
合加速度a'=√(a₁²+a₂²)=√(0.08²+0.064²)=0.102m/s²
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绛旓細璐ㄧ偣鐨勮閫熷害涓庢椂闂寸殑鍏崇郴锛毾=d蠁/dt=t/2 褰搕=1鏃讹紝蠅=0.5 rad/s 鎵浠ユ鏃剁殑閫熷害锛歷=蠅r=0.5X0.1=0.05m/s
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