初中数学,分式方程,已知x²+1/x=5,求x²+1/x²的值？
x+1/x=5(x+1/x)^2=25
x^2+1/x^2+2=25
x^2+1/x^2=23,10,(x²+1)/x=x+1/x=5
x²+1/x²=(x+1/x)²-2=5²-2=23,2,由已知(x^2+1)/x=5可得x+1/x=5, 两边平方，得
x^2+1/(x^2)+2=25
x^2+1/(x^2)=23,2,(x²+10/x=x+1/x=5
x²+1/x²=（x+1/x）^2-2=25-2=23,1,
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