1标准大气压等于多少米水柱？ 一个标准大气压能够支持水柱的高度是多少米
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一个标准大气压的数值为1.01325×10^5Pa，代表把温度为0℃、纬度45度海平面上的气压称为1个大气压,水银气压表上的数值为760毫米水银柱高。
0℃时水银的密度为13.595×10^3千克/m³，水的密度为：1.0g/cm3。
p水银=ρ水银gh=13.595×10^3千克/m³×9.80672牛/千克×0.76米=1.01325×10^5帕。
同理可以推算出相同压力下水的压强公式：p水=ρ水gh=1.01325×10^5帕，计算得出h≈10.339m。
P=ρhg
h=P/(ρg)
=101325÷1000÷9.8
=10.3393
水柱的话是10.3393米。
75毫米汞柱
绛旓細鎵浠ョ害鏄10.34m姘存煴
绛旓細1鏍囧噯澶ф皵鍘=760mm姹炴煴=76cm姹炴煴=1.01325脳105Pa=10.336m姘存煴銆1鏍囧噯澶ф皵鍘=101325 N/銕°傦紙鍦ㄨ绠椾腑閫氬父涓 1鏍囧噯澶ф皵鍘=1.01脳105Pa)濡傛灉瑕佸仛绮剧‘璁＄畻锛屽叧绯诲涓嬶細鍘嬪姏鎹㈢畻鍏崇郴锛1杈惧洜/骞虫柟鍘樼背锛坉yn/cm2锛=0.1甯曪紙Pa锛1鎵橈紙Torr锛=133.322甯曪紙Pa锛1姣背姹炴煴锛坢mHg锛=133.322甯曪紙Pa...
绛旓細1鏍囧噯澶ф皵鍘=760mm姹炴煴=76cm姹炴煴=1.01325脳10^5Pa=10.339m姘存煴銆
绛旓細1涓爣鍑嗗ぇ姘斿帇锛屽嵆1atm=101.325kPa銆傦紙1鏍囧噯澶ф皵鍘=760mm姹炴煴=76cm姹炴煴=1.01325脳10^5Pa=10.339m姘存煴銆傦級
绛旓細1绫虫按鏌卞ぇ绾︾瓑浜0.01mpa 1鍏嗗笗(MPa)=10宸(bar)=9.8澶ф皵鍘(atm) 鈮堝崄涓ぇ姘斿帇 1鏍囧噯澶ф皵鍘=760mm姹炴煴=1.01325脳10^5Pa=10.336m姘存煴 鎵浠ワ細1鍏嗗笗=9.8*10.336=101.2928鈮101绫虫按鏌 1绫虫按鏌=0.0097mpa鈮0.01mpa
绛旓細1鏍囧噯澶ф皵鍘=760mm姹炴煴=76cm姹炴煴=1.01325脳10^5Pa=10.336m姘存煴銆1鏍囧噯澶ф皵鍘=101325 N/銕°傦紙鍦ㄨ绠椾腑閫氬父涓 1鏍囧噯澶ф皵鍘=1.01脳10^5 N/銕)銆100kPa=0.1MPa 鏍囧噯澶ф皵鍘嬶紝鍦ㄦ爣鍑嗗ぇ姘旀潯浠朵笅娴峰钩闈㈢殑姘斿帇锛屽叾鍊间负101.325kPa锛屾槸鍘嬪己鐨勫崟浣嶏紝璁颁綔atm銆傚寲瀛︿腑鏇句竴搴﹀皢鏍囧噯娓╁害鍜屽帇鍔涳紙STP...
绛旓細涓鑸及璁★細1绫虫按鏌绾绛変簬0锛01mpa銆1mpa锛10bar锛9锛8atmosphere锛圓TM锛夆増10atm銆1鏍囧噯澶ф皵鍘锛760姣背hg锛1锛01325脳10锛5Pa锛10锛336绫虫按鏌便傚洜姝わ細1mpa锛9锛8锛10锛336锛101锛2928鈮101m姘存煴銆1m姘存煴锛0锛0097mpa鈮0锛01mpa銆
绛旓細1涓爣鍑嗗ぇ姘斿帇鑳芥敮鎸10.339绫虫按鏌便傛爣鍑嗗ぇ姘斿帇鏄湪鏍囧噯澶ф皵鏉′欢涓嬫捣骞抽潰鐨勬皵鍘嬶紝1644骞寸敱鐗╃悊瀛﹀鎵橀噷鎷嗗埄鎻愬嚭锛屽叾鍊间负101.325kPa锛屾槸鍘嬪己鐨勫崟浣嶏紝璁颁綔atm銆1982骞磋捣IUPAC灏嗏滄爣鍑嗗帇鍔涒濋噸鏂板畾涔変负100 kPa銆1鏍囧噯澶ф皵鍘=760mm姹炴煴=76cm姹炴煴=1.01325脳10^5Pa=10.339m姘存煴銆1鏍囧噯澶ф皵鍘=101325 N...
绛旓細涓涓澶ф皵鍘嬬瓑浜10.34绫虫按鏌 1涓鏍囧噯澶ф皵鍘=101325Pa=10.33m姘存煴锛屼絾涓嶄唬琛ㄦ病鏈夊鍔涚殑鎯呭喌涓嬪彲浠ュ惛10绫虫按鏌便 鐢辨恫浣撳帇寮哄叕寮忓緱h=p/蟻g=1.013x10⁵pa/1.0x10³kg/m³x9.8N/kg=10.34m銆 鍥犳锛屼竴涓ぇ姘斿帇鑳藉鏀寔10.34绫崇殑姘存煴銆傚ぇ姘斿帇鐨勫熀鏈畾涔夛細姘斿帇鏄綔鐢ㄥ湪鍗曚綅闈㈢Н...
绛旓細涓鏍囧噯澶ф皵鍘鍙互鏀寔10.339m楂樼殑姘存煴銆備竴涓爣鍑嗗ぇ姘斿帇鐨勬暟鍊涓1.01325脳10^5Pa锛屼唬琛ㄦ妸娓╁害涓0鈩冦佺含搴45搴︽捣骞抽潰涓婄殑姘斿帇绉颁负1涓ぇ姘斿帇,姘撮摱姘斿帇琛ㄤ笂鐨勬暟鍊间负760姣背姘撮摱鏌遍珮銆0鈩冩椂姘撮摱鐨勫瘑搴︿负13.595脳10^3鍗冨厠/m³锛屾按鐨勫瘑搴︿负锛1.0g/cm3銆俻姘撮摱=蟻姘撮摱gh=13.595脳10^3鍗冨厠/m...
