C语言编程,输入三个双精度的数,求他们的平均值后,保留小数点后一位,并对第二位按四舍五入的方式输出 C语言中怎样输入一个双精度数,对小数点后第2位进行四舍五入,...

\uff1f\uff1f\uff1f\u7528C\u8bed\u8a00\u7f16\u5199\uff1a\u8bfb\u5165\u4e09\u4e2a\u53cc\u7cbe\u5ea6\u6570\uff0c\u6c42\u5e73\u5747\u503c\u4fdd\u7559\u5c0f\u6570\u70b9\u540e\u4e00\u4f4d\u5bf9\u5c0f\u6570\u70b9\u540e\u7b2c\u4e8c\u4f4d\u56db\u820d\u4e94\u5165\u8f93\u51fa\u7ed3\u679c

ls\u7684\u6ca1\u6709\u505a\u56db\u820d\u4e94\u5165\u5904\u7406\u3002

#include
main()
{
double a,b,c,rzt;
scanf("%lf%lf%lf",&a,&b,&c);
rzt=(a+b+c)/3;
rzt=(int)(rzt*10+0.5)/10.0; //\u56db\u820d\u4e94\u5165\u5904\u7406
printf("%.1lf\n",rzt);
}

#include
int main()
{
double a;
scanf("%lf",&a);
printf("%.1lf\n",a);
return 0;
}

#include"stdio.h"
int main()
{
double a,b,c,ans;
scanf("%lf%lf%lf",&a,&b,&c);
ans=(a+b+c)/3;
printf("%.1lf\n",ans);//格式化输出1位小数,后面自动四舍五入的
return 0;
}

用双精度控制小数点后2位就可以了,自动四舍五入!

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