应用麦克劳林公式,按x的幂展开函数f(x)=(x^2-3x+1)^3 应用麦克劳林公式

\u6309x\u7684\u5e42\u5c55\u5f00\u51fd\u6570f(x)=(x^2-3x+1)^3

\u6c42\u51fan\u9636\u5bfc\uff0c\u7136\u540e\u5957\u516c\u5f0f\u5c31\u884c


\u9ea6\u514b\u52b3\u6797\u516c\u5f0f\u6309X\u7684\u5e42\u5c55\u5f00\u51fd\u6570\u662f\u6307\u5728x0=0\u5904\u5c55\u5f00.
\u5148\u6c42\u51fa
f (0) =1 ,f '(0) = -1 ,f ''(0) = -4/3 ,f '''(0) = -6 ,.\u4ee3\u5165\u6cf0\u52d2\u516c\u5f0f\u5f97\u5230\uff08\u5c55\u5f00\u52305\u6b21\u5e42\u65f6\uff09
f (x) = 1-x-2/3*x^2-x^3-16/9*x^4-31/9*x^5

求出n阶导,然后套公式就行



f(x)=x^6-9x^5+30x^4-39x^3+x^2-3x+1f(x)=f(0)+f'(0)x+[f''(0)/2!]+...+f"""(0)/6!

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