help，有难题，请求支援，要二元一次方程组解答啊。
help ~~\u6709\u96be\u9898,\u5e2e\u624b\u89e3\u51b3\u5b5d\u5fc3\uff0c\u4fe1\u5fc3\uff0c\u6052\u5fc3\uff0c\u8010\u5fc3\uff0c\u7231\u5fc3
\u8fd8\u662f\u6709\u53ef\u80fd\u957f\u9ad8\u7684\uff0c\u5982\u679c\u4f60\u9057\u4f20\u4e86\u4f60\u7238\u7684\u663e\u6027\u57fa\u56e0\uff0c\u90a3\u4f60\u6709\u53ef\u80fd\u4f1a\u6bd4\u4f60\u7238\u8fd8\u9ad8\uff0c\u5728\u957f\u8eab\u4f53\u9636\u6bb5\uff0c\u591a\u953b\u70bc\uff0c\u5403\u591a\u70b9\u6709\u8425\u517b\u7684\uff0c\u9ad8\u662f\u81ea\u7136\u7684\uff0c
1，k²-1=0 且9(k+1)=0,解得 k=10或k=-1 此时为一元一次。
当k²-1=0,即k=1或k=-1时为二元一次。
2，（5y-8)²+|2x+4|=0, 5x-ky=0
x+5y-8=0
2x+4=0
5x-ky=0
三式联立求解可得 x=-2,y=2, k=-5
3, ax-by=4, (1) 3x-y=5 (3)
ax+by=6 (2) 4x-7y=1 (4)
(1)加(2)，2ax=10, x=5/a
(2)减(1), 2by=2, y=1/b
代入 (3),(4) 15/a-1/b=5
20/a-7/b=1
可解得 a=5/2, b=1
把这页纸撕掉就行了
绛旓細1锛宬²-1=0 涓9(k+1)=0,瑙ｅ緱 k=10鎴杒=-1 姝ゆ椂涓轰竴鍏冧竴娆°傚綋k²-1=0,鍗砶=1鎴杒=-1鏃朵负浜屽厓涓娆°2锛岋紙5y-8)²+|2x+4|=0, 5x-ky=0 x+5y-8=0 2x+4=0 5x-ky=0 涓夊紡鑱旂珛姹傝В鍙緱 x=-2,y=2, k=-5 3, ax-by=4, (1) 3x-y=5 ...
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