C语言里如何将多个字符串数据合成一个数据? 请问在C语言中如何合并多个字符串??

c\u8bed\u8a00,\u5982\u4f55\u5c06\u591a\u79cd\u7c7b\u578b\u6570\u636e\u7ec4\u6210\u4e00\u4e2a\u5b57\u7b26\u4e32

# include int main(void){ int num = 10; void *mem = # size_t bytes = 100; char buf[100]; FILE *p = fopen("D:\\abc.txt", "w"); if (NULL == p) return -1; sprintf(buf, "%d %p %ud", num, mem, bytes); fprintf(p, "%s", buf); fclose(p); }

\u7528strcat(str1, str2)\u51fd\u6570\uff0c\u5b83\u7684\u529f\u80fd\u662f\u5c06str2\u8fde\u63a5\u5728str1\u540e\u9762\uff0c\u5f53\u7136\u524d\u63d0\u662fstr1\u8981\u8db3\u591f\u957f\uff0c\u4f60\u53ef\u4ee5\u4e24\u4e2a\u4e24\u4e2a\u7684\u8fde\u63a5\uff0c\u5728\u4f7f\u7528\u524d\u8981\u5305\u542bstring.h\u5934\u6587\u4ef6\u3002

主要有两种方法,一个是字符串连接操作strcat,另一个是格式化输出sprintf,主要代码如下,

//程序功能实现字符串合并
#include <stdio.h>
#include <string.h>
int main(int argc, char *argv[])
{
char name1[32]="456",name2[32]="123",name3[32]="789";
char NAME1[256]={'\0'},NAME2[256]={'\0'};
//字符串连接函数
strcat( NAME1,name2);
strcat( NAME1,name1);
strcat( NAME1,name3);
//格式化输出
sprintf(NAME2,"%s%s%s", name2, name1, name3);

printf("%s\n",NAME1);
printf("%s\n",NAME2);
return 0;
}

char *strcat( char *str1, const char *str2 );函数将字符串str2
连接到str1的末端,并返回指针str1。

int sprintf( char *buffer, const char *format, ... );sprintf和printf类似,
只是把输出发送到buffer缓冲区中,返回值是写入的字符数量。

//将两个字符串合成一个字符串,在括号中填入适当的语句,编译
运行出正确的结果。
#include
#include
void
main()
{
char
s1[20],s2[30],s3[50];
int
i,j,lengths1,lengths2;
printf("string1:");
gets(s1);
printf("string2:");
scanf("%s\n",s2);
lengths1=strlen(s1);
lengths2=strlen(s2);
for(i=0;i
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sprintf就可以。
sprintf(NAME, "%s%s%s", name1, name2, name3);

用库函数最简单……
//#include "stdafx.h"//vc++6.0加上这一行.
#include "stdio.h"
#include "string.h"
void main(void){
char name1[32]="456",name2[32]="123",name3[32]="789",NAME[256]="";
strcat(strcat(strcpy(NAME,name2),name1),name3);
printf("%s\n",NAME);
}

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