从0到9这十个数字中任选5个,组成没有重复的五位数,这五位数是奇数的概率是多少？ 从0到9的十个数字中选5个数字,组成没有重复的五位数且被5整...
\u4ece0\u52309\u8fd910\u4e2a\u6570\u5b57\u4e2d,\u9009\u51fa5\u4e2a\u6570\u5b57\u7ec4\u6210\u6ca1\u6709\u91cd\u590d\u6570\u5b57\u7684\u4e94\u4f4d\u6570,\u6c42\u767e\u4f4d\u6570\u5b57\u662f0\u7684\u6982\u7387P(5,9) -----5\u4f4d\u6570\u4e2d\u6ca10\u7684\u60c5\u51b5
P(4,9)*4 -----5\u4f4d\u6570\u4e2d\u67090\u7684\u60c5\u51b5
P(4,9) -----\u767e\u4f4d\u6570\u5b57\u662f0\u7684\u60c5\u51b5
P(4,9)/[P(5,9)+P(4,9)*4]=9*8*7*6/(9*8*7*6*5+9*8*7*6*4)=1/9
1. \u7ec4\u6210\u6ca1\u6709\u91cd\u590d\u7684\u4e94\u4f4d\u6570\u4e14\u88ab5\u6574\u9664
\u4e2a\u4f4d\u5fc5\u987b\u662f5\u62160
(1)\u4e2a\u4f4d\u662f5\u65f6\uff0c\u4e07\u4f4d\u4e0d\u80fd\u662f0\uff0c\u6240\u4ee5\u6709A(8,1)*A(8,3)
(2)\u4e2a\u4f4d\u662f0\u65f6\uff0c\u5176\u4ed64\u4e2a\u6570\u5b57\u53ef\u4efb\u9009\uff0c\u6240\u4ee5\u6709A(9,4)
\u5171\u6709\uff1aA(8,1)*A(8,3)+A(9,4)=8*8*7*6+9*8*7*6
=8*7*6*(9+8)=5712
2. \u6ca1\u6709\u91cd\u590d\u7684\u4e94\u4f4d\u5076\u6570
\u4e2a\u4f4d\u5fc5\u987b\u662f0\uff0c2\uff0c4\uff0c6\uff0c8
(1)\u4e2a\u4f4d\u662f0\u65f6\uff0c\u6709A(9, 4)
(2) \u4e2a\u4f4d\u4e0d\u662f0\u65f6\uff0c\u9996\u4f4d\u4e0d\u80fd\u662f0\uff0c\u6709A(4,1)*A(8,1)*A(8,3)
\u5171\u6709=A(9,4)+A(4,1)*A(8,1)*A(8,3)=9*8*7*6+4*8*8*7*6
=8*7*6*(9+32)
=13776
是奇数的，有：5×8×8×7×6种
所求概率为：(5×8×8×7×6）÷(9×9×8×7×6)=40/81
8*8*7*6*5/（9*9*8*7*6）=40/81。是奇数各位只有五种可能，万位又不能为零，所以只有八种可能，其余的根据不能重复，依次减一，明白了吗？
40/81
绛旓細鑳界粍鎴愮殑5浣嶆暟锛屼竴鍏辨湁锛9脳9脳8脳7脳6绉 鏄鏁扮殑锛屾湁锛5脳8脳8脳7脳6绉 鎵姹傛鐜囦负锛(5脳8脳8脳7脳6锛壝(9脳9脳8脳7脳6)=40/81
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