已知一个角的正切值是，2分之5. 怎么用计算器求角的度数？？？？ 已知正切值用计算器求角度
\u5df2\u77e5\u6b63\u5207\u503c\u600e\u4e48\u7528\u8ba1\u7b97\u5668\u6c42\u89d2\u5ea6\uff1f\u8ba1\u7b97\u5668\u8f93\u5165"18/5=","2nd","tan"
\u5f97\u5230\u901a\u8fc7\u53cd\u6b63\u5207\u51fd\u6570\u8ba1\u7b97\u7684\u89d2\u5ea6\uff0carctan(5/18)\u224874.4759\u5ea6\u3002
\u6216\uff1a
\u6309shift\u62162ndf\u952e\u518d\u6309tan\uff0c\u8ba1\u7b97\u5668\u4f1a\u663e\u793a\u4e00\u4e2atan-1\uff0c\u7136\u540e\u518d\u8f93\u6b63\u5207\u503c\uff0c\u518d\u6309=\u6216\u8005\u5148\u8f93\u6b63\u5207\u503c\u518d\u6309shift\u62162ndf\u952e\u518d\u6309tan\uff0c\u6b64\u64cd\u4f5c\u540c\u6837\u9002\u7528\u4e8esin\u3001cos\u3002
\u6269\u5c55\u8d44\u6599\uff1a
\u6b63\u5207\u51fd\u6570y=tanx\u5728\u5f00\u533a\u95f4\uff08x\u2208(-\u03c0/2,\u03c0/2)\uff09\u7684\u53cd\u51fd\u6570\uff0c\u8bb0\u4f5cy=arctanx \u6216 y=tan-1x\uff0c\u53eb\u505a\u53cd\u6b63\u5207\u51fd\u6570\u3002\u5b83\u8868\u793a(-\u03c0/2,\u03c0/2)\u4e0a\u6b63\u5207\u503c\u7b49\u4e8e x \u7684\u90a3\u4e2a\u552f\u4e00\u786e\u5b9a\u7684\u89d2\uff0c\u5373tan(arctan x)=x\uff0c\u53cd\u6b63\u5207\u51fd\u6570\u7684\u5b9a\u4e49\u57df\u4e3aR\u5373(-\u221e\uff0c+\u221e)\u3002\u53cd\u6b63\u5207\u51fd\u6570\u662f\u53cd\u4e09\u89d2\u51fd\u6570\u7684\u4e00\u79cd\u3002
\u53c2\u8003\u8d44\u6599\u6765\u6e90\uff1a\u767e\u5ea6\u767e\u79d1-\u53cd\u6b63\u5207\u51fd\u6570
\u8ba1\u7b97\u5668\u8f93\u5165"18/5=","2nd","tan"\uff0c
\u5f97\u5230\u901a\u8fc7\u53cd\u6b63\u5207\u51fd\u6570\u8ba1\u7b97\u7684\u89d2\u5ea6\uff0carctan(5/18)\u224874.4759\u5ea6\uff0c
tan2.5
应查三角函数表
绛旓細璇烽棶浣犵殑璁＄畻鍣ㄦ槸浠涔堟牱寮忕殑鍛紵濡傛灉鏄父瑙佺殑绉戝鍨嬭绠楀櫒锛屼竴鑸兘鏄寜SHIFT+tan锛屽嵆锛坅rctan锛屾垨tan^-1锛夛紝灏卞緱鍒瑙掔殑搴︽暟浜嗐
绛旓細鈮21掳48'5"
绛旓細X^2+5X^2=12锛孹^2=2锛X=鈭2锛屸埓AB=3X=3鈭2锛屸憽鈭燗涓哄簳瑙掞紝AB=BC锛岃繃AH=1/2BC=1锛屽張tanA=BH/AH=鈭5/2锛屸埓BH=鈭5/2锛屸埓AB=鈭(AH^2+BH^2)=3/2銆
绛旓細浣犲ソ锛屽緢楂樺叴涓烘偍瑙ｇ瓟銆傛弧瓒冲嬀鑲″畾鐞嗭紝鎵浠ユ湁涓涓鏄90搴︼紝鍙﹀涓や釜瑙掍腑锛岀涓涓锛姝ｅ垏鍊锛1/2锛涙寮﹀笺1/5锛涗綑寮﹀笺2/5 绗簩涓锛90搴 绗笁涓锛氭鍒囧笺2锛涙寮﹀笺2/5;浣欏鸡鍊硷細1/5
绛旓細鍥犱负姝ｅ垏鍊鏄(5^0.5)/2锛屾墍浠ュ彲浠ヨ楂樹负5^0.5锛屽垯绛夎叞涓夎褰㈢殑搴曟槸2*2=4锛岃叞鏄紙5+2^2锛塣0.5=3,銆傜敱浣欏鸡瀹氱悊椤惰鐨勪綑寮﹀间负(3^2+3^2-4^2)/2*3*3=1/9銆
绛旓細鍙互鐢ㄤ簩鍊嶈鍏紡
绛旓細宸茬煡涓涓鐨勬鍒囧鐨勮寖鍥存槸銆-1/2,1銆,涓斿凡鐭ヨ繖涓鍦ㄣ0,pai)涔嬮棿 姹傞棶杩欎釜瑙掔殑鑼冨洿 姹 宸茬煡涓涓鐨勬鍒囧肩殑鑼冨洿鏄-1/2,1銆,涓斿凡鐭ヨ繖涓鍦ㄣ0,pai)涔嬮棿姹傞棶杩欎釜瑙掔殑鑼冨洿姹傝繃绋嬭阿璋... 宸茬煡涓涓鐨勬鍒囧肩殑鑼冨洿鏄-1/2,1銆,涓斿凡鐭ヨ繖涓鍦ㄣ0,pai)涔嬮棿 姹傞棶杩欎釜瑙掔殑鑼冨洿姹傝繃绋 璋㈣阿...
绛旓細2銆乼an135掳=-1.3銆乼an150掳=鈥滆礋3鍒嗕箣鏍瑰彿3鈥濄備簲銆佸钩瑙掞細tan180掳=0銆傛敞锛氫簰涓鸿ˉ瑙掔殑涓涓鐨勬鍒囧浜掍负鐩稿弽鏁般傚父瑙佺壒娈婅鐨勬鍒囧硷細涓銆佸鍋舵э細姝ｅ垏鍑芥暟y=tanx鏄鍑芥暟銆傚湪姝ｅ垏鍑芥暟鏈夋剰涔夌殑鍓嶆彁涓嬶紝绛夊紡tan(-x)=-tanx鎭掓垚绔嬨備緥锛歵an(-45掳)=-tan45掳=-1銆浜銆佸懆鏈熸э細姝ｅ垏鍑芥暟...
绛旓細鍖栨垚涓鑸紡 y=3x/4+7/4 浠鐐逛负鍦嗗績,|AB|涓哄崐寰勭殑鍦嗕氦AC 浜嶥(a,b) 鐐 D鐐瑰悓鏃舵弧瓒 b=3a/4+7/4 鍜 (a-3)^2+(b-4)^2=25 瑙ｈ仈绔嬫柟绋嬬粍,寰楀埌 a=-1,b=1 DB鐨勪腑鐐瑰潗鏍囨槸M[(-1+6)/2,(1+0)/2] 鍗 M(2.5,0.5)杩嘇M鐨勭洿绾垮氨鏄A鐨勫钩鍒嗙嚎AT 鏄 (y-0.5)/(4-...
绛旓細BF=CE=鈭3锛孎G=鈭3/2锛鍕捐偂鈻矯FG寰桟G=鈭7/2锛岃В鈻矯EG锛岀敤浣欏鸡瀹氱悊锛歝os鈭燙EG=锛圕E²+EG²-CG²锛/锛2CE脳EG锛=锛3+3/4-7/4锛/锛2脳鈭3脳鈭3/2锛=2/3锛宻in鈭燙EG=鈭氾紙1-4/9锛=鈭5/3 tan鈭燙EG=鈭5/2 鍗矨F涓嶤E鎵鎴愮殑瑙掔殑姝ｅ垏鍊涓衡垰5/2....
