c语言从键盘上输入一个4位整数，输出其个位、十位、百位、千位上的数字，并求和。（代码15分，调试1 用c语言编程？（输入一个四位数,求出它的个位、十位、百位、千...
\u7528c\u8bed\u8a00\u7f16\u7a0b:\u8f93\u5165\u4e00\u4e2a\u56db\u4f4d\u6570,\u6c42\u51fa\u5b83\u7684\u4e2a\u4f4d\u3001\u5341\u4f4d\u3001\u767e\u4f4d\u3001\u5343\u4f4dC\u4ee3\u7801:---------------------
int a;
scanf("%d",&a);
printf("\u4e2a\u4f4d:%d,\u5341\u4f4d:%d,\u767e\u4f4d:%d,\u5343\u4f4d:%d",a%10,a%100/10,a%1000/100,a/1000)
--------------------------------
VC++\u4e2d\u4ee3\u7801\u5982\u4e0b:
#include "stdafx.h"
#include
int main(int argc, char* argv[])
{
int a;
scanf("%d",&a);
printf("\u4e2a\u4f4d:%d,\u5341\u4f4d:%d,\u767e\u4f4d:%d,\u5343\u4f4d:%d",a%10,a%100/10,a%1000/100,a/1000);
system("pause");
return 0;
}
C\u8bed\u8a00\u6709\u4ee5\u4e0b\u51e0\u79cd\u53d6\u6574\u65b9\u6cd5\uff1a
1\u3001\u76f4\u63a5\u8d4b\u503c\u7ed9\u6574\u6570\u53d8\u91cf\u3002\u5982\uff1a
int i = 2.5; \u6216 i = (int) 2.5;
\u8fd9\u79cd\u65b9\u6cd5\u91c7\u7528\u7684\u662f\u820d\u53bb\u5c0f\u6570\u90e8\u5206\uff0c\u53ef\u4ee5\u7528\u4e8e\u4f60\u7684\u95ee\u9898\u3002
2\u3001C/C++\u4e2d\u7684\u6574\u6570\u9664\u6cd5\u8fd0\u7b97\u7b26"/"\u672c\u8eab\u5c31\u6709\u53d6\u6574\u529f\u80fd(int / int)\uff0c\u800c\u4e0b\u9762\u4ecb\u7ecd\u7684\u53d6\u6574\u51fd\u6570\u8fd4\u56de\u503c\u662fdouble\u3002\u6574\u6570\u9664\u6cd5\u5bf9\u6b63\u6570\u7684\u53d6\u6574\u662f\u820d\u53bb\u5c0f\u6570\u90e8\u5206\uff0c\u4f46\u662f\u6574\u6570\u9664\u6cd5\u5bf9\u8d1f\u6570\u7684\u53d6\u6574\u7ed3\u679c\u548c\u4f7f\u7528\u7684C\u7f16\u8bd1\u5668\u6709\u5173\u3002
3\u3001\u4f7f\u7528floor\u51fd\u6570\u3002floor(x)\u8fd4\u56de\u7684\u662fx\u7684\u6574\u6570\u90e8\u5206\u3002\u5982\uff1a
floor(2.5) = 2
floor(-2.5) = -3
4\u3001\u4f7f\u7528ceil\u51fd\u6570\u3002ceil(x)\u8fd4\u56de\u7684\u662f\u4e0d\u5927\u4e8ex\u7684\u6700\u5c0f\u6574\u6570\u3002\u5982\uff1a
ceil(2.5) = 2
ceil(-2.5) = -2
floor\u548cceil\u5bf9\u4e8e\u6b63\u6570\u6ca1\u6709\u533a\u522b\uff0c\u4f46\u662f\u5bf9\u4e8e\u8d1f\u6570\u7ed3\u679c\u4e0d\u540c\u3002floor()\u662f\u5411\u8d1f\u65e0\u7a77\u5927\u820d\u5165\uff0cfloor(-2.5) = -3\uff1bceil()\u662f\u5411\u6b63\u65e0\u7a77\u5927\u820d\u5165\uff0cceil(-2.5) = -2\u3002
C\u4ee3\u7801:---------------------
int a;
scanf("%d",&a);
printf("\u4e2a\u4f4d:%d,\u5341\u4f4d:%d,\u767e\u4f4d:%d,\u5343\u4f4d:%d",a%10,a%100/10,a%1000/100,a/1000)
--------------------------------
VC++\u4e2d\u4ee3\u7801\u5982\u4e0b:
#include "stdafx.h"
#include
int main(int argc, char* argv[])
{
int a;
scanf("%d",&a);
printf("\u4e2a\u4f4d:%d,\u5341\u4f4d:%d,\u767e\u4f4d:%d,\u5343\u4f4d:%d",a%10,a%100/10,a%1000/100,a/1000);
system("pause");
return 0;
}
C\u8bed\u8a00\u6709\u4ee5\u4e0b\u51e0\u79cd\u53d6\u6574\u65b9\u6cd5\uff1a
1\u3001\u76f4\u63a5\u8d4b\u503c\u7ed9\u6574\u6570\u53d8\u91cf\u3002\u5982\uff1a
int i = 2.5; \u6216 i = (int) 2.5;
\u8fd9\u79cd\u65b9\u6cd5\u91c7\u7528\u7684\u662f\u820d\u53bb\u5c0f\u6570\u90e8\u5206\uff0c\u53ef\u4ee5\u7528\u4e8e\u4f60\u7684\u95ee\u9898\u3002
2\u3001C/C++\u4e2d\u7684\u6574\u6570\u9664\u6cd5\u8fd0\u7b97\u7b26"/"\u672c\u8eab\u5c31\u6709\u53d6\u6574\u529f\u80fd(int / int)\uff0c\u800c\u4e0b\u9762\u4ecb\u7ecd\u7684\u53d6\u6574\u51fd\u6570\u8fd4\u56de\u503c\u662fdouble\u3002\u6574\u6570\u9664\u6cd5\u5bf9\u6b63\u6570\u7684\u53d6\u6574\u662f\u820d\u53bb\u5c0f\u6570\u90e8\u5206\uff0c\u4f46\u662f\u6574\u6570\u9664\u6cd5\u5bf9\u8d1f\u6570\u7684\u53d6\u6574\u7ed3\u679c\u548c\u4f7f\u7528\u7684C\u7f16\u8bd1\u5668\u6709\u5173\u3002
3\u3001\u4f7f\u7528floor\u51fd\u6570\u3002floor(x)\u8fd4\u56de\u7684\u662fx\u7684\u6574\u6570\u90e8\u5206\u3002\u5982\uff1a
floor(2.5) = 2
floor(-2.5) = -3
4\u3001\u4f7f\u7528ceil\u51fd\u6570\u3002ceil(x)\u8fd4\u56de\u7684\u662f\u4e0d\u5927\u4e8ex\u7684\u6700\u5c0f\u6574\u6570\u3002\u5982\uff1a
ceil(2.5) = 2
ceil(-2.5) = -2
floor\u548cceil\u5bf9\u4e8e\u6b63\u6570\u6ca1\u6709\u533a\u522b\uff0c\u4f46\u662f\u5bf9\u4e8e\u8d1f\u6570\u7ed3\u679c\u4e0d\u540c\u3002floor()\u662f\u5411\u8d1f\u65e0\u7a77\u5927\u820d\u5165\uff0cfloor(-2.5) = -3\uff1bceil()\u662f\u5411\u6b63\u65e0\u7a77\u5927\u820d\u5165\uff0cceil(-2.5) = -2\u3002
#include<stdio.h>
int main()
{int x,a,b,c,d,s;
scanf("%d",&x);
a=x/1000;
b=x/100%10;
c=x/10%10;
d=x%10;
s=a+b+c+d;
printf("%d %d %d %d
%d",a,b,c,d,s);
return 0;
}
#include "stdio.h"
int main(int argc,char *argv[]){
int n,s,t;
printf("Please enter n(int 999<n<10000)...
n=");
if(scanf("%d",&n)!=1 || n<1000 || n>9999){
printf("Input error, exit...
");
return 0;
}
for(s=0;n;n/=10){
printf("%d ",t=n%10);
s+=t;
}
printf("
The sum of them is %d
",s);
return 0;
}
运行样例：
绛旓細include<stdio.h>int main(){int x,a,b,c,d,s; scanf("%d",&x); a=x/1000; b=x/100%10; c=x/10%10; d=x%10; s=a+b+c+d; printf("%d %d %d %d\n%d",a,b,c,d,s); return 0;}
绛旓細浠ヤ笅鏄娇鐢 C 璇█鍒ゆ柇杈撳叆鐨鍥涗綅鏁存暟鏄惁涓洪棸骞寸殑浠ｇ爜锛歚``c include <stdio.h> int main() { int year;printf("璇杈撳叆涓涓骞翠唤锛");scanf("%d", &year);if (year % 4 == 0 && year % 100 != 0 || year % 400 == 0) { printf("%d 鏄棸骞淬", year);} else { printf(...
绛旓細int main( ){ int num[4];for(int i = 0 ; i < 4 ; i++){ scanf("%d", num+i);} for(int i = 0 ; i < 4 ; i++){ int k = i;for(int j = i+1 ; j < 4 ; j++){ if(num[k] > num[j]){ k = j;} } if(k != i){ int temp = num[k];num[k...
绛旓細printf("鐧句綅鏁板瓧鏄細%d\n",two);printf("鍗佷綅鏁板瓧鏄細%d\n",three);printf("涓綅鏁板瓧鏄細%d\n",four);printf("\n杈撳叆鐨鍥浣嶆暟姣忎綅鐩稿姞寰楋細%d\n",total);return 0;}
绛旓細鍙互鍙傝冧笅闈㈢殑浠ｇ爜锛歩nclude<stdio.h> void main(){ int n,i;printf("璇杈撳叆涓涓洓浣嶆暣鏁锛歕n");scanf("%d",&n);if (n>999&&n<10000){ while (n>0){ i=n%10;switch(i){ case (0): printf("zero ",i);break;case (1):printf("one ",i); break;case (2):printf("two ...
绛旓細include<stdio.h> void main(void){ inta,i,sum=0;inttemp,b;printf("璇杈撳叆涓涓洓浣嶆暟锛歕n");scanf("%d",&a);for(i=0;i<4;i++){ temp=a%10;a/=10;sum+=temp;} printf("%d鐨勫悇涓暟瀛椾箣鍜屼负锛%d",b,sum);//sum灏辨槸鏈鍚庣殑缁撴灉 } ...
绛旓細include "stdio.h"int main (){ int x,y; //x鏄師鏁板瓧锛寉鏄掑簭鍚庣殑鏁板瓧 printf("璇杈撳叆鍘熸暟瀛:");scanf("%d",&x) ;if(x>9999) printf("杈撳叆鏁板瓧涓嶈兘瓒呰繃9999");else { for(y=0;x!=0;x=x/10 )y=y*10+x%10;} printf("鍊掑簭鍚庣殑鏁板瓧鏄細%d",y);system("pause");} ...
绛旓細杈撳叆涓涓洓浣嶆暟:");scanf("%d",&num);if(num <1000 ||num > 9999) continue;gw = (num%10 + 5)%10;num /= 10;sw = (num%10 + 5)%10;num /= 10;bw = (num%10 + 5)%10;num /= 10;qw = (num%10 + 5)%10;num /= 10;printf("%d%d%d\n",gw,sw,bw,qw);...
绛旓細printf("璇杈撳叆涓涓洓浣嶆暣鏁\n");//杈撳嚭鎻愮ず璇彞 scanf("%d",&x);//浠庡睆骞曚笂鑾峰彇杩欎釜鍥涗綅鏁 a=x%10;//鑾峰彇涓綅 b=(x%100)/10;//鑾峰彇鍗佷綅 c=(x%1000)/100;//鑾峰彇鐧句綅 d=x/1000;//鑾峰彇鍗冧綅 printf("%d鍚勪綅鐩稿姞缁撴灉涓%d\n",x,a+b+c+d);//杈撳嚭杩欎釜鍥涗綅鏁板強鍏跺悇浣嶇殑鍜 } vc...
绛旓細e=(1000*a)+(100*b)+(10*c)+(1*d);杩欐璁＄畻涓嶅嚭a锛宐锛宑锛宒鐨勫 杩欓噷璁＄畻a锛宐锛宑锛宒鐨勫艰鐢ㄥ彇浣欑鍙 d=e%10; //d鏄痚鐨勪釜浣嶆暟 鍙栦綑绗﹀彿灏辨槸鍙栦綑鏁帮紝姣斿锛 123%10=3 c=(e/10)%10; //c鏄崄浣嶆暟 杩欓噷 e/10 寰楀埌鐨勫彧鏄鏁存暟閮ㄥ垎锛屾瘮濡傦細123/10=12 b=(e/100)...
