java怎么样输出字符串中的字符? java怎么样输出字符串中的字符?

java\u7684\u5b57\u7b26\u4e32\u53ef\u4ee5\u7528\u5355\u4e2a\u7684\u5b57\u7b26\u8f93\u51fa\u5417\uff1f

public class Test2 {
public static void main(String[] args) {
String s="abcdefg";
char[] str=s.toCharArray();
for (char i:str) {
System.out.print(i+" , ");
}

}
}
\u4f60\u53ef\u4ee5\u628a\u7b2c\u4e09\u884cString s;\u7684\u503c\u6539\u6210\u4f60\u60f3\u8981\u7684\uff0c\u6216\u8005\u53ef\u4ee5\u901a\u8fc7Scanner\u6765\u4ece\u63a7\u5236\u53f0\u63a5\u53d7\u8f93\u5165\u8fdb\u6765\u7684\u5b57\u7b26\u4e32\uff0c\u7136\u540e\u8fdb\u884c\u8f6c\u6362\u3002
\u5e0c\u671b\u8fd9\u4e2a\u56de\u7b54\u5bf9\u4f60\u6709\u5e2e\u52a9\u3002

\u4ee3\u7801\u6539\u597d\uff0c\u4f60\u4e4b\u6240\u4ee5\u51fa\u9519\u662f\u56e0\u4e3a\u90a3\u4e2a
for (int i = 0; i < d.length; i++)
{
for (int j = 0; j < d.length; j++)
{
\u8fd9\u6837\u7684\u8bdd\u4f60\u60f3\u60f3\uff0c\u5982\u679c\u662f"abcabc",\u90a3\u5c31\u53d8\u6210"a"--"abcabc",b--"abcabc",c--"abcabc","a"--"abcabc",b--"abcabc",c--"abcabc"
\u800c\u4f60\u6bcf\u6b21\u90fd\u5f80\u6570\u7ec4\u91cc\u52a0\u4e00\u4e2a\uff0c\u6240\u4ee5\u91cd\u590d\u4e86\uff0c\u6539\u597d\u7684\u4ee3\u7801\u5728\u4e0b\u9762\u3002




import java.lang.String;

public class Charx {
public static void main(String args[]) {
System.out.println("\u8bf7\u8f93\u5165\u5b57\u7b26\u4e32");
String str = "how are you doing this?";
// String str = "aaa bbb ccc ddd";
System.out.println(str);

int sum[] = new int[100];
char d[] = str.toCharArray();
StringBuffer sb = new StringBuffer("");
boolean isAdd = false;
int i=0;
int j=0;

for(i=0;i<d.length;i++){
for(j=0;j<sb.length();j++){
//\u5982\u679c\u8be5\u5b57\u7b26\u5df2\u7ecf\u51fa\u73b0\u8fc7
if(d[i] == sb.charAt(j)){
++sum[j];
isAdd = true;
break;
}
isAdd = false;
}
//\u5982\u679c\u672a\u6dfb\u52a0\uff0c\u8bf4\u660e\u662f\u65b0\u51fa\u73b0\u7684\u5b57\u7b26
if(!isAdd){
sb.append(d[i]);
sum[sb.length()]++;

}
}
for (i = 0; i < sb.length(); i++) {
System.out.println(sb.charAt(i) + "\u51fa\u73b0" + sum[i] + "\u6b21");
}

}
}

参考编程:
import java.lang.*;
import javax.swing.*;
class A
{
static int i,j,max;
int count[]=new int[100];
char c[];
void setmax(String x)
{
max=x.length();
}
void sort(String x)
{
c=x.toCharArray();
for(i=0;i<max;i++)
count[i]=1;
for(i=max-1;i>0;i--)
{ for(j=0;j<i;j++)
{ if(c[i]==c[j])
{
count[j]++;
count[i]=0;
break;
}
}

}
}
void print()
{
int i,j=1;
System.out.println("字符串中每个字符出现的次数如下!");
System.out.println(" 字符"+" 出现次数");
for(i=0;i<max;i++)
if(count[i]!=0)
{
System.out.println("第"+j+"个字符是: "+c[i]+" "+count[i]);
j++;
}
}
}
class E
{ public static void main(String args[])
{ char c[];
String s;
s=JOptionPane.showInputDialog("请输入字符串:");
System.out.println("你输入字符串: "+s);
A a=new A();
a.setmax(s);
System.out.println("你输入字符串长为: "+a.max);
a.sort(s);
a.print();
System.exit(0);
}

你在输出的时候定义一个数组把你输入的字母放到里面。然后输出第二个字母的时候到那个数组里去找,看看有没有,有就不输出,没有就输出,在没有的情况下,在把第二个字母放到这个数组里去!
以此类推

使用循环输出啊 for循环

System.out.println(字符串变量)

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