求初二物理下册压强计算题10题
\u6c42\u521d\u4e8c\u7269\u7406\u4e0b\u518c\u538b\u5f3a\u8ba1\u7b97\u989810\u98982011\u5e74\u7269\u7406\u8ba1\u7b97\u4e13\u9898\u56db \u6709\u5173\u56fa\u4f53\u538b\u5f3a\u3001\u6db2\u4f53\u538b\u5f3a\u8ba1\u7b97\uff08\u5bb9\u6613\u9898+\u63d0\u9ad8\u9898\uff09\u7b54\u6848
\u4e00\u3001\u538b\u5f3a\u7684\u8ba1\u7b97\u516c\u5f0fP\uff1dF\uff0fS \uff08\u9002\u7528\u4e8e\u6240\u6709\u538b\u5f3a\uff09
P\uff1d\u03c1gh\uff08\u9002\u7528\u4e8e\u6db2\u4f53\u538b\u5f3a\u548c\u5bc6\u5ea6\u5747\u5300\u7684\u67f1\u4f53\u5bf9\u6c34\u5e73\u9762\u7684\u538b\u5f3a\uff09
\u9644\uff1a\u5355\u4f4d\u6362\u7b97
1\uff1a\u9762\u79ef\u5355\u4f4d
\u9762\u79ef\u7684\u5355\u4f4d\u6709\u5e73\u65b9\u7c73\uff08m2\uff09\u3001\u5e73\u65b9\u5206\u7c73\uff08dm2\uff09\u3001\u5e73\u65b9\u5398\u7c73\uff08cm2\uff09\u3001\u5e73\u65b9\u6beb\u7c73\uff08mm2 \uff09\u3001
\u5b83\u4eec\u4e4b\u95f4\u7684\u6362\u7b97\u5173\u7cfb\u4e3a\uff1a1m2=102 dm2\uff0c 1 dm2=102 cm2\uff0c 1 m2=104 cm2,1 mm2 = 10\uff0d6m2 , 1 cm2 = 10\uff0d4 m2
\u7ec3\u4e60\uff1a 30mm2\uff1d 3\u00d710 5 m2\uff0c50cm2\uff1d5\u00d710\uff0d3 m2\uff0c20dm2\uff1d0.2 m2\uff0c
2\uff1a\u4f53\u79ef\u5355\u4f4d
\u4f53\u79ef\u7684\u5355\u4f4d\u6709\u7acb\u65b9\u7c73\uff08m3\uff09\u3001\u7acb\u65b9\u5206\u7c73\uff08dm3\uff09\u3001\u7acb\u65b9\u5398\u7c73\uff08cm3\uff09\u3001\u7acb\u65b9\u6beb\u7c73\uff08mm3 \uff09\u3001\u56fd\u9645\u5355\u4f4d\u662fm3
1m3 =103dm3 , 1 dm3=103 cm3 ,1 m3=106cm3 , 1 cm3 = 10 6 m3
3\uff1a\u5bb9\u79ef\u5355\u4f4d
\u5bb9\u79ef\u7684\u5355\u4f4d\u6709\uff1a\u5347\uff08 \uff09\u3001\u6beb\u5347\uff08 \uff09\u3001
1L= 103 mL 1mL= 1 cm3 1L= 1 dm3 1L= 1dm3 =103mL=103 cm3
3L= 3 dm3=3\u00d7103mL\uff08cm3\uff09 9mL= 9 cm3
\u7ec3\u4e60\uff1a 20 mL = 20 cm3\uff0c 1000 cm3 = 1 dm3 1000 cm3 = 10-3 m3 2500 = 2.5 m3
2.5 m3= 2.5 \u00d7106 cm3 0.5 = 500 cm3 2.5 m3= 2.5 \u00d7103 2.5 =2.5 \u00d7103 cm3
4\uff1a\u8d28\u91cf\u5355\u4f4d
\u8d28\u91cf\u7684\u56fd\u9645\u5355\u4f4d\u662f\u5343\u514b(kg)\uff0c\u5e38\u7528\u7684\u5355\u4f4d\u6709\u5428\uff08t\uff09\u3001\u514b\uff08g\uff09\u3001\u6beb\u514b\uff08m g\uff09\uff0c
\u5b83\u4eec\u4e4b\u95f4\u7684\u6362\u7b97\u5173\u7cfb\u4e3a1 t =1000 kg\uff0c 1 kg =1000 g\uff0c 1 g =1000 mg
\u7ec3\u4e60\u9898\uff1a 1t\uff1d 1000 kg\uff0c1g\uff1d 10\uff0d3 kg\uff0c1mg\uff1d 10\uff0d6 kg
0.03t\uff1d 30 kg\uff0c30g\uff1d 0.03 kg\uff0c30mg\uff1d 3\u00d710\uff0d5 kg
\u4e8c\u3001\uff08\u89e3\u9898\u6280\u5de7\uff09\u6709\u5173\u538b\u5f3a\u7684\u8ba1\u7b97
\u6ce8\u610f\uff1a1\uff1a\u6c42\u5bb9\u5668\u5bf9\u684c\u9762\u7684\u538b\u5f3a \u5c5e\u4e8e\u56fa\u4f53\u7c7b\u578b\uff0c\u53ef\u5148\u6c42\u51fa\u5bb9\u5668\u5bf9\u684c\u9762\u7684\u538b\u529bF=G\uff0c\uff08\u5b83\u662f\u7531\u5bb9\u5668\u91cd\u548c\u6c34\u91cd\u5171\u540c\u5f15\u8d77\u7684\uff09 \uff0c\u518d\u5229\u7528P\uff1dF\uff0fS\uff0c\u6c42\u5bb9\u5668\u5bf9\u684c\u9762\u7684\u538b\u5f3a
2\uff1a\u6c42\u6c34\u5bf9\u5bb9\u5668\u5e95\u7684\u538b\u529b\uff0c\u5e94\u5148\u6c42\u51fa\u6c34\u5bf9\u5bb9\u5668\u5e95\u7684\u538b\u5f3aP\uff1d\u03c1gh\uff0c\u518d\u5229\u7528F\uff1dPS\u6c42\u6c34\u5bf9\u5bb9\u5668\u5e95\u7684\u538b\u529b\u3002\uff08\u56e0\u4e3a\u8fd9\u65f6\u7684F\u4e0d\u4e00\u5b9a\u7b49\u4e8eG\uff09
\uff08\u4e00\uff09\u3001\u56fa\u4f53\u538b\u5f3a\u7684\u8ba1\u7b97\uff08\u5bb9\u6613\u9898\uff09
1\u3001 (09\u4e0a\u6d77) \u201c\u6d77\u5b9d\u201d\u662f2010\u5e74\u4e16\u535a\u4f1a\u7684\u5409\u7965\u7269\uff0c\u5176\u5f62\u8c61\u5982\u56fe1\u6240\u793a\u3002\u5728\u70b9\u7f00\u4e0a\u6d77\u8857\u5934\u7684\u5404\u79cd\u201c\u6d77\u5b9d\u201d\u4e2d\uff0c\u6709\u4e00\u5ea7\u201c\u6d77\u5b9d\u201d\uff08\u6750\u8d28\u5747\u5300\u3001\u5b9e\u5fc3\uff09\u7684\u8d28\u91cf\u4e3a3.0\u00d7103\u5343\u514b\uff0c\u5bc6\u5ea6\u4e3a1.5\u00d7103\u5343\u514b/\u7c733\uff0c\u4e0e\u6c34\u5e73\u5730\u9762\u7684\u63a5\u89e6\u9762\u79ef\u4e3a1\u7c732\uff0c\uff08g\u53d610N/kg\uff0e\uff09\u6c42\u5176
\u2460\u4f53\u79efV\u3002 \u2461\u91cd\u529b\u5927\u5c0fG\u3002 \u2462\u5bf9\u5730\u9762\u7684\u538b\u5f3ap
\u7b54\u6848\uff1a\uff081\uff09V\uff1dm/r\uff1d3.0\u00d7103\u5343\u514b/\uff081.5\u00d7103\u5343\u514b/\u7c733\uff09\uff1d2\u7c733
\uff082\uff09G\uff1dmg\uff1d3.0\u00d7103\u5343\u514b´10\u725b/\u5343\u514b\uff1d3\u00d7104\u725b
\uff083\uff09p\uff1dF/S\uff1dG/S\uff1d3\u00d7104\u725b/\uff081\u7c732\uff09\uff1d3\u00d7104\u5e15
2\u3001\uff0808\u5b81\u5fb7\uff09 \u5982\u56fe\u6240\u793a,\u4e00\u5934\u5927\u8c61\u7684\u8d28\u91cf\u4e3a6.3\u00d7103\u338f\u7684\u5927\u8c61,\u6bcf\u652f\u811a\u638c\u7684\u7740\u5730\u9762\u79ef\u4e3a600 c\u33a1\uff0c\uff08g\u53d610N/kg\uff0e\uff09\u95ee:
1\u3001 \u5927\u8c61\u53d7\u5230\u7684\u91cd\u529b\u4e3a\u591a\u5c11\u725b?
2 \u3001\u5f53\u5927\u8c61\u62ac\u8d77\u4e00\u652f\u811a,\u4e09\u652f\u811a\u7740\u5730\u65f6\u5bf9\u6c34\u5e73\u5730\u9762\u7684\u538b\u5f3a\u662f\u591a\u5c11Pa?
3\u3001\uff0809\u5b89\u987a\uff09\u5982\u56fe \u6240\u793a\uff0c\u5c0f\u534e\u5728\u6ed1\u51b0\u573a\u4e0a\u5feb\u901f\u6ed1\u884c\uff0c\u572810s\u5185\u6ed1\u884c80m \uff0c\u5979\u548c\u51b0\u5200\u7684\u603b\u8d28\u91cf\u4e3a40kg\uff0c\u5df2\u77e5\u6bcf\u53ea\u51b0\u5200\u4e0e\u51b0\u9762\u7684\u63a5\u89e6\u9762\u79ef\u4e3a15cm2\u3002\uff08g\u53d610N/kg\uff0e\uff09\u95ee\uff1a
\uff081\uff09\u5c0f\u534e\u53d7\u5230\u7684\u91cd\u529b\u662f\u591a\u5927\uff1f
\uff082\uff09\u5c0f\u534e\u6ed1\u884c\u7684\u5e73\u5747\u901f\u5ea6\u662f\u591a\u5927\uff1f
\uff083\uff09\u5c0f\u534e\u5728\u5355\u811a\u6ed1\u884c\u65f6\u5bf9\u51b0\u9762\u7684\u538b\u5f3a\u662f\u591a\u5927\uff1f\u5f53\u5c0f\u534e\u53cc\u811a\u7ad9\u7acb\u65f6\uff0c\u5979\u5bf9\u51b0\u9762\u7684\u538b\u5f3a\u600e\u6837\u53d8\u5316\uff0c\u7b80\u8981\u8bf4\u660e\u7406\u7531\u3002
4\u3001\uff0809\u6c5f\u82cf\uff09\u7f6e\u4e8e\u6c34\u5e73\u5730\u9762\u4e0a\u7684\u77f3\u67f1\uff0c\u9ad8\u4e3a0.4m\uff0c\u6a2a\u622a\u9762\u79ef\u4e3a0.15m2\uff0c\u8d28\u91cf\u4e3a150kg\uff0cg\u53d610N/kg\uff0e\u6c42\uff1a
\uff081\uff09\u77f3\u67f1\u7684\u91cd\u529b\uff1b \uff082\uff09\u77f3\u67f1\u7684\u5bc6\u5ea6\uff1b\uff083\uff09\u77f3\u67f1\u5bf9\u6c34\u5e73\u5730\u9762\u7684\u538b\u5f3a
5\u3001\uff0808\u6c5f\u95e8\uff09\u4e00\u4e2a\u5bc6\u5ea6\u4e3a0.5\u00d7103 kg\uff0fm3\u3001\u8fb9\u957f\u4e3a0.2m\u7684\u5b9e\u5fc3\u6b63\u65b9\u4f53\u653e\u7f6e\u5728\u6c34\u5e73\u5730\u9762\u4e0a\uff0c\u8be5\u7269\u4f53\u7684\u8d28\u91cf\u662f\u3000\u3000\u3000\u3000kg\uff0c\u5b83\u5bf9\u5730\u9762\u7684\u538b\u529b\u5927\u5c0f\u662f\u3000\u3000\u3000\u3000N\uff0c\u5bf9\u5730\u9762\u7684\u538b\u5f3a\u662f\u3000\u3000\u3000\u3000Pa\u3002(\u53d6g=10N\uff0fkg)
\u7b54\u6848\uff1a4kg\uff1b40N\uff1b1000Pa\u3002
6\u3001(08\u6e58\u897f\uff09(7\u5206)\u8d28\u91cf\u4e3a1.6 t\u7684\u5927\u8c61\uff0c\u5e73\u5747\u6bcf\u4e00\u53ea\u811a\u7684\u89e6\u5730\u9762\u79ef\u7ea6\u4e3a400\u339d2\u3002\u4e00\u4e2a\u5973\u58eb\u7684\u8d28\u6700\u4e3a52\u338f\uff0c\u6bcf\u53ea\u9ad8\u8ddf\u978b\u7684\u89e6\u5730\u9762\u79ef\u7ea6\u4e3a13cm2\u3002g\u53d610N/\u338f\uff0c\u5f53\u5927\u8c61\u548c\u8be5\u5973\u58eb\u90fd\u9759\u9759\u5730\u7ad9\u7acb\u5728\u540c\u6837\u677e\u8f6f\u7684\u6ce5\u5730\u4e0a\u65f6\uff0c\u95ee:
\uff081\uff09\u5927\u8c61\u4e0e\u4eba\u7684\u91cd\u529b\u5206\u522b\u662f\u591a\u5c11\uff1f
\uff082\uff09\u8bd5\u901a\u8fc7\u8ba1\u7b97\u6bd4\u8f83\uff0c\u5927\u8c61\u4e0e\u4eba\u8c01\u4f1a\u5728\u6ce5\u5730\u4e0a\u9677\u5f97\u66f4\u6df1\uff1f
7\u3001\uff082010\u54b8\u5b81\uff09\u5982\u56fe5\u6240\u793a\uff0c\u201c\u9a6c\u8e0f\u98de\u71d5\u201d\u662f\u6c49\u4ee3\u827a\u672f\u5bb6\u9ad8\u5ea6\u667a\u6167\u3001\u4e30\u5bcc\u60f3\u8c61\u3001\u6d6a\u6f2b\u4e3b\u4e49\u7cbe\u795e\u548c\u9ad8\u8d85\u827a\u672f\u7684\u7ed3\u6676\u3002\u98de\u5954\u7684\u9a8f\u9a6c\u4e4b\u6240\u4ee5\u80fd\u7528\u4e00\u53ea\u8e44\u7a33\u7a33\u5730\u8e0f\u5728\u98de\u71d5\u4e0a\uff0c\u662f\u56e0\u4e3a\u9a6c\u7684 \u4f4d\u7f6e\u7684\u7ad6\u76f4\u7ebf\u80fd\u901a\u8fc7\u98de\u71d5\u3002\u6709\u4e00\u201c\u9a6c\u8e0f\u98de\u71d5\u201d\u5de5\u827a\u54c1\u91c7\u7528\u5bc6\u5ea6\u4e3a 8.0\u00d7103kg/m3\u7684\u5408\u91d1\u6750\u6599\u5236\u9020\uff0c\u603b\u4f53\u79ef\u4e3a1dm3\uff0c\u98de\u71d5\u4e0e\u6c34\u5e73\u684c\u9762\u7684\u63a5\u89e6\u9762\u79ef\u4e3a20cm2\uff0c\u5219\u8be5\u5de5\u827a\u54c1\u7684\u8d28\u91cf\u4e3a kg\uff0c\u5bf9\u6c34\u5e73\u684c\u9762\u7684\u538b\u5f3a\u4e3a Pa\u3002
\u56fe5 \u56fe6
\u7b54\u6848\uff1a\u91cd\u5fc3 8 4\u00d7104
8\u3001 (09\u798f\u5dde\uff09\u4e3a\u7eaa\u5ff5\u90d1\u548c\u4e03\u4e0b\u897f\u6d0b\u5c06\u534e\u590f\u6587\u660e\u4f20\u626c\u4e8e\u4e16\uff0c\u95fd\u6c5f\u53e3\u5c79\u7acb\u8d77\u56fd\u5185\u6700\u5927\u6700\u9ad8\u7684\u4e00\u5c0a\u77f3\u96d5\u50cf\uff0c\u5982\u56fe6\u6240\u793a\u3002\u77f3\u96d5\u50cf\u548c\u57fa\u5ea7\u7684\u603b\u8d28\u91cf\u4e3a7\u00d7105kg\uff0c\u57fa\u5ea7\u5e95\u90e8\u5448\u6b63\u65b9\u5f62\uff0c\u9762\u79ef\u7ea6\u4e3a50m2\uff0c\u5219\u77f3\u96d5\u50cf\u548c\u57fa\u5ea7\u603b\u91cd\u529b\u662f 7\u00d7106 N\uff0c\u5bf9\u6c34\u5e73\u5730\u9762\u7684\u538b\u5f3a\u662f 1.4\u00d7105 Pa\u3002\uff08g\u53d610N/kg\uff09
\uff08\u4e8c\uff09\u3001\u56fa\u4f53\u538b\u5f3a\u3001\u6db2\u4f53\u538b\u5f3a\u8ba1\u7b97\uff08\u63d0\u9ad8\u9898\uff09
\u7ec3\u4e60\uff1a 1\u3001\u5982\u56fe1\u6240\u793a\uff0c\u4e00\u68af\u5f62\u622a\u9762\u5bb9\u5668\u91cd10N\uff0c\u5bb9\u5668\u5e95\u9762\u79ef\u662f200cm2 \uff0c \u5012\u51654 Kg\u6c34\u7684\u9ad8\u5ea6\u662f30cm\u3002
\uff08g\uff1d10N/Kg \uff09\u6c42\uff1a\uff081\uff09\u5bb9\u5668\u5e95\u6240\u53d7\u6c34\u7684\u538b\u5f3a\uff082\uff09\u5bb9\u5668\u5e95\u6240\u53d7\u6c34\u7684\u538b\u529b\uff083\uff09\u5bb9\u5668\u5bf9\u684c\u9762\u7684\u538b\u5f3a
(1)\u6c34\u5bf9\u5bb9\u5668\u5e95\u7684\u538b\u5f3a\uff1a =1.0\u00d7103Kg/m3\u00d710N/Kg\u00d70.3m=3000Pa
(2): S=200cm2=0.02m2
\u6c34\u5bf9\u5bb9\u5668\u5e95\u7684\u538b\u529b\uff1a =3000Pa\u00d70.02m2=60 N
(3)\u5bb9\u5668\u5bf9\u684c\u9762\u7684\u538b\u529b\uff1a =4 Kg\u00d710N/Kg +10N=50N
\u5bb9\u5668\u5bf9\u684c\u9762\u7684\u538b\u5f3a\uff1a P2=F2/S=50N /0.02m2=2.5\u00d7103 Pa
2\u3001\u4e00\u4e2a\u957f\u65b9\u4f53\u6e38\u6cf3\u6c60\u6c34\u6df12m\uff0c\u6c60\u5e95\u9762\u79ef\u4e3a1200m2\uff08g\u53d610N/kg\uff09\u3002\u6c42\uff1a
\uff081\uff09\u6c60\u5e95\u53d7\u5230\u6c34\u7684\u538b\u5f3a\u3002\uff082\uff09\u6c60\u5e95\u53d7\u5230\u6c34\u7684\u538b\u529b\u3002
\u7b54\u6848\u89e3\uff1a\uff081\uff09P=\u03c1g h =1.0\u00d7103kg/m3\u00d710N/kg\u00d72m=2\u00d7104Pa
\uff082\uff09F=pS =2\u00d7104Pa\u00d71200m2=2.4\u00d7107 N
3\u3001\uff0808\u547c\u4f26\u8d1d\u5c14\uff09\u5982\u56fe\u6240\u793a\uff0c\u6c34\u5e73\u684c\u9762\u7684\u6b63\u4e2d\u592e\u653e\u7740\u4e00\u4e2a\u5706\u5f62\u9c7c\u7f38\uff0c\u91cd\u4e3a30 N\uff0c\u5176\u5e95\u9762\u79ef\u4e3a1200cm2 \u3002\u9c7c\u7f38\u5185\u88c5\u67090\uff0e2 m\u6df1\u7684\u6c34\uff0c\u6c34\u7684\u8d28\u91cf\u662f27kg\u3002(g=10N\uff0fkg)\u8bf7\u8ba1\u7b97\uff1a
(1)\u9c7c\u7f38\u5185\u6240\u88c5\u6c34\u7684\u91cd\u529b\uff1b
(2)\u9c7c\u7f38\u5e95\u90e8\u53d7\u5230\u7684\u6c34\u7684\u538b\u5f3a\uff1b
(3)\u9c7c\u7f38\u5bf9\u684c\u9762\u4ea7\u751f\u7684\u538b\u5f3a\u3002
\u7b54\u6848\uff1a\uff081\uff09
\uff082\uff09
\uff083\uff09
4\u3001\uff0809\u6210\u90fd\uff09\uff086\u5206\uff09\u53d1\u751f\u5728\u5c71\u533a\u7684\u5927\u5730\u9707\uff0c\u5f80\u5f80\u4f1a\u5f62\u6210\u5f88\u591a\u7684\u5830\u585e\u6e56\uff08\u5982\u56fe14\u6240\u793a\uff09\uff0c\u8fd9\u4e9b\u5830\u585e\u6e56\u968f\u65f6\u6709\u6e83\u5824\u7684\u53ef\u80fd\uff0c\u4e25\u91cd\u7684\u5a01\u80c1\u7740\u4e0b\u6e38\u7fa4\u4f17\u7684\u751f\u547d\u5b89\u5168\u3002\u82e5\u67d0\u5830\u585e\u6e56\u6e56\u5824\u5e95\u90e8\u7684\u6c34\u6df1\u5df2\u8fbe\u523055 m\uff0c(\u6c34\u7684\u5bc6\u5ea6\u4e3a1.0\u00d7l03 kg/m3\uff0cg\u53d610 N/kg\u3002)
(1)\u6c42\u4e0a\u8ff0\u60c5\u51b5\u4e0b\u6e56\u5824\u5e95\u90e8\u53d7\u5230\u7684\u6c34\u7684\u538b\u5f3a\u3002
(2)\u5047\u8bbe\u8be5\u6e56\u5824\u5e95\u90e8\u548c\u6e56\u5824\u5404\u90e8\u5206\u80fd\u627f\u53d7\u7684\u6c34\u7684\u6700\u5927\u538b\u5f3a\u90fd\u662f6 \u00d7105 Pa\uff0c\u90a3\u4e48\u6700\u591a\u8fd8\u80fd\u5141\u8bb8\u6c34\u9762\u4e0a\u5347\u591a\u5c11\u7c73\uff1f
5\u3001\uff0808\u5e7f\u5b89\uff09\u5728\u4e00\u4e2a\u91cd2N\uff0c\u5e95\u9762\u79ef\u4e3a0.01 m2\u7684\u5bb9\u5668\u91cc\u88c58N\u7684\u6c34\uff0c\u5bb9\u5668\u4e2d\u6c34\u7684\u6df1\u5ea6\u4e3a0.05m\u3002\uff0c\u628a\u5b83\u653e\u5728\u6c34\u5e73\u684c\u9762\u4e0a\uff0c\u5982\u56fe12\u6240\u793a\uff08g=1ON/kg\uff09\u3002\u6c42\uff1a
(1\uff09\u6c34\u5bf9\u5bb9\u5668\u5e95\u90e8\u7684\u538b\u5f3a\u548c\u538b\u529b\uff1b\uff082\uff09\u5bb9\u5668\u5bf9\u684c\u9762\u7684\u538b\u529b\u548c\u538b\u5f3a\u3002
\u7b54\u6848\uff1a
(1)\u6c34\u5bf9\u5bb9\u5668\u5e95\u7684\u538b\u5f3a\uff1a
=1.0\u00d7103Kg/m3\u00d710N/Kg\u00d70.05m=500Pa
\u6c34\u5bf9\u5bb9\u5668\u5e95\u7684\u538b\u529b\uff1a =500 Pa\u00d70.01m2
(2)\u5bb9\u5668\u5bf9\u684c\u9762\u7684\u538b\u529b\uff1a =8N+2N=10N
\u5bb9\u5668\u5bf9\u684c\u9762\u7684\u538b\u5f3a\uff1a
6\u3001\uff0809\u592a\u539f\uff09\u690d\u6811\u8282\u91cc\uff0e\u5c0f\u60c5\u540c\u5b66\u7528\u56fe15\u6240\u793a\u7684\u6c34\u6876\u63d0\u4e8615L\u6c34\u7ed9\u521a\u683d\u4e0a\u7684\u6811\u82d7\u6d47\u6c34\uff0c\u5df2\u77e5\u6876\u81ea\u8eab\u8d28\u91cf\u4e3a1kg\uff0c\u6876\u4e2d\u6c34\u6df1h\u4e3a30cm\uff0c\u63d0\u6c34\u65f6\uff0c\u624b\u7684\u53d7\u529b\u9762\u79ef\u4e3a 1 \u00d710-3m2\uff0e\uff08\u6c34\u7684\u5bc6\u5ea6\u4e3a1. 0 \u00d7103kg/m3\uff0cg\u53d610N/kg\uff09
\u6c42\uff1a\uff081\uff09\u6c34\u5bf9\u6876\u5e95\u7684\u538b\u5f3a\u662f\u591a\u5927\uff1f
\uff082\uff09\u63d0\u6c34\u65f6\uff0c\u4eba\u624b\u53d7\u5230\u7684\u538b\u5f3a\u662f\u591a\u5927\uff1f
7\u3001 (2010\u53a6\u95e8) 33\uff0e\u4e3a\u8282\u80fd\u51cf\u6392\uff0c\u5efa\u7b51\u4e0a\u666e\u904d\u91c7\u7528\u7a7a\u5fc3\u7816\u66ff\u4ee3\u5b9e\u5fc3\u7816\u3002\u5982\u56fe\u6240\u793a\uff0c\u8d28\u91cf3.6kg\u7684\u67d0\u7a7a\u5fc3\u7816\uff0c\u89c4\u683c\u4e3a20cm\u00d715cm\u00d710cm\uff0c\u7816\u7684\u5b9e\u5fc3\u90e8\u5206\u5360\u603b\u4f53\u79ef\u768460\ufe6a\u3002\uff08g\u53d610N/kg\uff09
\u6c42\uff1a
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\uff082\uff09\u751f\u4ea7\u6bcf\u5757\u7a7a\u5fc3\u7816\u6bd4\u540c\u89c4\u683c\u7684\u5b9e\u5fc3\u7816\u53ef\u8282\u7701\u6750\u6599\u591a\u5c11\u5343\u514b\uff1f
\uff083\uff09\u4e00\u5757\u540c\u89c4\u683c\u7684\u7a7a\u5fc3\u7816\u548c\u5b9e\u5fc3\u7816\uff0c\u4ee5\u76f8\u540c\u65b9\u5f0f\u653e\u5728\u6c34\u5e73\u5730\u9762\u4e0a\uff0c\u5bf9\u5730\u9762\u7684\u538b\u5f3a\u6700\u591a\u76f8\u5dee\u591a\u5c11\u5e15\uff1f
\u538b\u529b\u7b49\u4e8e\u91cd\u529b\uff1aF\uff1dG\uff1dmg=3kg x 10N/kg=30N
\u53d7\u529b\u9762\u79ef\uff1aS\uff1d100cm^2=0.01m^2
\u538b\u5f3a\uff1aP=F/S=30N/0.01m^2\uff1d3000Pa
F=G=mg=(200000kg+13000kg)*10N/kg=2.13*16六次方N
设至少有x个轮子，据题意，得
2.13*10的6六次方除以(1.4乘10的-2次方 * x) 小于等于 1。5*10的6次方Pa
x大于等于102(要用进一法） 一物体为正方体，宽10CM，厚1CM，里住入水满。在一次航海中丢入100M深水中，求方体个各表面的压强. 求压力：有一斜度为30度的光滑斜面高1M，有一 小物块10M没秒的速度从斜面底冲上斜面，问到达中心高度时物体对斜面的 压力。
初二物理压强计算题弹簧测力计下挂一个质量是158g的铁块，若将铁块完全浸没在截面积是200㎡的圆柱形容器的水中，求：<1>铁块所受的浮力<2>弹簧测力计的示数<3>由于铁块的放入，水对容器底部压强的增加值。(ρ铁=7.9×10�0�6kg/m�0�6，g=10N/kg)要过程，谢谢了。上题答案：1)铁块体积V=0.158÷7900=2*10(-5)m�0�6 浮力F=ρ水gV=1000*10*2*10(-5)=0.2N2）读数=拉力N=G-F=0.158*10-0.2=1.38N3)水对铁块的浮力=铁块对水的压力容器增加的压力=铁块对水的压力所以增加的压强=F/S=0.2/200=0.001Pa
绛旓細銕★紝姹傚ス绔欑珛 鏃跺鍦伴潰鐨鍘嬪己锛3 銆佷竴鍧楅暱鏂瑰舰鐨勬鐨川閲忎负 30 鍏嬶紝渚ф斁鍦ㄦ按骞虫闈笂锛屽畠涓庢闈㈢殑鎺ヨЕ闈㈢Н涓 1 脳 10 -3 銕★紝姹傚畠瀵规闈㈢殑鍘嬪己鏄灏戯紵4 銆佷竴鍙钩搴曠幓鐠冩澂骞虫斁鍦ㄦ按骞虫闈笂锛屽唴瑁 150 鍏嬬殑姘达紝鏉瓙涓庢闈㈢殑鎺ヨЕ闈㈢Н鏄 10cm 2 鏃讹紝鐜荤拑鏉妗岄潰鐨勫帇寮烘槸 2.7 脳 10 3 P ...
绛旓細鍒濅簩鐗╃悊鍘嬪己璁＄畻棰寮圭哀娴嬪姏璁涓鎸備竴涓川閲忔槸158g鐨勯搧鍧楋紝鑻ュ皢閾佸潡瀹屽叏娴告病鍦ㄦ埅闈㈢Н鏄200銕＄殑鍦嗘煴褰㈠鍣ㄧ殑姘翠腑锛屾眰锛<1>閾佸潡鎵鍙楃殑娴姏<2>寮圭哀娴嬪姏璁＄殑绀烘暟<3>鐢变簬閾佸潡鐨勬斁鍏ワ紝姘村瀹瑰櫒搴曢儴鍘嬪己鐨勫鍔犲笺(蟻閾=7.9脳10�0�6kg/m�0�6锛実=10N/kg)瑕佽繃...
绛旓細锛1锛夌煶鏂欏鍩哄骇鐨鍘嬪己 鐢盤=F/S F1=G1=mg=2.0x10^5N P1=F1/S1=1.67x10^5pa 锛2锛夊熀搴у鍦伴潰鐨勫帇寮 F2=G1+G2 G2=蟻gv2 v2=2x1x0.4=0.8m^3 G2=16000N P2=f2/s2=2.16x10^5N/2=1.08x10^5pa
绛旓細锛1锛塒=蟻gh=1000kg/m^3x10N/kgx300m=3x10^6pa (2)s=100cm^2=100x10^-4m^2=10^-2m^2 (3)F=PS=3x10^6pax10^-2m^2=3x10^4N
绛旓細0.03t= 30 kg,30g= 0.03 kg,30mg= 3脳10-5 kg浜屻(瑙ｉ鎶宸)鏈夊叧鍘嬪己鐨璁＄畻娉ㄦ剰:1:姹傚鍣ㄥ妗岄潰鐨勫帇寮 灞炰簬鍥轰綋绫诲瀷,鍙厛姹傚嚭瀹瑰櫒瀵规闈㈢殑鍘嬪姏F=G,(瀹冩槸鐢卞鍣ㄩ噸鍜屾按閲嶅叡鍚屽紩璧风殑) ,鍐嶅埄鐢≒=F/S,姹傚鍣ㄥ妗岄潰鐨勫帇寮2:姹傛按瀵瑰鍣ㄥ簳鐨勫帇鍔,搴斿厛姹傚嚭姘村瀹瑰櫒搴曠殑鍘嬪己P=蟻gh,鍐嶅埄鐢‵=PS姹傛按瀵...
绛旓細1姹傚帇寮锛氫竴鐗╀綋涓烘鏂逛綋锛屽10CM锛屽帤1CM锛岄噷浣忓叆姘存弧銆傚湪涓娆¤埅娴蜂腑涓㈠叆100M娣辨按涓紝姹傛柟浣撲釜鍚勮〃闈㈢殑鍘嬪己.2姹傚帇鍔涳細鏈変竴鏂滃害涓30搴︾殑鍏夋粦鏂滈潰楂1M锛屾湁涓 灏忕墿鍧10M娌＄鐨勯熷害浠庢枩闈㈠簳鍐蹭笂鏂滈潰锛岄棶鍒拌揪涓績楂樺害鏃剁墿浣撳鏂滈潰鐨 鍘嬪姏銆3姹傛憾瑙ｅ害锛氭湁 涓 鏉恫浣500G锛屾湭鐭ュ叾瀹瑰珘濡掞紝鐜版湁100G鐨...
绛旓細绗竴闂厛绠 鍘嬪己 P1= 瀵嗗害 g*h=800 9.8 0.1 =784 Pa鍐嶇畻鍘嬪姏 F=P1*S=784 0..04 = 31.36 N 绗簩闂厛绠楀帇鍔 鍘嬪姏= 閲嶅姏 N= 瀵嗗害*V*g=800 0..0005 9.8=3.92 N鍐绠楀帇寮 P2=N/S=3.92/0.2=19.6 Pa
绛旓細1)閾佸潡浣撶НV=0.158梅7900=2*10(-5)m³娴姏F=蟻姘磄V=1000*10*2*10(-5)=0.2N 2锛夎鏁=鎷夊姏N=G-F=0.158*10-0.2=1.38N 3)姘村閾佸潡鐨勬诞鍔=閾佸潡瀵规按鐨勫帇鍔 瀹瑰櫒澧炲姞鐨勫帇鍔=閾佸潡瀵规按鐨勫帇鍔 鎵浠ュ鍔犵殑鍘嬪己=F/S=0.2/200=0.001Pa ...
绛旓細2=1.2156*10^5 N mg=F m=F/g=1.2156*10^4N 2)F=PS=(1.013*10^5)*500=5.065*10^7 N 鍥犳埧椤剁殑涓琛ㄩ潰鍙楀埌浜嗕笌涔嬪ぇ灏忥紝浼圭浉鍚屾柟鍚戝悜涓婄殑鍘嬪姏锛屾墍浠ユ埧灞嬩笉浼氳鍘嬪 3)鍚硅捣姘旂悆鐨勬渶灏鍘嬪己P'=澶ф皵鍘嬪己+姘翠骇鐢熺殑鍘嬪己 P'=P+pgh=1.013*10^5 +(1000)*10*5=1.513*10^5pa ...
绛旓細1銆佸皢涓寮犳壃瀛愭櫄鎶ュ钩鎽婂湪妗岄潰涓婏紝瀵规闈㈢殑鍘嬪己绾︿负0.5Pa锛屽叾琛ㄧず鐨鐗╃悊鍚箟鏄 銆傝繖涓帇寮哄肩浉褰撲簬 鐧惧笗銆2銆佸浗鍐呮渶澶ф渶楂樼殑涓灏婇儜鍜岀煶闆曞儚锛岀煶闆曞儚鍜屽熀搴х殑鎬昏川閲忎负7脳105kg锛屽熀搴у簳閮ㄥ憟姝ｆ柟褰紝闈㈢Н绾︿负50m2锛屽垯鐭抽洉鍍忓拰鍩哄骇鎬婚噸鍔涙槸7脳106 N锛屽姘村钩鍦伴潰鐨勫帇寮烘槸1.4脳105 Pa锛...
