java查询String中所有的元素并输出重复次数 找出string数组里的重复元素并输出
java\u600e\u4e48\u67e5\u8be2\u4e00\u4e2a\u5b57\u7b26\u4e32\u4e2d\u91cd\u590d\u7684\u5b57\u7b26\uff0c\u5e76\u4e14\u8ba1\u7b97\u4ed6\u51fa\u73b0\u7684\u6b21\u6570\u3002public class FindSubStringClass {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
String str = "abcdabcdabcdabcd";
String subStr = "abcd";
int cursor = 0, subStrLen = subStr.length(), totalStrLen = str.length();
int count = 0; // \u8868\u793a\u91cd\u590d\u5b57\u7b26\u7684\u4e2a\u6570
while ((cursor + subStrLen) <= totalStrLen) {
String tempStr = str.substring(cursor, cursor + subStrLen); // \u83b7\u53d6\u5b57\u7b26\u4e32\u4e2d\u7684\u5b50\u5b57\u7b26\u4e32
if (tempStr.equals(subStr)) {
count++;
cursor += subStrLen;
} else {
cursor++;
}
}
System.out.println(subStr + "\u51fa\u73b0\u5728" + str + "\u4e2d\u7684\u6b21\u6570\u4e3a" + count + "\u6b21");
}
}
int i,counter[100];
for(i=0;i<=100;i++) counter[i]=0;
for(i=0;i<=strlen(string);i++) counter[string[i]-32]++;
for(i=0;i1) printf("%c ",i+32);
实现思路：就是将字符串变为一个一个的char类型，之后进行循环计数，同样的加1，之后输出计算结果。
import java.util.ArrayList;
public class Test {
public static void main(String[] args) {
String s = "abcdaebijkd";
ArrayList list = new ArrayList();
for(int i=0; i<s.length(); i++){
char c = s.charAt(i);
if(s.indexOf(c,i+1)>-1){
Character ch = new Character(c);
if(!list.contains(ch))
list.add(ch);
}
}
for(int i=0; i<list.size(); i++)
System.out.print(list.get(i)+",");
}
}
String input ="a,ab,abc,a,b,ab,abc,abced";
TreeMap<String,Integer> stringMap = new TreeMap<String,Integer>();
String[] array = input.split(",");
for (int i = 0; i < array.length; i++) {
if(array.equals("") == false){
if(stringMap.containsKey(array[i])){
stringMap.put(array[i], stringMap.get(array[i])+1);
}else{
stringMap.put(array[i], 1);
}
}
}
Iterator<String> it = stringMap.keySet().iterator();
while(it.hasNext()){
String c = it.next();
int count = stringMap.get(c);
System.out.println("字符："+c+"，出现次数："+count+"次");
}
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