sql语句两表查询，但是有部分重复结果，想让相同部分只显示一条，怎么写？ 多表查询结果出现重复记录,根据条件只取其中的一条记录的sql...
SQL\u67e5\u8be2\uff0c\u5982\u4f55\u53bb\u9664\u91cd\u590d\u7684\u8bb0\u5f55\uff1f\u9996\u5148\uff0c\u5148\u8bf4\u660e\u4e00\u4e2a\u95ee\u9898\u3002\u8fd9\u6837\u7684\u7ed3\u679c\u51fa\u73b0\uff0c\u8bf4\u660e\u7cfb\u7edf\u8bbe\u8ba1\u662f\u6709\u95ee\u9898\u7684\u3002\u5176\u6b21\u5220\u9664\u91cd\u590d\u6570\u636e\uff0c\u4f60\u8981\u63d0\u4f9b\u4f60\u662f\u4ec0\u4e48\u6570\u636e\u5e93\u3002\u4e0d\u540c\u6570\u636e\u5e93\u4f1a\u6709\u4e0d\u540c\u7684\u89e3\u51b3\u65b9\u6848\u3002\u5173\u952e\u5b57Distinct \u53bb\u9664\u91cd\u590d\uff0c\u5982\u4e0b\u5217SQL\uff0c\u53bb\u9664Test\u76f8\u540c\u7684\u8bb0\u5f55\uff1b1. select distinct Test from Table2. \u5982\u679c\u662f\u8981\u5220\u9664\u8868\u4e2d\u5b58\u5728\u7684\u91cd\u590d\u8bb0\u5f55\uff0c\u90a3\u5c31\u903b\u8f91\u5904\u7406\uff0c\u5982\u4e0b\uff1a3. select Test from Table group by Test having count\uff08test)>14. \u5148\u67e5\u8be2\u5b58\u5728\u91cd\u590d\u7684\u6570\u636e\uff0c\u540e\u9762\u6839\u636e\u6761\u4ef6\u5220\u9664\u8fd8\u6709\u4e00\u4e2a\u66f4\u7b80\u5355\u7684\u65b9\u6cd5\u53ef\u4ee5\u5c1d\u8bd5\u4e00\u4e0b\uff1aselect aid, count(distinct uid) from \u8868\u540d group by aid \u8fd9\u662fsqlserver \u7684\u5199\u6cd5\u3002
\u5982\u56fe\u4e00\u5728\u6570\u636e\u8868\u4e2d\u6709\u4e24\u4e2a\u8180\u80f1\u51b2\u6d17\u91cd\u590d\u7684\u8bb0\u5f55\u3002
2
\u53ef\u4ee5\u901a\u8fc7sql\u8bed\u53e5\u201cselect *from \u8868\u540d where \u7f16\u7801 in(select \u7f16\u7801 from \u8868\u540d group by \u7f16\u7801 having count(1) >= 2)\u201d\u6765\u67e5\u8be2\u51fa\u53d8\u79cd\u6240\u6709\u91cd\u590d\u7684\u8bb0\u5f55\u5982\u56fe\u4e8c
3
\u901a\u8fc7sql\u8bed\u53e5"
delete from \u8868\u540d where
\u7f16\u7801 in(select \u7f16\u7801 from \u8868\u540d group by \u7f16\u7801 having count(1) >= 2)
and \u7f16\u7801 not in (select max(\u7f16\u7801)from \u8868\u540d group by \u7f16\u7801 having count(1) >=2)
"\u6765\u5220\u9664\u91cd\u590d\u7684\u8bb0\u5f55\u53ea\u4fdd\u7559\u7f16\u7801\u6700\u5927\u7684\u8bb0\u5f55
select top 1 * form \u88682 where id=(select id form \u88681 order by id esc) order by time desc
top 1 \u9009\u51fa\u7b2c\u4e00\u6761\u8bb0\u5f55
order by time desc \u6309\u65f6\u95f4\u5012\u5e8f\u6392\u5217,\u8fd9\u6837\u7b2c\u4e00\u6761\u8bb0\u5f55\u5c31\u662f\u65e5\u671f\u6700\u665a\u7684\u8bb0\u5f55\u4e86
id=(select id form \u88681 order by id esc)\u8868\u4e00\u4e2d\u7684id\u4e0e\u8868\u4e8c\u4e2d\u76f8\u7b49\u7684id
select DISTINCT a,b,表1.c,d,e from 表1,表2 where 表1.C=表2.C
SELECT tableA.*, tableB.* FROM 表1 tableA LEFT JOIN 表2.tableB
ON tableA.c=tableB.c;
直接用where会得到一个笛卡尔乘积 匹配所有相等的情况 相当于 inner join
这里改成 LEFT JOIN 应该好点
用distinct 来去重呀
leeyige 的做法正确!可行....已测试,楼主可以使用
group by a, b ,c ,d, e
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