请教一个关于matlab进行自定义曲线参数拟合的问题

\u5982\u4f55\u7528MATLAB\u62df\u5408\u66f2\u7ebf\u6765\u6c42\u53c2\u6570\uff1f

\u4ee4x\uff1d(cos(k)./sin(k))./c\uff0c\u8fd9\u4e2a\u5c31\u662fxdata\u5411\u91cf
y=252/(2.016129032*10^9)*a*x^b

\u53d6log\u5f97\u5230
log(y)=b*log(x)+log(252/(2.016129032*10^9)*a)
\u6240\u4ee5log(y)\u4e0elog(x)\u662f\u7ebf\u6027\u5173\u7cfb\uff0c\u7528p=polyfit(log(xdata),log(y),1)\u6c42\u51fa
b=p(1);
a=exp(p(2))/252*(2.016129032*10^9); % \u56e0\u4e3alog(252/(2.016129032*10^9)*a)=p(2)

\u6240\u4ee5\u6700\u7ec8\u7a0b\u5e8f\u662f\u5982\u4e0b\uff1a

clear all
c=[2.7,2.8,2.9,3,3.1,3.2,3.45,3.7,3.95,4.2,4.45,4.7,4.95,5.2];
k=[0,47,93,140,186,279,372,465,558,651];
y=[18.98,27.35,34.86,38.52,38.44,37.73,38.43,43.87,42.77,46.22];
xdata=(cos(k)./sin(k))./c;
p=polyfit(log(xdata),log(y),1);
b=p(1);
a=exp(p(2))/252*(2.016129032*10^9);

\u65e2\u7136\u4f60\u5df2\u7ecf\u77e5\u9053\u5f85\u62df\u5408\u7684\u51fd\u6570\u8868\u73b0\u5f62\u5f0f\u4e86\uff0c\u7528\u5185\u8054\u51fd\u6570\u5427

可以用cftool工具箱拟合。但拟合精度偏低,R²=0.8444。

General model:
     f(x) = a*erfc(x/(2*sqrt(b*(28/315360000)^c*315360000)))
       where x is normalized by mean 27.5 and std 15.14
Coefficients (with 95% confidence bounds):
       a =        3.24  (3.002, 3.477)
       b =       10.54  (-4.122e+008, 4.122e+008)
       c =       1.243  (-2.409e+006, 2.409e+006)

Goodness of fit:
  SSE: 0.7045
  R-square: 0.879
  Adjusted R-square: 0.8444
  RMSE: 0.3172



这个拟合是很不好啊!不知道怎么得出的?
你可以试试用 多项式拟合polyfit(x,y,n)

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