绝缘水平面上静止着两个质量均为m、电荷量均为+Q的物体A和B(A、B均可视为质点),它们间的距离为r

\u7edd\u7f18\u7684\u6c34\u5e73\u9762\u4e0a\u9759\u6b62\u7740\u4e24\u4e2a\u8d28\u91cf\u5747\u4e3aM\uff0c\u7535\u8377\u91cf\u5747\u4e3a+Q\u7684\u7269\u4f53A\u548cB\uff08A\uff0cB\u5747\u53ef\u89c6\u4e3a\u8d28\u70b9\uff09\u5b83\u4eec\u95f4\u7684\u8ddd\u79bb\u4e3aR\uff0c

\u89e3\uff1a\u4f9d\u9898\u610f\uff0c3kQ^2/R^2<\u03bcmg<4kQ^2/R^2,\u8fd9\u6837\u5f00\u59cb\u8fd0\u52a8\u65f6\u7684\u77ac\u95f4\uff0c\u6bcf\u4e2a\u7269\u4f53\u53d7\u5230\u7684\u5408\u529b\u4e3a4kQ^2/R^2-\u03bcmg\uff0c\u968f\u540e\uff0c\u7531\u4e8e\u4e24\u4e2a\u7269\u4f53\u4e4b\u95f4\u8ddd\u79bb\u7684\u589e\u52a0\u7535\u8377\u65a5\u529b\u9010\u6e10\u51cf\u5c0f\uff0c\u8fd9\u662f\u4e00\u4e2a\u5408\u529b\u6216\u8005\u52a0\u901f\u5ea6\u9010\u6e10\u51cf\u5c0f\u7684\u52a0\u901f\u8fd0\u52a8\uff0c\u5f53\u5408\u529b\u51cf\u5c0f\u5230\u5927\u5c0f\u7b49\u4e8e\u03bcmg\u65f6\u52a0\u901f\u5ea6\u4e3a\u96f6\uff0c\u8bbe\u6b64\u65f6\u4e24\u7269\u4f53\u7684\u8ddd\u79bb\u4e3ar,\u5219\u6709
4kQ^2/r^2-\u03bcmg=0
r=2Q\u221a(k/\u03bcmg)
A\uff0cB\u8fd0\u52a8\u4e86\u7684\u8ddd\u79bb\uff08\u76f8\u7b49\u7684\uff09\u4e3a
(r-R)/2
=[Q\u221a(k/\u03bcmg)-R/2]

\u89e3\uff1a\u4f9d\u9898\u610f\uff0c3kQ\uff3e2\uff06\uff0347\uff1bR\uff3e2\uff06lt\uff1b\u03bcmg\uff06lt\uff1b4kQ\uff3e2\uff06\uff0347\uff1bR\uff3e2dhlp\u8fd9\u6837\u5f00\u59cb\u8fd0\u52a8\u65f6\u7684\u77ac\u95f4\uff0c\u6bcf\u4e2a\u7269\u4f53\u53d7\u5230\u7684\u5408\u529b\u4e3a4kQ\uff3e2\uff06\uff0347\uff1bR\uff3e2\uff0d\u03bcmg9517\u968f\u540e\u7531\u4e8e\u4e24\u4e2a\u7269\u4f53\u4e4b\u95f4\u8ddd\u79bb\u7684\u589e\u52a0\u7535\u8377\u65a5\u529b\u9010\u6e10\u51cf\u5c0f\u8fd9\u662f\u4e00\u4e2a\u5408\u529b\u6216\u8005\u52a0\u901f\u5ea6\u9010\u6e10\u51cf\u5c0f\u7684\u52a0\u901f\u8fd0\u52a89\u5f53\u5408\u529b\u51cf\u5c0f\u5230\u5927\u5c0f\u7b49\u4e8e\u03bcmg\u65f6\u52a0\u901f\u5ea6\u4e3a\u96f6jnrv\u8bbe\u6b64\u65f6\u4e24\u7269\u4f53\u7684\u8ddd\u79bb\u4e3ar\uff0c\u5219\u67094kQ\uff3e2\uff06\uff0347\uff1br\uff3e2\uff0d\u03bcmg\uff1d0r\uff1d2Q\u221a\uff08k\uff06\uff0347\uff1b\u03bcmg\uff09A\uff0cB\u8fd0\u52a8\u4e86\u7684\u8ddd\u79bb\uff08\u76f8\u7b49\u7684\uff09\u4e3a\uff08r\uff0dR\uff09\uff06\uff0347\uff1b2\uff1d\uff3bQ\u221a\uff08k\uff06\uff0347\uff1b\u03bcmg\uff09\uff0dR\uff06\uff0347\uff1b2\uff3d

解:依题意,3kQ^2/R^2<μmg<4kQ^2/R^2,这样开始运动时的瞬间,每个物体受到的合力为4kQ^2/R^2-μmg,随后,由于两个物体之间距离的增加电荷斥力逐渐减小,这是一个合力或者加速度逐渐减小的加速运动,当合力减小到大小等于μmg时加速度为零,设此时两物体的距离为r,则有 4kQ^2/r^2-μmg=0 r=2Q√(k/μmg) A,B运动了的距离(相等的)为 (r-R)/2 =[Q√(k/μmg)-R/2]

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