C语言定义二维数组输入每位学生的成绩定义二维数组求每名学生成绩的平均值并将其按降序排列 采用二维数组输入多个学生五门课的成绩,分别求出每个学生的平均...

C\u8bed\u8a00\u4e2d\u7528\u4e8c\u7ef4\u6570\u7ec4\u7edf\u8ba1\u5b66\u751f\u6210\u7ee9\uff0c\u8fd8\u8981\u6c42\u6bcf\u79d1\u5e73\u5747\u6210\u7ee9\uff0c\u6bcf\u4e2a\u4eba\u7684\u5e73\u5747\u6210\u7ee9\u3002\u8fd8\u60f3\u8f93\u5165\u5b66\u53f7\u3002\u6c42\u4fee\u6539\uff0c\u8865\u5145

#include
//\u4e0d\u77e5\u9053\u4f60\u6709\u6ca1\u6709\u5b66\u52a8\u6001\u6570\u7ec4\uff0c\u6240\u4ee5\u5199\u6210\u5b8f\u5b9a\u4e49\u6539\u8d77\u6765\u65b9\u4fbf
#define N 100 //\u4eba\u6570
#define SUB 3 //\u79d1\u76ee
int main()
{
int stu;
int i;
int j;
float sum = 0.0;
char num[N][10] ;
float s_sum[SUB] = {0};
float score[N][SUB] = {{0}};
printf("\u8f93\u5165\u5b66\u751f\u4e2a\u6570:");
scanf("%d",&stu);
printf("\u8f93\u5165\u5b66\u751f\u5b66\u53f7:\n");
for(i = 0;i < stu;i++)
{
scanf("%s",&num[i]);
}
printf("\u8f93\u5165\u5206\u6570:\n");
for(i = 0; i < stu; i++)
{
printf("\u5b66\u53f7%s\u5b66\u751f\u7684\u5404\u79d1\u5206\u6570\uff1a\n",num[i]);
for(j = 0; j<SUB; j++) //\u5b58\u5404\u79d1\u5206\u6570
{
scanf("%f",&score[i][j]);
}
}
for(i = 0; i < stu; i++)
{
for(j = 0; j < SUB; j++)
{
sum +=score[i][j];
}
printf("\u5b66\u53f7%s\u5b66\u751f\u7684\u5e73\u5747\u5206\uff1a%f\n",num[i],sum/(float)SUB);
sum = 0;
}
for(j = 0 ;j < SUB; j++)
{
for(i = 0;i < stu; i++)
{
s_sum[j]+=score[i][j];
}
printf("\u7b2c%d\u5b66\u79d1\u7684\u5b66\u751f\u5e73\u5747\u5206\uff1a%f\n",j,s_sum[j]/stu);
}
return 0;
}
\u6709\u95ee\u9898hi\u6211\uff0c\u6211\u52a0\u4f60\u597d\u53cb\u4e86\uff0c\u5171\u540c\u5207\u78cb\u554a\u3002

#include
#define max 100
float student[max][5];
float sum[max];
float kemu[max];
int main(){
int n;//\u5b66\u751f\u4eba\u6570
int i,j;

scanf("%d",&n);

for (i=0;i<n;i++){
sum[i]=0;
for(j=0;j<5;j++){
scanf("%f",&student[i][j]);
sum[i]=sum[i]+student[i][j];//\u8ba1\u7b97\u6bcf\u4e2a\u540c\u5b66\u7684\u5e73\u5747\u6210\u7ee9
}
sum[i]=sum[i]/5;
}
//\u8ba1\u7b97\u6bcf\u95e8\u8bfe\u7684\u5e73\u5747\u6210\u7ee9
for(i=0;i<5;i++){
kemu[i]=0;
for (j=0;j<n;j++)
kemu[i]=kemu[i]+student[j][i];
kemu[i]=kemu[i]/n;
}
printf("\u6bcf\u4e2a\u540c\u5b66\u7684\u5e73\u5747\u6210\u7ee9\u4e3a\uff1a");
for (i=0;i<n;i++)
printf(" % lf",sum[i]);
printf("\n\u5404\u79d1\u7684\u5e73\u5747\u6210\u7ee9\u4e3a\uff1a");
for (i=0;i<5;i++)
printf("% lf",kemu[i]);
printf("\n");
return 0;
}



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