C++用递归求倒置字符串,并验证回文,要求忽略大小写和特殊符号!!! c++用递归判断回文,求大神看看怎么不对

C++\u600e\u4e48\u7528\u9012\u5f52\u5224\u65ad\u56de\u6587\u5b57\u7b26\u4e32\u5e76\u4e14\u53ef\u4ee5\u5ffd\u7565\u7a7a\u683c\u548c\u6807\u70b9\u7b26\u53f7\uff0c\u6700\u597d\u662f\u4e00\u4e2a\u5b8c\u6574\u7684\u7a0b\u5e8f\uff0c\u4ece\u63d0\u793a\u8f93\u5165\u53e5\u5b50\u8d77

#include
using namespace std;
char s[100];
int recurs(int i,int j)
{
if(s[i]!=s[j])return 0;
else if(i>j-2)return 1;
else return return(i+1,j-1);
}
void main()
{
int i;
cout<<"\u8f93\u5165\u4e00\u4e2a\u5b57\u7b26\u4e32:";
cin>>s;
for(i=0;s[i];i++);
if(recurs(0,i-1))
cout<<"\u662f\u56de\u6587\u4e32"<<endl;
else
cout<<"\u4e0d\u662f\u56de\u6587\u4e32"<<endl;
}

\u4f60\u6839\u672c\u6ca1\u6709\u5224\u65ad\u51fd\u6570\u8fd4\u56de\u503c\u554a\uff01if(true) \u8fd9\u6c38\u8fdc\u662f\u771f\u554a

void reverse(string &src, int a, int b)
{
if(a >= b)
return;
char t = src[a];
for(int k = a; k < b; k++)
src[k] = src[k+1];
src[b] = t;
reverse(src, a, b - 1);
}

string str("hello world");
reverse(str, 0, str.size() - 1);
cout<<str<<endl;

递归实现字符串逆转,剩下的你自己解决

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