急求概率论题解答！x服从泊松分布，p(x=0)=0.4,求p(x>2)！要详细过程！在线等！ X服从参数为1的泊松分布，Y服从参数为2的泊松分布，求P{m...
\u8bbe\u79bb\u6563\u578b\u968f\u673a\u53d8\u91cfX\u670d\u4ece\u53c2\u6570\u4e3a\u03bb(\u03bb\uff1e0)\u7684\u6cca\u677e\u5206\u5e03\uff0c\u4e14\u5df2\u77e5\u6982\u7387P{X=0)=P{X=2}\uff0c\u5219\u53c2\u6570\u7531 P{X=0)=P{X=2} \u77e5
(\u03bb^0 / 0! )*e^(-\u03bb) = (\u03bb^2/ 2! )*e^(-\u03bb) ,
\u5373 1*e^(-\u03bb)= (\u03bb^2/ 2! )*e^(-\u03bb)\uff0c\u6240\u4ee5(\u03bb^2/ 2!=1 \uff0c\u89e3\u5f97\uff0c \u03bb = \u6839\u53f72
X\u548cY\u662f\u72ec\u7acb\u7684\u5427\u3002
\u56e0\u4e3a\u6cca\u677e\u5206\u90e8\u7684\u53d8\u91cf\u53ea\u80fd\u662fX=0,1,2.........\uff0cY=0,1,2.........
\u6240\u4ee5P(X>=0)=P(Y>=0)=1
P{min(X,Y)=0}
=P{X=0,Y>=0}+P(Y=0,X>=0}=P(X=0)P(Y>=0)+P(Y=0)P(X>=0)-P(x=0)P(y=0)
=P(X=0)*1+P(Y=0)*1-P(x=0)P(y=0)
=(1^0)e^(-1)/0!+(2^0)e^(-2)/0!-[(1^0)e^(-1)/0!]*[(2^0)e^(-2)/0!]
=(1/e)+(1/e^2)-(1/e)*(1/e^2)
=(1/e)+(1/e^2)-(1/e^3)
\u6ee1\u610f\u8bf7\u91c7\u7eb3\uff0c\u8c22\u8c22\u652f\u6301\u3002
答案的确是错了。你是对的！
p(x=0)=0.4=e^(-λ)
λ=-ln0.4
p(x=1)=-0.4ln0.4
p(x=2)=0.4ln²0.4
p(x>2)=1-P(x=0)-P(x=1)-P(x=2)=1-0.4(ln²0.4-ln0.4+1)=0.6-0.4(ln²0.4-ln0.4)
p(x=0)=e^(-λ)=0.4==>λ=-ln0.4 p(x=1)=λe^(-λ)=0.4λ
所以p(x>2)=1-p(x=0)-p(x=1)=0.6+0.4ln0.4,
绛旓細X鑻鏈嶄粠娉婃澗鍒嗗竷,鏈塮X(x)=e^(-位) (位^x)/x!P(X>=1)=1-e^(-2)1-P(X=0)=1-e^(-2)1-fX(0)=1-e^(-2)1-(位)^0e^(-位)/0!-=1-e^(-2)位=2Var(X)=2 E(X)=2E(X^2)=Var(X)+E^2(X)=2+2^2=6E(X^2)-Var(X)=E^2(X)璁綱ar(X)=E(X)=...
绛旓細绛旀鐨勭‘鏄敊浜嗐備綘鏄鐨勶紒
绛旓細绠鍗曡绠椾竴涓嬪嵆鍙紝绛旀鏄8
绛旓細X鏈嶄粠娉婃澗鍒嗗竷P(3),鍒橢(X)=3锛孻=3X-2,鍒橢(Y)=E(3X-2)=3E(x)-2=7 N(0,1)锛孨(0,1)
绛旓細Poisson鍒嗗竷锛屾槸涓绉嶇粺璁′笌姒傜巼瀛閲屽父瑙佸埌鐨勭鏁ｆ鐜囧垎甯冿紝鐢辨硶鍥芥暟瀛﹀瑗胯帿鎭┞峰痉灏悸娉婃澗锛圫im茅on-Denis Poisson锛夊湪1838骞存椂鍙戣〃銆侾(X=k) = (位^k/k!)e^(-位) ; k=0,1,2,...
绛旓細1.X鏈嶄粠鍙傛暟涓篴鐨娉婃澗鍒嗗竷锛屾晠姒傜巼瀵嗗害涓篺(x)=ae^(-ax) x>0,寰楀埌鍒嗗竷鍑芥暟涓篎(x)=1-e^(-ax) x>0,鍙圶={X1,X2,鈥,Xn}锛屾晠鑱斿悎鍒嗗竷鍒椾负F(Xi)=1-e^(-aXi) Xi>0 i=1,2,鈥,n 鍦╔i涓哄叾浠栫殑鏃跺橣(Xi)=0銆2.x鏈嶄粠[0,1]鐨勫潎鍖鍒嗗竷,鍒檉(x)=1 0<x<1,f(x)=0 鍏朵粬,...
绛旓細瑙ｇ瓟杩囩▼锛氳涓x锛屽垪涓何伙紝浜ゅ弶寰楀埌鐨勮〃鏍煎唴鐨勬暟瀛楀氨鏄緱鍒扮殑绛旀銆傚彟澶栧苟鏈煡鍒版湁位=5鐨勮〃锛屼竴鑸儏鍐典笅锛屛讳笉浼氬ぇ浜1銆傝繖涓〃鍦姒傜巼璁涓庢暟鐞嗙粺璁＄殑闄勮〃閲屻娉婃澗鍒嗗竷锛Poisson鍒嗗竷锛堟硶璇細loi de Poisson锛岃嫳璇細Poisson distribution锛岃瘧鍚嶆湁娉婃澗鍒嗗竷銆佹櫘闃挎澗鍒嗗竷銆佸崪鐡︽澗鍒嗗竷銆佸竷鐡︽澗鍒嗗竷銆佸竷闃挎澗鍒嗗竷銆...
绛旓細娉婃澗鍒嗗竷鏄噸瑕佺殑绂绘暎鍒嗗竷涔嬩竴锛屽畠澶氬嚭鐜板湪褰X琛ㄧず鍦ㄤ竴瀹氱殑鏃堕棿鎴栫┖闂村唴鍑虹幇鐨勪簨浠朵釜鏁拌繖绉嶅満鍚堛傚湪涓瀹氭椂闂村唴鏌愪氦閫氳矾鍙ｆ墍鍙戠敓鐨勪簨鏁呬釜鏁帮紝鏄竴涓吀鍨嬬殑渚嬪瓙銆傛硦鏉惧垎甯冨湪绠＄悊绉戝銆佽繍绛瑰浠ュ強鑷劧绉戝鐨勬煇浜涢棶棰樹腑閮藉崰鏈夐噸瑕佺殑鍦颁綅銆傦紙鍦ㄦ棭鏈熷鐣岃涓轰汉绫昏涓烘槸鏈嶄粠娉婃澗鍒嗗竷锛2005骞村湪nature涓婂彂琛ㄧ殑鏂囩珷鎻ず...
绛旓細寮曠敤 鍥炵瓟鑰咃細 aquex - 缁忕悊 浜旂骇 4-18 23:12 P(X=K)=lamda^k/k!*e^(-lamda)閭ｄ箞e^(-lamda)鏄畾鍊 P(X=K+1)/P(X=K)=lamda/K+1 鍙鐪嬭繖涓瘮涓嶆瘮1澶у挴 鍙互鐭ラ亾鏈澶х殑P(X=K)鍦↘=[lamda](鍙栨暣)鐨勬椂鍊欏彇鍒板憖 鈥斺斺斿叧浜嶺~Po锛埼伙級P(X=K+1)/P(X=K)=位/(K+1)閭ｄ箞...
绛旓細缁忔祹鏁板鍥㈤槦涓轰綘瑙ｇ瓟锛屾湁涓嶆竻妤氳杩介棶銆傛弧鎰忕殑璇濓紝璇峰強鏃惰瘎浠枫傝阿璋!
