（2010?南通模拟）如左图所示，一带电粒子以水平速度v0 （v0＜E/B）先后进入方向互相垂直的匀强电场和匀
\u4e00\u4e2a\u7535\u5b50\u8d28\u91cf\u4e3am,\u7535\u8377\u91cf\u4e3aE,\u4ee5\u521d\u901f\u5ea6V0\u6cbf\u7740\u5300\u5f3a\u7535\u573a\u7684\u7535\u573a\u7ebf\u65b9\u5411\u98de\u5165\u5300\u5f3a\u7535\u573a(1)\u7535\u5b50\u5728\u5300\u5f3a\u7535\u573a\u4e2d\u8fd0\u52a8\uff0c\u7531\u4e8e\u4e0d\u53d7\u91cd\u529b\uff0c\u5219\u8be5\u7535\u5b50\u53ea\u53d7\u7535\u573a\u529b\u7684\u4f5c\u7528\u3002\u7531\u725b\u987f\u7b2c\u4e8c\u5b9a\u5f8b\u53caF=Eq\u5f97\u7535\u5b50\u5728\u7535\u573a\u4e2d\u8fd0\u52a8\u7684\u52a0\u901f\u5ea6a=Eq/m
(2)\u7535\u5b50\u5728\u5300\u5f3a\u78c1\u573a\u4e2d\u53d7\u5230\u4e0e\u7535\u573a\u7ebf\u65b9\u5411\u76f8\u53cd\u7684\u7535\u573a\u529b\uff0c\u56e0\u6b64\uff0c\u7535\u5b50\u5728\u6cbf\u7740\u5300\u5f3a\u7535\u573a\u7684\u7535\u573a\u7ebf\u65b9\u5411\u8fdb\u5165\u65f6\uff0c\u5b9e\u9645\u662f\u505a\u5300\u51cf\u901f\u76f4\u7ebf\u8fd0\u52a8\uff0c\u6545\u7531V=V0-at\u5f97\uff0c\u5f53\u7535\u5b50\u7684\u901f\u5ea6\u4e3a0\u65f6\u7684\u8fd0\u52a8\u65f6\u95f4\u4e3at=V0\u9664\u4ee5Eq/m\u5373t=V0m/(Eq),\u7531X=V0t-1/2at^2\u5f97\u7535\u5b50\u8fdb\u5165\u7535\u573a\u7684\u6700\u5927\u8ddd\u79bbX=V0^2 m/(Eq)-Eq V0^2 m^2/(2 m E^2 q^2)=(2 V0^2 m - V0^2 m)/(2Eq)=(V0^2 m)/2Eq
(3)\u6709\u80fd\u91cf\u5b88\u6052\u5f97\uff0c\u7535\u5b50\u8fdb\u5165\u7535\u573a\u6700\u5927\u8ddd\u79bb\u7684\u4e00\u534a\u65f6\u7684\u52a8\u80fd\u5373\u4e3a\u7535\u573a\u529b\u505a\u8d1f\u529f\uff08W==EqL)\u65f6L\u7684\u4e00\u534a\uff0c\u6545\u6b64\u65f6\u52a8\u80fd\u4e3a1/2W==1/2 Eq (V0^2 m)/(2Eq)==(V0^2 m)/4 (L\u4e3a\u7535\u5b50\u5728\u7535\u573a\u4e2d\u8fd0\u52a8\u7684\u6700\u5927\u8ddd\u79bb\uff0c\u4e5f\u5c31\u662f\u7b2c\u4e8c\u95ee\u4e2d\u7684X)
C
\u6839\u636e\u52a8\u80fd\u5b9a\u7406\u53ef\u5f97\uff0c\u91cd\u529b\u548c\u7535\u573a\u529b\u505a\u529f
故选A
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