问一个C语言问题:输入两个浮点数,输出较大的一个?这个怎么写程序啊? c语言中写程序 输入三个浮点数,找出其中最大的值

C\u8bed\u8a00\u95ee\u9898\uff1a\u6bd4\u8f83\u4e24\u4e2a\u6d6e\u70b9\u6570\u5927\u5c0f

1\u3001\u6d6e\u70b9\u7c7b\u578b\u4e0d\u80fd\u6bd4\u8f83\u76f8\u7b49\u6216\u4e0d\u7b49\uff0c\u4f46\u53ef\u4ee5\u6bd4\u8f83>,=,<=\u3002
2\u3001\u7528==\u4ece\u8bed\u6cd5\u4e0a\u8bf4\u6ca1\u9519\uff0c\u4f46\u662f\u672c\u6765\u5e94\u8be5\u76f8\u7b49\u7684\u4e24\u4e2a\u6d6e\u70b9\u6570\u7531\u4e8e\u8ba1\u7b97\u673a\u5185\u90e8\u8868\u793a\u7684\u539f\u56e0\u53ef\u80fd\u7565\u6709\u5fae\u5c0f\u7684\u8bef\u5dee\uff0c\u8fd9\u65f6\u7528==\u5c31\u4f1a\u8ba4\u4e3a\u5b83\u4eec\u4e0d\u7b49\u3002\u5e94\u8be5\u4f7f\u7528\u4e24\u4e2a\u6d6e\u70b9\u6570\u4e4b\u95f4\u7684\u5dee\u5f02\u7684\u7edd\u5bf9\u503c\u5c0f\u4e8e\u67d0\u4e2a\u53ef\u4ee5\u63a5\u53d7\u7684\u503c\u6765\u5224\u65ad\u5224\u65ad\u5b83\u4eec\u662f\u5426\u76f8\u7b49\u3002

\u4e00\u3001\u4e0d\u53ef\u5c06\u6d6e\u70b9\u53d8\u91cf\u7528\u201c==\u201d\u6216\u201c\uff01=\u201d\u4e0e\u4efb\u4f55\u6570\u5b57\u6bd4\u8f83\u3002\u8981\u7559\u610f\uff0c\u65e0\u8bba\u662ffloat \u8fd8\u662fdouble \u7c7b\u578b\u7684\u53d8\u91cf\uff0c\u90fd\u6709\u7cbe\u5ea6\u9650\u5236\u3002\u6240\u4ee5\u4e00\u5b9a\u8981\u907f\u514d\u5c06\u6d6e\u70b9\u53d8\u91cf\u7528\u201c==\u201d\u6216\u201c\uff01=\u201d\u4e0e\u6570\u5b57\u6bd4\u8f83\uff0c\u5e94\u8be5\u8bbe\u6cd5\u8f6c\u5316\u6210\u201c>=\u201d\u6216\u201c<=\u201d\u5f62\u5f0f\u3002
\u4e8c\u3001\u5047\u8bbe\u6d6e\u70b9\u53d8\u91cf\u7684\u540d\u5b57\u4e3ax\uff0c\u5e94\u5f53\u5c06
if (x == 0.0) // \u9690\u542b\u9519\u8bef\u7684\u6bd4\u8f83
\u8f6c\u5316\u4e3a
if ((x>=-EPSINON) && (x<=EPSINON))
\u5176\u4e2dEPSINON \u662f\u5141\u8bb8\u7684\u8bef\u5dee\uff08\u5373\u7cbe\u5ea6\uff09\u3002

#include
main()
{
float a,b,c,r;
printf("\n\u8bf7\u8f93\u5165\u7b2c\u4e00\u4e2a\u6570:");
scanf("%f".&a);
printf("\n\u8bf7\u8f93\u5165\u7b2c\u4e8c\u4e2a\u6570:");
scanf("%f".&b);
printf("\n\u8bf7\u8f93\u5165\u7b2c\u4e09\u4e2a\u6570:");
scanf("%f".&c);


r=a;
if (b>r) r=b;
if (c>r) r=c;
printf("\n%f",r);
}

#include <stdio.h>
main()
{
float a,b;
printf("\n输入第一个数:");
scanf("%f".&a);
printf("\n输入第二个数:");
scanf("%f".&a);
if (a>b)
printf("\n%f",a);
else
printf("\n%f"b);
}/*没有包括 它们相等的情况*/

#include "stdio.h"

main( )
{
int t;
float a,b;
printf("a=");
scanf("%f",&a);
printf("\nb=");
scanf("%f",&b);
if(a>b)
printf("Max=%f\n",a);
else if(b>a)
printf("Max=%f\n",b);

}

浮点数不能直接与零值比较
应该设定一个精度范围
假设定义 |a - b| <= PRICISION
为a == b; // 即在精度范围PRICISION内

float a, b;
cin >> a >> b;

const PRICISION = 0.000001; // 精度
if(a - b > PRICISION)
cout << a;
else if(a - b < -PRICISION )
cout << b;
else
cout << "a == b";

弄个简单的~~~、

#include<stdio.h>
void main()
{
float n,m;
printf("请输入要比较的两数:\n");
scanf("%f %f",&n,&m);
printf("%f\n",n>m?n:m);
}

#include<stdio.h>
void main()
{
float n,mmax;
printf("请输入要比较的数:\n");
scanf("%f%f",&n,&m);
max(m>n)? n:m;
printf("最大的数为:%f\n",max)
}

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