解方程,2倍x的平方减一等于根号三x,有一位同学解答如下
\u5316\u7b80\uff1a\u6839\u53f748\u51cf\u6839\u53f73\u662f\u591a\u5c11 \u8ba1\u7b97\uff1a\u6839\u53f7\uff08\u6839\u53f73-2\uff09\u7684\u5e73\u65b9+\u6839\u53f73\u7b49\u4e8e\u591a\u5c11 \u65b9\u7a0b\uff1a\u6839\u53f71-x=2\u7684\u6839\u662f\u591a\u5c11\u6839\u53f748\u51cf\u6839\u53f73=4\u6839\u53f73-\u6839\u53f73=3\u6839\u53f73
\u6839\u53f7\uff08\u6839\u53f73-2\uff09\u7684\u5e73\u65b9+\u6839\u53f73
=2-\u6839\u53f73+\u6839\u53f73
=2
\u6839\u53f71-x=2
1-x=4
x=1-4
x=-3
\u539f\u65b9\u7a0b\u56e0\u5f0f\u5206\u89e3\u5f97\uff1a
(x- \u6839\u53f73)[x-(2-\u6839\u53f73)]=0
\u89e3\u5f97\uff1ax=\u6839\u53f73\u6216x=2-\u6839\u53f73
2x²-√3x-1=0
x=[√3±√(3+8)]/4=(√3±√11)/4
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(2X)还是2X
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