采矿工程，爆破工程题目。急求解！
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该情况下岩石的单耗：q=Q/v 其中 Q=14 v=1/3*2*3.14*2*2=8.37（就是地面半径为2m高也是2m的圆锥体体积）q=1.67n=1.2时v‘=1/3*2*3.14*（2*1.2）*（2*1.2）=12.05 此时所用药量为：Q’=v‘*q=1.67*12.05=20.12
n=0.75时v‘’=1/3*2*3.14*（2*0.75）*（2*0.75）=4.71此时所用药量为：Q’‘=v‘’*q=1.67*4.71=7.87
绛旓細璇ユ儏鍐典笅宀╃煶鐨勫崟鑰楋細q=Q/v 鍏朵腑 Q=14 v=1/3*2*3.14*2*2=8.37锛堝氨鏄湴闈㈠崐寰勪负2m楂樹篃鏄2m鐨勫渾閿ヤ綋浣撶Н锛塹=1.67 n=1.2鏃秜鈥=1/3*2*3.14*锛2*1.2锛*锛2*1.2锛=12.05 姝ゆ椂鎵鐢ㄨ嵂閲忎负锛歈鈥=v鈥*q=1.67*12.05=20.12 n=0.75鏃秜鈥樷=1/3*2*3.14*锛2*0...
绛旓細鐢甸浄绠---(蹇呴』)鐢ㄧ數鑳藉嚮鍙戠殑璧风垎鍣ㄦ潗 甯︽湁闆风鐨勮捣鐖嗗厓浠,鏃犺鐏浄绠/鐢甸浄绠/闈炵數瀵肩垎绯荤粺,鍧囧彲涓庨潪鐢靛鐖嗙郴缁/瀵肩垎绱/鐐歌嵂杩炴帴.骞夸笢 鎴愪簯椹 閲囩熆宸ョ▼甯/涓骇1+3C鐖嗙牬宸ョ▼甯
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