求导f(x)=sin²x。。。。过程
\u6c42\u5bfc\uff1asin²x\u89e3
(sin²x)'
=2sinx(sinx)'
=2sinxcosx
=sin2x
f(x)=(sinx)^2
\u4ee4g(x)=sinx
f(g(x))=g(x)^2
f'(g(x))=2*g(x)
g'(x)=cosx
[f(g(x))]'=f'(g(x))*g'(x)=2*g(x)*g'(x)=2*sinx*cosx=sin2x
\u671b\u91c7\u7eb3\u5c0f\u5973\u5b50\u7b54\u6848\u4e3a\u6ee1\u610f\u7b54\u6848 \u8c22\u8c22
=2sinxcosx
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