武汉理工大学大学物理A和大学物理B有什么区别 求武汉大学出版社的《大学物理学》习题答案

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\u53cc\u8bed\u8bfe\u7a0b\uff1a
\u70ed\u5b66 Thermal Physics\uff1b\u70ed\u529b\u5b66\u4e0e\u7edf\u8ba1\u7269\u7406\u5b66 Thermodynamics and Statistical physics\uff1b\u7535\u52a8\u529b\u5b66 Electrodynamics\uff1b\u91cf\u5b50\u529b\u5b66 Quantum Mechanics\uff1b\u7fa4\u8bba Group Theory\uff1b\u539f\u5b50\u7269\u7406\u4e0e\u539f\u5b50\u6838\u7269\u7406 Atomic Physics and Nuclear Physics\uff1b\u975e\u7ebf\u6027\u5149\u5b66 Nonlinear Optics\u3002

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\u7b2c\u4e00\u7ae0 \u8d28\u70b9\u529b\u5b661.1 \u627e\u51fa\u4e0b\u5217\u8868\u8fbe\u5f0f\u4e2d\u7684\u9519\u8bef\uff0c \u5199\u51fa\u6b63\u786e\u8868\u8fbe\uff1a\uff081\uff09 r = x + y\u89e3\u7b54\uff1ar = xi + yj\uff082\uff09 v = v x i + v y j\u89e3\u7b54\uff1av = v x i + v y j\uff083\uff09 v = v x i + v y j\u89e3\u7b54\uff1av = v x i + v y j\uff084\uff09 v = v x i + v y j\u89e3\u7b54\uff1av = v x i + v y j\uff085\uff09 v = (v 2x + v2y+ v 2z )1/2\u89e3\u7b54\uff1av = (v 2x + v2y+ v 2z )1/21.2 \u5df2\u77e5r = 2ti − 4t 2 j\uff0c \u7b2c1\u79d2\u5185\u7684\u4f4d\u79fb \u0394r = 2i − 4j \uff0c \u4efb\u610f\u65f6\u523b\u7684\u901f\u5ea6v(t) = 2i − 8tj \uff0c \u52a0\u901f\u5ea6a(t) = −8j \uff0c \u8f68\u8ff9\u65b9\u7a0b\u4e3a y = −x 21.3 \u5e73\u629b\u7269\u4f53\u7684\u8fd0\u52a8\u5b66\u65b9\u7a0bx = 5t\uff0c y = 5t 2 \uff0c \u5219\u4efb\u610f\u65f6\u523b\u7684\u4f4d\u77e2r = 5ti + 5t 2 j \uff0c \u901f\u5ea6v(t) = 5i + 10tj \uff0c\u52a0\u901f\u5ea6a(t) = 10j \uff0c \u8f68\u9053\u65b9\u7a0b\u4e3a x 2 = 5y1.4 \u76f4\u7ebf\u8fd0\u52a8\u7684\u70b9\uff0c \u5176\u901f\u5ea6v(t) = e −t \uff0c \u521d\u59cb\u4f4d\u7f6e\u4e3ax 0 = 2\uff0c \u5219x(t) = 3 − e −t\u89e3\u7b54\uff1ax(t) = x 0 +ˆt0e −t dt = 2 + (−e −t )?t0= 2 + (−e −t +1)1.5 \u4ece\u5730\u9762\u4e0a\u629b\u4e00\u4e2a\u7269\u4f53\uff0c \u5176\u9ad8\u5ea6h = 10t−5t 2 \uff0c \u4efb\u610f\u65f6\u523b\u7684\u901f\u5ea6v(t) = 10 − 10t \uff0c \u5230\u8fbe\u6700\u9ad8\u70b9\u7684\u65f6\u523b\u662ft = 1\u89e3\u7b54\uff1a\u4ece\u7269\u7406⾓\u5ea6\u6765\u770b\uff0c \u5728\u6700⾼\u70b9\u5904\uff0c \u7269\u4f53\u7684\u901f\u5ea6\u4e3a\u96f6v = dh/dt = 10 − 10t = 0\uff0c \u5f97t = 1\uff0e\u4ece\u6570\u5b66⾓\u5ea6\u7406\u89e3\uff0ch(t)\u662f\u65f6\u95f4\u7684\u51fd\u6570\uff0c \u8be5\u51fd\u6570\u53d6\u5f97\u6781\u5024\u7684\u6761\u4ef6\u662f dh/dt = 0\uff0e1.6 \u5224\u5b9a\u6b63\u8bef\uff1a\uff081\uff09 \u76f4\u7ebf\u8fd0\u52a8\u7684\u7269\u4f53\u8fbe\u5230\u6700\u5c0f\u901f\u5ea6\u65f6\uff0c \u52a0\u901f\u5ea6\u4e00\u5b9a\u4e3a\u96f6\uff1b \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 [✓]\uff082\uff09 \u76f4\u7ebf\u8fd0\u52a8\u7684\u7269\u4f53\u8fbe\u5230\u6700\u5927\u4f4d\u7f6e\u65f6\uff0c \u901f\u5ea6\u4e00\u5b9a\u4e3a\u96f6\uff1b \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 [✓]1.7 \u9009\u62e9\uff1a \u82e5\u8d28\u70b9\u7684\u4f4d\u77e2\u4e3ar\uff0c \u901f\u5ea6\u4e3av\uff0c \u901f\u7387\u4e3av\uff0c \u8def\u7a0b\u4e3as\uff0c \u5219\u5fc5\u6709 \u3010 B \u3011A\uff0e|\u0394r| = \u0394s = \u0394rB\uff0e|\u0394r| ̸= \u0394s ̸= \u0394r\uff0c \u5f53\u0394t \u2192 0 \u65f6\uff0c \u6709|dr| = ds ̸= drC\uff0e|\u0394r| ̸= \u0394s ̸= \u0394r\uff0c \u5f53\u0394t \u2192 0 \u65f6\uff0c \u6709|dr| = dr ̸= dsD\uff0e|\u0394r| ̸= \u0394s ̸= \u0394r\uff0c \u5f53\u0394t \u2192 0 \u65f6\uff0c \u6709|dr| = dr = ds1.8 \u9009\u62e9\uff1a \u6839\u636e\u4e0a\u9898\u7684\u7b26\u53f7\uff0c \u5219\u5fc5\u6709 \u3010 C \u3011A\uff0e|v| = v, |v| = v B\uff0e|v| ̸= v, |v| ̸= vC\uff0e|v| = v, |v| ̸= v D\uff0e|v| ̸= v, |v| = v1.9 \u9009\u62e9\uff1a \u8d28\u70b9\u5728\u67d0\u77ac\u65f6\u4f4d\u4e8e\u4f4d\u77e2r = (x,y)\u5904\uff0c \u5176\u901f\u5ea6\u5927\u5c0fv \u7684\u8ba1\u7b97\u9519\u8bef\u7684\u4e3a \u3010 A \u3011A\uff0e drdtB\uff0e?drdt? C\uff0e dsdtD\uff0e\u221a (dxdt) 2+( dydt) 21.10 \u76f4\u5f84\u4e3a40 cm\u7684\u5b9a\u6ed1\u8f6e\u4e0a\u7f20\u7ed5\u7740\u4e00\u6761\u7ec6\u94a2\u4e1d\u7ef3\uff0c \u7ef3\u7684\u53e6\u4e00\u7aef\u540a\u7740\u4e00\u4e2a\u91cd\u7269\uff0c \u82e5\u67d0\u65f6\u523b\u91cd\u7269\u4e0b\u843d\u7684\u52a0\u901f\u5ea6\u4e3a1 m/s 2 \uff0c \u901f\u5ea6\u4e3a0.3 m/s\uff0c \u5219\u6b64\u523b\u6ed1\u8f6e\u7684\u89d2\u52a0\u901f\u5ea6\u4e3a 5 rad/s 2 \uff0c \u89d2\u901f\u5ea6\u4e3a 1.5\u00b71\u00b7\u8bfe\u5802\u7ec3\u4e60\u7b54\u6848 \u7b2c1\u7ae0 \u8d28\u70b9\u529b\u5b66rad/s\u89e3\u7b54\uff1a\u7269\u4f53\u4e0b\u843d\u7684\u8ddd\u79bb\u7b49\u4e8e\u6ed1\u8f6e\u8fb9\u7f18\u8f6c\u52a8\u7684\u8ddd\u79bb\uff0c \u7269\u4f53\u4e0b\u843d\u7684\u901f\u5ea6\u5c31\u662f\u6ed1\u8f6e\u8fb9\u7f18\u7684\u7ebf\u901f\u5ea6\uff0c \u7269\u4f53\u4e0b\u843d\u7684\u52a0\u901f\u5ea6\u7b49\u4e8e\u6ed1\u8f6e\u8fb9\u7f18\u7684\u5207\u7ebf\u52a0\u901f\u5ea6\uff0e1.11 \u534a\u5f84\u4e3a 0.1 m \u7684\u8f68\u9053\u4e0a\u6709\u4e00\u4e2a\u8d28\u70b9\uff0c\u5b83\u7684\u89d2\u4f4d\u7f6e \u03b8 = \u03c0 + t 2 \uff0c \u5219\u4efb\u610f\u65f6\u523b\u7684\u5207\u7ebf\u52a0\u901f\u5ea6a t = 0.2 \uff0c \u6cd5\u7ebf\u52a0\u901f\u5ea6a n = 0.4t 2\u89e3\u7b54\uff1a\u03c9 =d\u03b8dt= 2t\uff0c\u03b2 =d\u03c9dt= 2\uff0ca t = R\u03b2\uff0ca n = R\u03c9 21.12 \u534a\u5f84\u4e3a 1 m \u7684\u8f68\u9053\u4e0a\u6709\u4e00\u4e2a\u8d28\u70b9\uff0c\u5b83\u7684\u8def\u7a0b s = 2t − 0.5t 2 \uff0c \u5219\u4efb\u610f\u65f6\u523b\u7684\u5207\u7ebf\u52a0\u901f\u5ea6a t = −1 \uff0c \u6cd5\u7ebf\u52a0\u901f\u5ea6a n = (2 − t) 2\u89e3\u7b54\uff1av =dsdt= 2 − t\uff0ca t =dvdt= −1\uff0ca n =v 2R1.13 \u5224\u5b9a\u6b63\u8bef\uff1a\uff081\uff09 \u4ee5\u5706\u5fc3\u4e3a\u5750\u6807\u539f\u70b9\u7684\u5706\u5468\u8fd0\u52a8\u6ee1\u8db3 dr/dt = 0\u4e14 dr/dt ̸= 0\uff1b\u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 [✓]\uff082\uff09 \u5300\u901f\u7387\u5706\u5468\u8fd0\u52a8\u6ee1\u8db3 dv/dt = 0\u4e14 dv/dt = 0\uff1b........................................... [\u00d7]\uff083\uff09 \u5300\u901f\u7387\u66f2\u7ebf\u8fd0\u52a8\u6ee1\u8db3 dv/dt = 0\u4e14 dv/dt ̸= 0\uff1b \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 [✓]\uff084\uff09 \u6cd5\u7ebf\u52a0\u901f\u5ea6\u7684\u6548\u679c\u662f\u6539\u53d8\u901f\u5ea6\u7684\u65b9\u5411\uff1b\u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 [✓]\uff085\uff09 \u5207\u7ebf\u52a0\u901f\u5ea6\u7684\u6548\u679c\u662f\u6539\u53d8\u901f\u5ea6\u7684\u5927\u5c0f\uff1b\u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 [✓]\uff086\uff09 \u5706\u5468\u8fd0\u52a8\u4e2d\uff0c \u82e5a n \u662f\u5e38\u91cf\uff0c \u5219a t \u4e3a\u96f6\uff1b \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 [✓]\uff087\uff09 \u5706\u5468\u8fd0\u52a8\u4e2d\uff0c \u82e5a t \u662f\u5e38\u91cf\uff0c \u5219a n \u4e5f\u662f\u5e38\u91cf\uff1b...............................................[\u00d7]1.14 \u7269\u4f53\u4e0b\u843d\uff0c \u53d7\u5230\u91cd\u529bmg \u4ee5\u53ca\u7a7a\u6c14\u963b\u529bf = kv\uff0c \u5219\u7ec8\u6781\u901f\u5ea6v T = mg/k \uff0c \u82e5\u963b\u529bf = kv 2 \uff0c \u5219\u7ec8\u6781\u901f\u5ea6v T =\u221amg/k1.15 \u5224\u5b9a\u6b63\u8bef\uff1a\uff081\uff09 \u7269\u4f53\u8d28\u91cf\u8d8a\u5927\uff0c \u60ef\u6027\u8d8a\u5927\uff1b\u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 \u00b7 [✓]\uff082\uff09 \u7269\u4f53\u7684\u901f\u5ea6\u8d8a\u5927\uff0c \u60ef\u6027\u8d8a\u5927\uff1b............................................................. [\u00d7]1.16 \u9009\u62e9\uff1a \u7528\u6c34\u5e73\u529bF N \u628a\u4e00\u4e2a\u7269\u4f53\u538b\u7740\u9760\u5728\u7c97\u7cd9\u7684\u7ad6\u76f4\u5899\u9762\u4e0a\u4fdd\u6301\u9759\u6b62\uff0c \u5f53F N \u9010\u6e10\u589e\u5927\u65f6\uff0c \u7269\u4f53\u6240\u53d7\u7684\u9759\u6469\u64e6\u529bF f \u7684\u5927\u5c0f \u3010 A \u3011A\uff0e\u4e0d\u4e3a\u96f6\uff0c \u4f46\u4fdd\u6301\u4e0d\u53d8\uff1b B\uff0e\u968fF N \u6210\u6b63\u6bd4\u5730\u589e\u5927\uff1bC\uff0e\u8fbe\u5230\u67d0\u4e00\u6700\u5927\u503c\u540e\uff0c \u5c31\u4fdd\u6301\u4e0d\u53d8\uff1b1.17 \u9009\u62e9\uff1a \u4e00\u6bb5\u8def\u9762\u6c34\u5e73\u7684\u516c\u8def\uff0c \u8f6c\u5f2f\u5904\u8f68\u9053\u534a\u5f84\u4e3aR\uff0c \u6c7d\u8f66\u8f6e\u80ce\u4e0e\u8def\u9762\u95f4\u7684\u6469\u64e6\u56e0\u6570\u4e3a \u03bc\uff0c \u8981\u4f7f\u6c7d\u8f66\u4e0d\u81f3\u4e8e\u53d1\u751f\u4fa7\u5411\u6253\u6ed1\uff0c \u6c7d\u8f66\u5728\u8be5\u5904\u7684\u884c\u9a76\u901f\u7387 \u3010 C \u3011A\uff0e\u4e0d\u5f97\u5c0f\u4e8e\u221a\u03bcgR\uff1b B\uff0e\u5fc5\u987b\u7b49\u4e8e\u221a\u03bcgR\uff1bC\uff0e\u4e0d\u5f97\u5927\u4e8e\u221a\u03bcgR\uff1b D\uff0e\u8fd8\u9700\u6c7d\u8f66\u7684\u8d28\u91cfm\u51b3\u5b9a\uff1b1.18 \u9009\u62e9\uff1a \u5c0f\u7269\u4f53\u6cbf\u56fa\u5b9a\u7684\u5706\u5f27\u5f62\u5149\u6ed1\u8f68\u9053\u7531\u9759\u6b62\u4e0b\u6ed1\uff0c \u5728\u4e0b\u6ed1\u8fc7\u7a0b\u4e2d \u3010 B \u3011A\uff0e\u5b83\u7684\u52a0\u901f\u5ea6\u65b9\u5411\u6c38\u8fdc\u6307\u5411\u5706\u5fc3\uff0c \u901f\u7387\u4e0d\u53d8\uff1bB\uff0e\u8f68\u9053\u7684\u652f\u6491\u529b\u7684\u5927\u5c0f\u4e0d\u65ad\u589e\u52a0\uff1bC\uff0e\u5b83\u53d7\u5230\u7684\u5408\u5916\u529b\u5927\u5c0f\u53d8\u5316\uff0c \u65b9\u5411\u6c38\u8fdc\u6307\u5411\u5706\u5fc3\uff1bD\uff0e\u5b83\u53d7\u5230\u7684\u5408\u5916\u529b\u5927\u5c0f\u4e0d\u53d8\uff0c \u901f\u7387\u4e0d\u65ad\u589e\u52a0\uff1b1.19 \u5728\u4e1c\u5317\u5929\u5750\u6807\u7cfb\u4e2d\uff0cA\u8f66\u5411\u4e1c\u8fd0\u52a8v A = 2i m/s\uff0cB\u8f66\u5411\u5317\u8fd0\u52a8\uff0cv B = 3j m/s\uff1b \u5219B\u76f8\u5bf9\u4e8eA\u7684\u901f\u5ea6v BA = (3j − 2i) m/s1.20 \u7a33\u5b9a\u7684\u5357\u98ce\u98ce\u901fv 1 = 2 m/s\uff0c \u67d0\u4eba\u5411\u897f\u5feb\u8dd1\uff0c \u901f\u7387v 2 = 4 m/s\uff0e \u6b64\u4eba\u611f\u53d7\u5230\u7684\u98ce\u901f\u5927\u5c0f\u4e3a\u221a2 2 + 4 2 =\u221a20 m/s
\u5176\u4ed6\u7684\u5728\u9644\u4ef6\u91cc

难度要求不一样,A最难,B次之,C最简单!我们工程类非物理相关专业的学C

大学物理A的学分是5,大学物理B的学分是4

一个简单一个难,不同专业队物理的要求不同。就像高数AB一样的道理啊啊~

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