写一个函数sum，函数功能实现1-100求和，函数返回值为int型，在主函数调用sum函数，结果在主函数中输出 编写一个函数sum(i),将输入的参数i的各位求和，返回求和...
\u7f16\u5199\u4e00\u4e2a\u51fd\u6570SUM\u5b9e\u73b0\u6c421+2+3+\u2026100\u7684\u6c42\u548c,\u7ed3\u679c\u5728MAIN\u51fd\u6570\u4e2d\u8f93\u51fa#include
int main() {
printf("sum:%d\n", sum());
return 0;
}
int sum() {
int i;
int sum = 0;
for (i = 1; i <= 100; i++)
sum += i;
return sum;
}
\u4f60\u597d\uff0c\u63d0\u95ee\u8005:
\u5982\u679c\u89e3\u51b3\u4e86\u4f60\u7684\u95ee\u9898\u8bf7\u91c7\u7eb3\uff0c\u82e5\u6709\u7591\u95ee\u8bf7\u8ffd\u95ee\uff0c\u8c22\u8c22\uff01
package com.zyx.cn.baidu_test;import java.util.Scanner;/** * \u7f16\u5199\u4e00\u4e2a\u51fd\u6570sum(i),\u5c06\u8f93\u5165\u7684\u6574\u5f62\u53c2\u6570i\uff08i\u22650\uff09\u7684\u5404\u4f4d\u6c42\u548c\uff0c\u8fd4\u56de\u6c42\u548c\u7ed3\u679c\u3002 * \u5728main()\u51fd\u6570\u4e2d\u6d4b\u8bd5\u6b64\u51fd\u6570\uff0c\u4ece\u952e\u76d8\u8f93\u5165\u6574\u6570n\uff08n\u2208[1,20]\uff09\uff0c * \u7136\u540e\u518d\u8f93\u5165n\u4e2a\u975e\u8d1f\u6574\u6570\uff0c\u5bf9\u4e8e\u6bcf\u4e00\u4e2a\u975e\u8d1f\u6574\u6570\u8c03\u7528sum\u51fd\u6570\u6c42\u5404\u4f4d\u6570\u548c\uff0c * \u5c06\u7ed3\u679c\u8f93\u51fa\u5230\u5c4f\u5e55\u3002 * @author yltd */public class SumShow {public static void main(String[] args) {Scanner sc= new Scanner(System.in);System.out.println("\u8bf7\u8f93\u5165\u5927\u4e8e\u7b49\u4e8e0\uff0c\u5c0f\u4e8e\u7b49\u4e8e20\u7684\u6570");int i =sc.nextInt();sum(i);System.out.println("\u8bf7\u8f93\u5165\u4e00\u4e2a\u975e\u8d1f\u6574\u6570");int ii =sc.nextInt();sum(ii);}public static int sum(int i){int sum =0;for (int j = 0; j <= i; j++) {sum+=j;}System.out.println(sum);return sum;}}\u8bf7\u8f93\u5165\u5927\u4e8e\u7b49\u4e8e0\uff0c\u5c0f\u4e8e\u7b49\u4e8e20\u7684\u65701055\u8bf7\u8f93\u5165\u4e00\u4e2a\u975e\u8d1f\u6574\u657020210
int SUM()
{
int n, sum= 0;
for(n = 1;n<=100;n++)
{
sum += n;
}
return sum;
}
int main(void)
{
printf("1-100的和为%d",SUM());
return 0;
}
#include <stdio.h>
int he(void)
{
int n;
int sum= 0;
for(n = 1;n<=100;n++)
{
sum += n;
}
return sum;
}
int main(void)
{
printf("1-100的和为%d",he());
return 0;
}
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绛旓細int sum(int x, int y) /*瀵鍑芥暟sum()杩涜瀹氫箟*/ { return x + y;} 2銆丆浠ｇ爜濡備笅锛歩nclude <stdio.h> int f(int n) { // 杩斿洖n!int i, s = 1;for (i = 1; i <= n; i++)s = s * i;return s;} int main() { int sum = f(4) + f(6) + f(7);printf("...
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绛旓細姹傚拰鍑芥暟涓锛sum 1銆佹垜浠夌湅鐪媠um鐨勮娉曪細SUM(number1,number2, 鈥)璇硶瑙ｈ锛歴um鏄嚱鏁板悕锛屽畠鐨勭敤閫旀槸瀵逛竴缁勬暟鍊间笉娣讳换浣曟潯浠跺湴鐩存帴杩涜姹傚拰銆傛嫭鍙蜂腑鐨刵umber1銆乶umber2鐩村埌number 255閮芥槸鍙傛暟(07鍙婁互涓婄増鏈渶澶氬厖璁255涓紝03鐗堟渶澶氬彧鍏佽30涓弬鏁)锛屼篃灏辨槸鎴戜滑骞冲父鎵璇寸殑鍔犳暟銆備絾鏄繖閲岀殑鍙傛暟鍙...
绛旓細include <stdio.h> int SUM(){ int n, sum= 0;for(n = 1;n<=100;n++){ sum += n;} return sum;} int main(void){ printf("1-100鐨勫拰涓%d",SUM());return 0;}
绛旓細PHP锛<?php function SUM($oArray){ echo array_sum($oArray); } $a = array ('a' => 1, 'b' => 2); SUM($a);?>
绛旓細int sum(a,b) /*姹傚拰鍑芥暟*/ { int he;he=a+b;return he; /*杩斿洖姹傚拰缁撴灉*/ } int main(){ int num1,num2;printf("璇疯緭鍏ヨ姹傚拰鐨勪袱涓-32768鍒32767涔嬮棿鐨勬暣鏁癨n");scanf("%d %d",&num1,&num2);printf("涓や釜鏁扮殑鍜岋細%8d\n",sum(num1,num2)); /*姹傚拰鍑芥暟璋冪敤*/ system(...
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