求大神帮忙画此C语言程序的程序框图 ，初学C语言数学逻辑不强 求大神帮忙画此C语言程序的程序框图 ,初学C语言数学逻辑不强
\u6c42\u5927\u795e\u5e2e\u5fd9\u753b\u6b64C\u8bed\u8a00\u7a0b\u5e8f\u7684\u7a0b\u5e8f\u6846\u56fe \uff0c\u521d\u5b66C\u8bed\u8a00\u6570\u5b66\u903b\u8f91\u4e0d\u5f3a(\u6025\u8c22\u8c22)
\u662f\u8fd9\u4e2a\u5417\uff1f
\u4ee3\u7801\u5c31\u8fd9\u6837\u4e86\u5176\u4ed6\u7684\u4f60\u81ea\u5df1\u5199\u5427#include #include void output(int a[5][5]){int i, j;for(i = 0; i =0 && x+i =0 && y+i =0 && x-i =0 && y+i < 5 )a[x-i][y+i] = 2;}a[x][y] = 1;}void set(int a[5][5], int cnt, int x, int y){int t[5][5];int i, j;for(i = 0; i < 5; i++){for(j = 0; j < 5; j ++){if(i*5+j < x*5+y) continue;if(a[i][j]) continue;if(cnt == 4){a[i][j] = 1;output(a);a[i][j] = 0;}else{memcpy(t, a, sizeof t);set_one(t, i, j);set(t, cnt+1, i, j);}}}}int main(){int a[5][5]={{0}};set(a, 0, 0,0);return 0;}
使用visio完成，网上下载软件，然后可以自己学学。
麻烦，没空仔细画，你可以把中间每一个矩形替换成一串菱形的if判断框
#include <stdio.h>
void sort(int [], int);
int main() {
int a[4] = {0};
printf("请输入四个数据哦：");
scanf("%d,%d,%d,%d",a,a+1,a+2,a+3);
sort(a,4);
for(int i = 0; i < 4; ++i) {
printf("%d
",a[i]);
}
return 0;
}
void sort(int x[], int N) {
int temp = 0;
for(int i = 0; i < N; ++i) {
for(int j = i + 1; j < N; ++j) {
if(x[i] > x[j]) {
temp = x[i];
x[i] = x[j];
x[j] = temp;
}
}
}
}
jude community是画程序框图 流程图的软件 你可以发下你的邮箱
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