输入一个整数N,逆序输出N的各位数,如果输出的起始是0,则不输出,从非0位开始输出。 输入一个正整数 输出整数的逆序,如果末尾为0首位不输出0c语...

python \u8f93\u5165\u4e00\u4e2a\u6574\u6570N\uff0c\u9006\u5e8f\u8f93\u51faN\u7684\u5404\u4f4d\u6570\uff0c\u5982\u679c\u8f93\u51fa\u7684\u8d77\u59cb\u662f0\uff0c\u5219\u4e0d\u8f93\u51fa\uff0c\u4ece\u975e0\u4f4d\u5f00\u59cb\u8f93\u51fa

# -*- coding:utf-8 -*-x=raw_input('Please input a number:\r\n')print ''.join([''.join(i) for i in x[::-1] if i!='0'])>>>Please input a number:123321

\u601d\u8def\uff1a\u9006\u5e8f\u8f93\u51fa\u4e00\u4e2a\u6574\u6570\u53ef\u4ee5\u5bf9\u5176\u966410\u76f4\u5230\u5176\u4e3a0\u4e3a\u6b62\uff0c\u5e76\u8f93\u51fa\u5176\u5bf910\u53d6\u4f59\uff0c\u6700\u540e\u7684\u7ed3\u679c\u5c31\u662f\u8fd9\u4e2a\u6574\u6570\u7684\u9006\u5e8f\u3002\u53c2\u8003\u4ee3\u7801\uff1a#includeintmain(){intn;scanf("%d",&n);while(n){printf("%d",n%10);n/=10;}return0;}/*\u8f93\u51fa\uff1a1234554321*/

#include "stdio.h"
int main(int argv,char *argc[]){
int n;
printf("Input an integer(int n>=0)...
n=");
if(scanf("%d",&n)!=1 || n<0){
printf("Input error, exit...
");
return 0;
}
while(n%10==0)
n/=10;
while(n){
printf("%d",n%10);
n/=10;
}
printf("
");
return 0; 
}

运行样例“



#include <stdio.h>
int main()
{
    int a, t;
    scanf ("%d", &a);
    t = 0;
    while (a){
        t= t*10+a%10;
        a/=10;
    }
    printf("%d
", t);
    getch();
    
    return 0;
}


  • 杈撳叆涓涓暣鏁癗,閫嗗簭杈撳嚭N鐨鍚勪綅鏁,濡傛灉杈撳嚭鐨勮捣濮嬫槸0,鍒欎笉杈撳嚭,浠庨潪0...
    绛旓細include "stdio.h"int main(int argv,char *argc[]){int n;printf("Input an integer(int n>=0)...\nn=");if(scanf("%d",&n)!=1 || n<0){printf("Input error, exit...\n");return 0;}while(n%10==0)n/=10;while(n){printf("%d",n%10);n/=10;}printf("\n");r...
  • 浠庨敭鐩樿鍏涓涓暟n,鍏閫嗗簭杈撳嚭n鐨鍚勪綅鏁,鍐嶈緭鍑簄鐨勫悇浣嶆暟涔嬪拰.
    绛旓細int n,sum=0,x; printf("璇杈撳叆涓涓暣鏁:"); scanf("%d",&n); printf("璇ユ暟鐨勫悇浣嶄箣閫嗗簭涓:"); while(n){ sum+=(x=n%10); printf("%d",x); n/=10; } printf("\n璇ユ暟鐨勫悇浣嶆暟涔嬪拰涓:%d\n",sum);} White_MouseYBZ | 鍙戝竷浜2013-07-12 涓炬姤| 璇勮 7 0 涓烘偍鎺ㄨ崘: 钁遍敭鐩杈...
  • c璇█濡備綍灏涓涓暟閫嗗簭杈撳嚭?
    绛旓細鍦–璇█涓紝鍙互浣跨敤涓涓猣or寰幆鎴栭掑綊鏉ヨ緭鍑轰竴涓暟鐨勯嗗簭銆備互涓嬫槸涓ょ鏂规硶鐨勭ず渚嬶細浣跨敤for寰幆锛氶鍏堝畾涔涓涓暣鍨鍙橀噺n锛鐢ㄤ簬瀛樺偍闇瑕杈撳嚭閫嗗簭鐨勬暟銆傜劧鍚庝娇鐢╢or寰幆锛屼粠n鐨涓綅寮濮嬶紝渚濇鍙栧嚭姣忎竴浣锛岄嗗簭杈撳嚭銆傚湪寰幆浣撲腑锛屼娇鐢╬rintf鍑芥暟杈撳嚭姣忎竴浣嶃傜ず渚嬩唬鐮佸涓嬶細浣跨敤閫掑綊锛氶鍏堝畾涔変竴涓暣鍨嬪彉閲弉锛...
  • 鐢–璇█杈撳叆涓涓姝鏁存暟n,灏嗗叾閫嗗簭杈撳嚭?
    绛旓細```c include <stdio.h> int main() { int n, rev = 0;printf("璇杈撳叆涓涓姝鏁存暟锛");scanf("%d", &n);while(n != 0) { rev = rev * 10 + n % 10;n /= 10;} printf("閫嗗簭杈撳嚭涓猴細%d\n", rev);return 0;} ```浠g爜鐨勬濊矾鏄厛瀹氫箟涓涓彉閲弉鏉ュ瓨鍌ㄨ緭鍏ョ殑姝f暣鏁帮紝鐒跺悗...
  • 浣跨敤閿洏杈撳叆涓涓澶氫綅鏁存暟n,鍒╃敤寰幆瀹炵幇灏嗚繖涓暣鏁閫嗗簭杈撳嚭?
    绛旓細} printf("閫嗗簭杈撳嚭涓猴細%d\n", reversed);return 0;} 杩欓噷浣跨敤scanf鍑芥暟浠庨敭鐩杈撳叆涓涓澶氫綅鏁存暟n锛鐒跺悗浣跨敤寰幆灏嗚繖涓暣鏁伴嗗簭杈撳嚭銆傚惊鐜腑锛屾瘡娆″彇鍑簄鐨勪釜浣嶆暟锛屽姞鍏ュ埌reversed鐨勬湯灏撅紝鐒跺悗灏唍闄や互10鍘绘帀涓綅鏁般傛渶缁堬紝reversed涓瓨鍌ㄧ殑灏辨槸n鐨勯嗗簭鏁銆傝繍琛岀▼搴忓悗锛岃緭鍏ヤ竴涓浣嶆暣鏁帮紝绋嬪簭浼氬皢鍏堕嗗簭...
  • pascal杈撳叆涓涓暣鏁癗(1<=N<=10000000),鎶婂畠鐨勫悇浣嶆暟瀛鍊掑簭杈撳嚭銆侼鏈 ...
    绛旓細杈撳叆涓涓姝鏁存暟n锛鍙互鍋囪n鍦╥nt鑼冨洿鍐 杈撳嚭灏唍鎸夊叾閫嗗簭杈撳嚭锛屾瘡涓暟瀛楀悗鏈変竴涓┖鏍硷紝杈撳嚭鍗犱竴琛屻/ include<stdio.h> int main(){int i;int n;scanf("%d",&n);int num = 0;for(i = 0; ; i ++){num = n % 10;n /= 10;printf("%d\n",num);if( n < 1)break;]return 0...
  • 鐢–璇█杈撳叆涓涓姝鏁存暟n,灏嗗叾閫嗗簭杈撳嚭?
    绛旓細C璇█杈撳叆涓涓姝鏁存暟n,灏嗗叾閫嗗簭杈撳嚭锛歩nclude<stdio.h> include<stdlib.h> int main(){ int a;while(scanf("%d",&a)!= EOF){ while(a>0){ printf("%d",a%10);a = a/10;} printf("\n");} return 0;} 杩愯缁撴灉濡備笅锛
  • 杈撳叆姝鏁存暟n,姹傚嚭閫嗗簭鏁,骞跺皢鎵鏈夐嗗簭鏁板鍒嗗埆杈撳嚭銆侰璇█
    绛旓細include <stdio.h> define NUM 20 void main(){ long n;int data[NUM]={0},len=0;scanf("%d",&n);do { data[len++] = n%10;n/=10;}while(n!=0);for(n=0;n<len;n++){ printf("%d",data[n]);} }
  • python 杈撳叆涓涓暣鏁癗,閫嗗簭杈撳嚭N鐨鍚勪綅鏁,濡傛灉杈撳嚭鐨勮捣濮嬫槸0,鍒欎笉杈撳嚭...
    绛旓細-*- coding:utf-8 -*-x=raw_input('Please input a number:\r\n')print ''.join([''.join(i) for i in x[::-1] if i!='0'])>>>Please input a number:123321
  • 浠庨敭鐩樿鍏涓涓暟n,鍏閫嗗簭杈撳嚭n鐨鍚勪綅鏁,鍐嶈緭鍑簄鐨勫悇浣嶆暟涔嬪拰.
    绛旓細{ printf("%c",s[i]);sum= sum + s[i]-'0';} printf("\nsum: %d\n",sum);} // 濡傛灉缂栬瘧鍣ㄦ敮鎸佷腑鏂杈撳嚭锛浣犲彲浠ユ敼涓枃銆// 濡傛灉杈撳叆鏁闀夸簬79瀛楃锛屼綘鍙互澧炲姞s鐨勫ぇ灏忋// 鑻ラ渶鍒ゆ柇杈撳叆鏄惁鏄暟瀛,鍙互鍦ㄥ惊鐜噷鍔犲叆 if ( (s[i] >= '0') && (s[i] <= '9') )...
  • 扩展阅读:输入三个整数xyz 由小到大输出 ... java逆序输出一个整数 ... 6-1逆序输出n个整数 ... 输入四位整数逆序输出 ... python逆序输出123 ... 将一个正整数逆序输出 ... 输入五位数 逆序输出 ... 输入n位整数反序输出 ... 输入一个整数n将n倒序输出 ...

    本站交流只代表网友个人观点,与本站立场无关
    欢迎反馈与建议,请联系电邮
    2024© 车视网