C语言用函数来实现输入一个五位数,输出它与其反向相加之和。如12345结果为12345+54321=66666 C语言任意输入一个有五位数字的正整数,逆序输出每一数位上的数...

C\u8bed\u8a00\u7f16\u7a0b\uff0c\u8f93\u5165\u4e00\u4e2a\u4e94\u4f4d\u6570\uff0c\u8f93\u51fa\u53cd\u5411\u6570\u3002\u4f8b\u598212345\uff0c\u8f93\u51fa\u4e3a54321\u3002\u3002\u3002\u62dc\u6258\u770b\u770b\u9519\u54ea\u513f\u4e86

#include int main(void){ int x; printf("Please input a number: "); scanf("%d", &x); if(x>9999 && x0); } else printf("Data error."); return 0;}

#include
usingnamespacestd;
intmain(){
intoriginal,key,result=0;
cout<<"PleaseEntertheNumber:"<<endl;
cin>>original;
do
{
key=original%10;
if(key==0)
{
cout<<"NewNumberis0"<<original;
//original=(original-key)/10;
}
else
{
result=key+result*10;//result\u9700\u8981\u79fb\u4f4d
original=(original-key)/10;
//cout<<"NewNumberis"<<result;
}

}while(key!=0);//key=0\u662f\u7ec8\u6b62\u6761\u4ef6
cout<<"NewNumberis"<<result<<endl;
return0;
}

\u6269\u5c55\u8d44\u6599
c++\uff0c\u8f93\u5165\u4e00\u4e2a\u6574\u6570\u503c\u5e76\u8f93\u51fa\u6b64\u6574\u6570\u7684\u5404\u6570\u5b57\u53cd\u5e8f\u7684\u6570\u503c

#include
usingnamespacestd;
voidfunc(int);
intmain()
{
intnum;
cout<<"\u8f93\u5165\u4e00\u4e2a\u6574\u6570\uff1a";
cin>>num;
func(num);
return0;
}
voidfunc(intn)
{
intcon=0;
while(n)
{
con=con*10+n%10;
n/=10;
};
cout<<"\u8fd9\u4e2a\u6570\u7684\u53cd\u5e8f\uff1a"<<con<<endl;
}

参考代码如下:

#include<stdio.h>

int main()
{
int number,numberInput,reverse=0,sum=0;
printf("Please input a number(10000~99999):");
scanf("%d",&numberInput);
number=numberInput;
for(int i=0;i<5;i++){
reverse=reverse*10+number%10;
number/=10;
}
printf("%d+%d=%d",numberInput,reverse,numberInput+reverse);
    return 0;               
}

执行效果如下:



#include<stdio.h>




int main()
{
int n,sum = 0,k;
while(scanf("%d",&n) == 1) {
k =10000;
sum = 0;
sum += n;
while(n) {
sum += n%10  * k;
n /=10;
k /= 10;
}
printf("%d
",sum);
}
return 0;
}


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