解方程：(x-1)的平方=(3-2x)的平方
\u89e3\u65b9\u7a0b\uff082x+1\uff09\u7684\u5e73\u65b9=\uff08x-3\uff09\u7684\u5e73\u65b9\u56e0\u4e3a
\uff082x+1\uff09\u7684\u5e73\u65b9=\uff08x-3\uff09\u7684\u5e73\u65b9
\u6240\u4ee5
2x+1=x-3
x=-4
\u6216
2x+1=-(x-3)
3x=2
x=2/3
\u5373
x=-4\u62162/3
\u60a8\u597d\uff1a
(x-3\uff09\uff08x+1\uff09=\uff082x+3)-(x\u7684\u5e73\u65b9+1\uff09
x²-2x-3=2x+3-x²-1
x²-2x-3=-x²+2x+2
x²+x²-2x-2x-3-2=0
2x²-4x-5=0
x²-2x-2.5=0
x²-2x+1-3.5=0
(x-1)²=3.5
x-1=\u00b1\u221a3.5
x=1\u00b11/2\u221a7
\u4e0d\u660e\u767d\uff0c\u53ef\u4ee5\u8ffd\u95ee
\u5982\u6709\u5e2e\u52a9\uff0c\u8bb0\u5f97\u91c7\u7eb3\uff0c\u8c22\u8c22
\u795d\u5b66\u4e60\u8fdb\u6b65\uff01
(x-1)²-(3-2x)²=0
[(x-1)+(3-2x)][(x-1)-(3-2x)]=0
(2-x)(3x-4)=0
(x-2)(3x-4)=0
x1=2，x2=4/3
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答：
(x-1)^2=(3-2x)^2
x^2-2x+1=9-12x+4x^2
3x^2-10x+8=0
(3x-4)(x-2)=0
x1=4/3
x2=2
（x-1）²=（3-2x）²
（x-1）²-（3-2x）²=0
（x-1-3+2x）（x-1+3-2x）=0
（3x-4）（-x+2）=0
所以x=4/3或x=2
解：（X-1）²-（2X-3）²=0
（X-1+2X-3）（X-1-2X+3）=0
3X-4=0或-X+2=0
X=4/3或X=2
x^2-2x+1=9-12x+4x^2
3x^2-10x+8=0
(3x-4)(x-2)=0
x=4/3或者x=2
希望可以帮到你，满意请采纳
两边打开x²－2x＋1=4x²－12x 9，左边移动到右边：3x²－10x＋8=0
十字相乘
1 -2
3 -4
得(x－2)(3x－4)=0
解得x=2或x=4/3
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