C语言。输入两个整数，求出它们的和，并判断它们的和是不是偶数，如果是偶数则输出y，否则输出n？ C语言编程 用户输入两个整数，求两个整数之间偶数的和？
\u7f16\u5199\u7a0b\u5e8f,\u8f93\u5165\u4e24\u4e2a\u6574\u6570\u6c42\u51fa\u5b83\u4eec\u7684\u548c,\u5e76\u5224\u65ad\u5b83\u4eec\u7684\u548c\u662f\u4e0d\u662f\u5076\u6570,\u5982\u679c\u662f\u5076\u6570\u5219\uff1f
#include
int main()
{ int a,b,c;
scanf("%d%d",&a,&b);
c=a+b;
printf("%d\u662f%s\u6570\n",c,c%2?"\u5947":"\u5076");
return 0;
}
#include
int main()
{
int a,b,sum=0;
int i;
printf("\u8bf7\u8f93\u5165\u6574\u6570\u533a\u95f4\uff1aa,b\n");
scanf("%d,%d",&a,&b);
for(i=a;i<=b;i++)
{
if(i%2==0)
{
sum+=i;
}
}
printf("%d\u548c%d\u4e4b\u95f4\u6240\u6709\u5076\u6570\u7684\u548c\u4e3a%d\n",a,b,sum);
return 0;
}
程序如下：
main(){
int a,b,c;
scanf("%d%d",&a,&b);
c=a+b;
printf("%d+%d=%d\n",a,b,c);
if(c%2)printf("n\n");
else printf("y\n");
}
有什么问题请留言。
先定义两个整数，
int a,b;
scanf来等待获取数字，屏幕输入
输出printf a+b;
判断是不是偶数，用(a+b)/2是不是有余数，(a+b)%2
学习程序主要是逻辑思维，代码不是特别重要
这个问题的答案很简单，直接相加对2取余数就可以了，根据结果进行输出！谢谢，望采纳！
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