求解答过程：实验室中浓硫酸的商标
\u6025\uff01\uff08\u6c42\u8fc7\u7a0b\uff09\u5b9e\u9a8c\u5ba4\u6709\u4e00\u74f6\u6d53\u786b\u9178\u74f6\u4e0a\u6807\u7b7e\u5185\u5bb9\u5982\u56fe\u6240\u793a\uff0c\u8bf7\u8ba1\u7b97\u5e76\u56de\u7b54\u4e0b\u5217\u95ee\u9898\uff1a(1) \u8bbe50mL\u8be5\u6eb6\u6db2\u53ef\u914d\u6210\u7684\u7a00\u786b\u9178x\u514b
50*1.8*90%=x*20%
\u89e3\u5f97x=405 (g)
(2) \u2460\u6d89\u53ca\u5230\u7684\u5316\u5b66\u65b9\u7a0b\u5f0f\u4e3a\uff1a Fe+H2SO4=FeSO4+H2\u2191
56 98 152 2
y Z 30.4 x
\u2461\u5229\u7528\u5df2\u77e5\u6761\u4ef6\u6c42\u89e3\u751f\u6210\u6c22\u6c14\u8d28\u91cf\uff08X\uff09 \u7684\u6bd4\u4f8b\u5f0f\u4e3a\uff1a152:2=30.4:x
\u2462\u5408\u91d1\u4e2d\u94c1\u7684\u542b\u91cf\u662f\uff1a\u8bbe\u94c1\u6709y\u514b
\u521956:152=y:30.4 \u5f97y=11.2(\u514b)
\u94c1\u542b\u91cf=11.2/(11.2+8.8)*100%=56%
\u2463\u8bbe\u6d88\u8017H2SO4 z\u514b
\u521998:152=z:30.4 \u5f97z=19.6\u514b
20%\u7684\u6eb6\u6db2\u514b\u6570=19.6/20%=98(\u514b)
\u53cd\u5e94\u540e\u7684\u6ee4\u6db2\u84b8\u53d18.8g\u6c34\uff08\u65e0\u6676\u4f53\u6790\u51fa\uff09\u540e\uff0c\u6240\u5f97\u6eb6\u6db2=(98-19.6)+30.4-8.8=100(\u514b)
\u6240\u5f97\u6eb6\u6db2\u7684\u6eb6\u8d28\u8d28\u91cf\u5206\u6570=30.4/100*100%=30.4%
1.920*98%=901.6\u514b
2.920g/500ml=1.84g/ml=1.84*10^3\u5343\u514b/\u7acb\u65b9\u7c73
3.
\u53d6\u51fa300\u514b\uff0c\u91cc\u9762\u542b\u6eb6\u8d28\u786b\u9178300*98%=294\u514b
\u4e8e\u662f\u6df7\u5408\u540e\u7a00\u786b\u9178\u7684\u8d28\u91cf\u5206\u6570\u4e3a
=\u6eb6\u8d28/\u6eb6\u6db2=294/(300+700)=29.4%
| （1）920 （2）20g （3）0.2g |
绛旓細鍥炵瓟锛(1)920 (2)20g (3)0.2g
绛旓細2銆傚鏋瀹為獙瀹鏈10ML\20ML\50ML鐨勯噺绛掞紝閫20mL鏈濂 3.灏嗛噺鍙栫殑娴揌2SO4娌跨儳鏉唴澹佹參鎱㈡敞鍏ユ湁绾100ML姘寸殑鐑ф澂閲岋紝骞朵笉鏂悈鎷岋紝鐩殑鏄姞閫熸憾瑙ｏ紝骞朵娇纭吀婧朵簬姘存墍鏀惧嚭鐨勭儹閲忔墿鏁ｅ潎鍖锛岄槻姝㈠眬閮ㄨ繃鐑紝娑蹭綋娌歌吘銆4.灏嗗喎鍗磋嚦瀹ゆ俯鐨勪笂杩版憾娑叉部鐜荤拑妫掓敞鍏500mL鐨勫閲忕摱涓紝骞剁敤50ML钂搁姘存礂娑ょ儳鏉2~3娆★紝...
绛旓細C
绛旓細闇瑕纭吀涓烘祿搴*浣撶Н 0.5*0.5*0.98=24.5g v=m/p=锛24.5/0.98锛/1.84=13.59ml
绛旓細鍥炵瓟锛(1)鐜荤拑妫;閲忕瓛 (2)娴撶～閰 (3)閰告恫椋炴簠 銆愯仈绯讳笌鎷撳睍銆戣厫铓鎬;瀛樻斁鏃惰璐村ソ鏍囩,鏀惧湪瀹夊叏鍦版柟(鎴栦娇鐢ㄦ椂瑕佹牳瀵规爣绛)(鍚堢悊绛旀鍧囧彲)
绛旓細50姣崌娴撶～閰哥殑璐ㄩ噺 50mL*1.84g/mL=92g 鍏朵腑鍚憾璐ㄨ川閲92g*98%=90.16g 浠栧皢杩50姣崌娴撶～閰镐笌200鍏嬫按鍧囧寑娣峰悎锛屾墍寰楃█纭吀鐨勮川閲忓垎鏁 90.16g/(200g+92g)*100%=30.9 鑻瀹為獙瀹瑕侀厤鍒630鍏嬫憾璐ㄨ川閲忓垎鏁28锛呯殑绋纭吀锛屽垯闇瑕佽繖鐡舵憾璐ㄨ川閲忓垎鏁颁负98锛呯殑娴撶～閰 630g*28%=x*98 x=180g ...
绛旓細锛1锛夎鎵闇娴撶～閰哥殑璐ㄩ噺涓簓锛2NaOH+H2SO4=Na2SO4+2H2O80 9880g 98%x鈭8098=80g98%y瑙ｄ箣寰楋細y=100g锛庢晠绛旀涓猴細100g锛庯紙2锛夆憼M鍜岀～閰稿弽搴旂殑鏂圭▼寮忎负锛歁+H2SO4=MSO4+H2鈫戯紟鈶¤鍙嶅簲鐢熸垚姘㈡皵璐ㄩ噺涓簒锛孧鐨勭浉瀵瑰師瀛愯川閲忎负z锛孧+H2SO4=MSO4+H2鈫憐 98 210g-7.6g 98g脳...
绛旓細1.500*19.6%=98%x x=100g(98%H2SO4)浣撶Н=100g/1.84g/l=54L 姘寸殑璐ㄩ噺=500-100=400g 2.40%x=20%*500g x=250g(40%姘㈡哀鍖栭挔)500-250=250g(姘).
绛旓細5.鐢20ml宸﹀彸鐨勮捀棣忔按娲楁钉鐑ф澂鍜岀幓鐠冩鍚庡湪杞叆瀹归噺鐡躲6.鐢ㄥ惛绠″惛鍙栬捀棣忔按锛屼粩缁嗘淮鍔犳憾娑插埌瀹归噺鐡跺埢搴︾嚎锛屽姞涓婄摱濉炪7.灏嗗閲忕摱濉炲瓙濉炵揣锛屽彸鎵嬮鎸囨寜浣忓瀛愶紝鍙虫墜鎻′綇鐡堕宸︽墜鎷栦綇鐡跺簳銆傚皢瀹归噺鐡朵笂涓嬮鍊3娆°8.鍦ㄦ爣绛剧焊涓2N纭吀鍜岄厤缃棩鏈燂紝鎾曞紑璐村湪瀹归噺鐡朵笂锛岃创瀹炪
绛旓細1銆侀噺娑诧細鐢5mL 閲忕瓛閲忓彇2.7mL98%鐨娴撶～閰 2銆佺█閲婏細閫変竴閫傚綋澶у皬鐨勬磥鍑鐑ф澂锛屽厛鍔犲叆绾20mL 钂搁姘(绾﹂厤鍒舵讳綋绉殑1/5)锛岀劧鍚庢妸閲忓ソ鐨勬祿纭吀缂撶紦鍊掑叆姘翠腑锛岃竟鍊 杈规悈鎷屻傚喎鍗磋嚦瀹ゆ俯銆3銆佺Щ娑诧細灏嗛厤鍒跺ソ鐨勬祿纭吀娌跨幓鐠冩灏忓績鍊掑叆瀹归噺鐡朵腑锛屾礂娑ょ儳鏉拰鐜荤拑妫 2-3 娆(姣忔绾︾敤 15mL 钂搁姘)锛...
