有一个不多于5位的正整数，求出它是几位数，分别顺序打印出它的每一位数字，再逆序打印出它的每一位数字 //给定一个不多于5位的正整数，要求：① 求它是几位数；② ...
c\u8bed\u8a00 \u6709\u4e00\u4e2a\u4e0d\u591a\u4e8e5\u4f4d\u7684\u6b63\u6574\u6570\uff0c\u6c42\u51fa\u5b83\u662f\u51e0\u4f4d\u6570\uff0c\u5206\u522b\u987a\u5e8f\u51fa\u5b83\u7684\u6bcf\u4e00\u4f4d\u6570\u5b57\uff0c\u518d\u9006\u5e8f\u51fa\u5b83\u7684\u6bcf\u4e00\u4f4d\u6570\u5b57#include //\u671b\u91c7\u7eb3!^_^
int main(void)
{
int n;
int count=0,i,a[5];
printf ("\u8bf7\u8f93\u5165\u4e00\u4e2a\u6570(\u5927\u4e8e0\u4e14\u5c0f\u4e8e100000):");
if(scanf("%d",&n)!=1)
{
printf("\u8f93\u5165\u4e0d\u5408\u6cd5!\n");
return 0;
}
if (n=100000)
{
printf ("\u4f60\u8f93\u5165\u7684\u6570\u4e0d\u5408\u6cd5,\u8bf7\u8f93\u5165\u4e00\u4e2a\u5927\u4e8e0\u4e14\u5c0f\u4e8e100000\u7684\u6570!\n");
return 0;
}
while(1)
{
a[count]=n%10;
n=n/10;
if(n==0)
{
break;
}
count++;
}
printf("%d\n",count+1);
for (i=count;i>=0;i--)
{
printf("%d",a[i]);
}
printf("\n");
for (i=0;i<=count;i++)
{
printf("%d",a[i]);
}
printf("\n");
return 0;
}
\u4e0b\u9762\u5df2\u7ecf\u6539\u597d\u4e86\uff1a
#include
int main(){
int a[5];
int n,quotient,count=0,i=0;
printf("\u8f93\u5165\u4e00\u4e2a\u4e0d\u591a\u4e8e\u4e94\u4f4d\u6570\u7684\u6574\u6570\n");
scanf("%d",&n);
quotient=n;
while(quotient>0){ //\u5faa\u73af\u8bed\u53e5\u6539\u4e86
a[i]=quotient%10;
quotient/=10;
count++;
i++;
} //\u540e\u9762\u5220\u4e862\u53e5
for(i=count-1;i>=0;i--){
printf("%d,",a[i]);
}
printf("\n");
for(i=0;i<count;i++){
printf("%d,",a[i]);
}
printf("\n");
}\u001a
#include <stdio.h>
int main(void)
{
int n;
int count=0,i,a[5];
printf ("输入一个不多于5位正整数(0~99999):
");
scanf("%d",&n);
if (n<=0 || n>=100000)
{
printf ("输入的数不合法
");
}
else
{
while(1)
{
a[count]=n%10;
n=n/10;
if(n==0)
{
break;
}
count++;
}
printf("位数：%d
正序：",count+1);
for (i=count;i>=0;i--)
{
printf("%d ",a[i]);
}
printf("
倒序：");
for (i=0;i<=count;i++)
{
printf("%d ",a[i]);
}
printf("
");
}
return 0;
}
#include <stdio.h>
int main()
{
int n ,a,i;
int s = 0;
i = 0;
scanf("%d",&n);
a = n;
while(a!=0)
{
i ++;
s = s*10+a%10;
a = a/10;
}
printf("%d是%d位数
",n,i);
printf("各数数字是:");
a = s;
while(a!=0)
{
printf("%d ",a%10);
a = a/10;
}
printf("
逆序为:");
a = n;
while(a!=0)
{
printf("%d ",a%10);
a = a/10;
}
printf("
");
return 0;
}
#include <stdio.h>
int main()
{
int n,i;
scanf("%d",&n);
for(i=1;n/10!=0;i++)
{
printf("%d ",n%10);
n=n/10;
}
if(n/10==0)
printf("%d\n",n);
printf("%d\n",i);
return 0;
}
希望可以！
不免
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