(x-2)²=4(x-2)用因式分解法算.

\u7528\u56e0\u5f0f\u5206\u89e3\u89e3\u65b9\u7a0b 9\uff08x-2\uff09²=4\uff08x+1\uff09²


x-4=(x-4)²
(x-4)² - (x-4) = 0
(x-4)(x-4-1) = 0
(x-4)(x-5) = 0
x=4 \u6216 x=5

\uff085x-1)(2x+4)=3x+6
\uff085x-1)(2x+4) - (3x+6) = 0
2(5x-1)(x+2) - 3(x+2) = 0
(x+2) { 2(5x-1) - 3} = 0
(x+2)(10x-5) =0
(x+2)(2x-1) = 0
x=-2 \u6216 x=1/2

x²-3x-18=0
(x-6)(x+3) = 0
x=6 \u6216 x=-3

2y²-5y+2=0
(2y-1)(y-2) = 0
y=1/2 \u6216 x=2

x²+5=2\uff08\u6839\u53f75\uff09x
x² - 2\u221a5x + 5 = 0
(x-\u221a5)² = 0
x = \u221a5 \u91cd\u6839

(3x+2)²-4x²=0
(3x+2+2x)(3x+2-2x) = 0
(5x+2)(x+2) = 0
x=-2/5 \u6216 x=-2

2x²-mx=15m
2x²-mx-15m = 0
(x-3m)(2x+5m) = 0
x=3m \u6216 x=-2.5m




(x-2)²=4(x-2)·
x²-4x+4=4x-8
x²-8x+12=0
(x-6)(x-2)=0
x1=6 x2=2

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