x的平方等于2x(x减1)用因式分解解元二次方程
3(4X\u4e8c\u6b21\uff0d9)-2(2X-3)=0\u7528\u56e0\u5f0f\u5206\u89e3\u6cd5\u89e3\u89e3\uff1a3(2x+3)(2x-3) - 2(2x-3)=0
(2x-3)[3(2x+3) - 2]=0
(2x-3)(6x+9-2)=0
(2x-3)(6x+7)=0
x=3/2\u6216x=-7/6
x²=2x²-2x
x²-2x=0
x(x-2)=0
x₁=0;x₂=2
绛旓細x²-2x-1=0锛寈²-2x+1=2锛锛坸-1锛²=2锛寈1=鈭2+1锛寈2=-鈭2+1
绛旓細鐢ㄢ骞虫柟宸叕寮忓垎瑙ｅ洜寮忔硶鈥濊В璇ヤ竴鍏冧簩娆℃柟绋嬶細x^2锛(2x-3)^2 瑙ｏ細x^2-(2x-3)^2锛0 [x+(2x-3)][x-(2x-3)]锛0 (x+2x-3)(x-2x+3)锛0 (3x-3)(-x+3)锛0 3x-3锛0鎴-x+3锛0 鎵浠ワ紝x1锛1锛寈2锛3銆
绛旓細x=-5/2銆傝缁嗚绠楁楠 姝ら楠岀畻杩囩▼濡備笅锛氬乏杈=(x+1)/2-(x+2)/6=(-5/2+1)/2-(-5/2+2)/6=-3/4+1/12=-2/3;鍙宠竟=1+2x/3=1-5/3=-2/3;宸﹁竟=鍙宠竟锛屽嵆x=-5/2鏄柟绋嬬殑瑙ｃ傜煡璇嗘嫇灞:涓鍏冧竴娆℃柟绋嬫寚鍙惈鏈変竴涓湭鐭ユ暟銆佹湭鐭ユ暟鐨勬渶楂樻鏁颁负1涓斾袱杈归兘涓烘暣寮忕殑绛夊紡銆備竴鍏冧竴娆...
绛旓細(2x-1)²-(3-x)²=0 (2x-1+3-x)(2x-1-3+x)=0 (x+2)(3x-4)=0 x+2=0鎴3x-4=0 x1=-2锛寈2=4/3
绛旓細鏂圭▼x^2+2x-1=0鐨勮В涓簒1=-1+鈭2锛寈2=-1-鈭2銆傝В锛歺^2+2x-1=0 鍥犱负鈻=b^2-4ac=2^2-4x1x(-1)=8锛0锛岄偅涔堟柟绋媥^2+2x-1=0鏈変袱涓笉鐩哥瓑鐨勫疄鏁版牴銆傛牴鎹眰鏍瑰叕寮忓彲寰楋紝x=(-b卤鈭(b^2-4ac))/(2a)x=(-2卤鈭8)/2=-1卤鈭2 鍒檟1=-1+鈭2锛寈2=-1-鈭2 鍗虫柟绋媥^2+...
绛旓細褰搙>1 鏃讹紝浜屾鍑芥暟y=x骞虫柟-2x鐨涔嬮殢鐫x鐨勫澶ц屽澶с傚洜涓簓'=2(x-1)=0,y''=2>0琛ㄧずy鍦▁=1鏃舵湁鏋佸皬鍊硷紝浜屾鍑芥暟y=x骞虫柟-2x鏇茬嚎鐨勫紑鍙ｅ悜涓婄殑銆
绛旓細绛夊彿鍙宠竟娌″啓娓呮鍚с傚鐢ㄧ敤鎷彿銆傦紙鎷彿鍝鏄閮界敤灏忔嫭鍙凤紝涔熻锛夛級锛夎鐪熸槸浣犻鐩殑鏍峰瓙锛岄偅涔堝氨鍏堟妸鍙宠竟鐢ㄥ叕寮忓睍寮銆傚緱鍒帮細鍙宠竟=x²锛(x锛1)²锛2x(x锛1).涓涓嬪瓙涓庡乏杈规秷鍘讳簡涓ら」銆傛柟绋嬪彉涓猴紙x-2锛²+锛坸 -3锛²锛2x(x锛1).灞曞紑锛屽緱鍒帮細锛4x锛4锛6x锛9锛...
绛旓細2x^2-x = 1 2x^2-x-1 = 0 (2x+1)(x-1) = 0 涓や釜鏁扮殑涔樼Н绛変簬0鐨勮瘽锛屽彧闇瑕佸叾涓竴涓暟鐨勭瓑浜0灏鏄浜嗐2x+1 = 0 鎴 x-1 = 0 瑙ｅ緱锛歺= -1/2 鎴 x =1
绛旓細x^2-x=2 x^-x-2=0 (x-2)(x+1)=0 鎵浠-2=0 鎴杧+1=0 x=2鎴杧=-1
绛旓細(2x-1)^2=(3-x)^2 (2x-1)^2 - (3-x)^2=0 (2x-1+3-x)(2x-1-3+x)=0 (x+2)(3x-4)=0 x+2=0鎴3x-4=0 瑙ｅ緱x=-2鎴杧=4/3 濡傝繕涓嶆槑鐧斤紝璇风户缁拷闂傚鏋滀綘璁ゅ彲鎴戠殑鍥炵瓟锛岃鍙婃椂鐐瑰嚮銆愰噰绾充负婊℃剰鍥炵瓟銆戞寜閽 鎵嬫満鎻愰棶鐨勬湅鍙嬪湪瀹㈡埛绔彸涓婅璇勪环鐐广愭弧鎰忋戝嵆鍙
