混合气体中某一气体质量分数计算公式是什么 由混合气体各组分的质量分数，怎么计算体积分数？非标况，有温度...
\u6df7\u5408\u6c14\u4f53\u7684\u8d28\u91cf\u5206\u6570\u600e\u4e48\u6c42\uff1f\u9996\u5148\u5e94\u8be5\u8ba1\u7b97\u51fa\u6c14\u4f53\u4e4b\u95f4\u7684\u7269\u8d28\u7684\u91cf\u4e4b\u6bd4\u3002\u7136\u540e\u8ba1\u7b97\u51fa\u5176\u4e2d\u4e00\u79cd\u6c14\u4f53\u7684\u8d28\u91cf\u6bd4\u4e0a\u6df7\u5408\u6c14\u4f53\u7684\u8d28\u91cf\u3002\u4f8b\u5982\u4e00\u6c27\u5316\u78b322.4\u5347\u4e0e\u4e8c\u6c27\u5316\u78b344.8\u5347\u6df7\u5408\uff0c\u6c42\u4e00\u6c27\u5316\u78b3\u7684\u8d28\u91cf\u5206\u6570
\u4e8c\u8005\u7684\u7269\u8d28\u7684\u91cf\u4e4b\u6bd4\u662f22.4/44.8=1/2
\u4e00\u6c27\u5316\u78b3\u7684\u8d28\u91cf\u5206\u6570\u662f1\u00d728/\uff081\u00d728+2\u00d744\uff09=24.14%
\u540c\u6e29\u540c\u538b\u4e0b\u3002\u7269\u8d28\u7684\u91cf\u4e4b\u6bd4\u7b49\u4e8e\u4f53\u79ef\u6bd4
\u6240\u4ee5\u5c06\u8d28\u91cf\u5206\u6570\u76f4\u63a5\u9664\u4ee5\u8be5\u7269\u8d28\u7684\u6469\u5c14\u8d28\u91cf\u5373\u5f97\u4f53\u79ef\u6bd4
\u6c2e\u6c14\u7684\u4f53\u79ef\u4e3a\uff1a0.84/28=0.03
\u4e8c\u6c27\u5316\u78b3\uff1a0.084/44=0.002
\u6c27\u6c14\uff1a0.063/32=0.002
\u6c34\u84b8\u6c14\uff1a0.011/18=0.0006
\u603b\u4f53\u79ef\u4e3a\uff1a0.0346
\u6c2e\u6c14\u4f53\u79ef\u5206\u6570\uff1a0.03/0.0346=86.7%
\u4e8c\u6c27\u5316\u78b3\u4f53\u79ef\u5206\u6570\uff1a0.002/0.0346=5.8%
\u6c27\u6c14\u4f53\u79ef\u5206\u6570 \uff1a0.002/0.0346=5.8%
\u6c34\u84b8\u6c14\u4f53\u79ef\u5206\u6570\uff1a0.0006/0.0346=1.7%
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绛旓細闂綘鍚屽锛屼粬浠簲璇ヤ細
绛旓細棣栧厛搴旇璁＄畻鍑烘皵浣撲箣闂寸殑鐗╄川鐨勯噺涔嬫瘮銆傜劧鍚庤绠楀嚭鍏朵腑涓绉嶆皵浣撶殑璐ㄩ噺姣斾笂娣峰悎姘斾綋鐨勮川閲銆備緥濡備竴姘у寲纰22.4鍗囦笌浜屾哀鍖栫⒊44.8鍗囨贩鍚堬紝姹備竴姘у寲纰崇殑璐ㄩ噺鍒嗘暟 浜岃呯殑鐗╄川鐨勯噺涔嬫瘮鏄22.4/44.8=1/2 涓姘у寲纰崇殑璐ㄩ噺鍒嗘暟鏄1脳28/锛1脳28+2脳44锛=24.14 ...
绛旓細璐ㄩ噺鍒嗘暟NH3 = (NH3鐨勮川閲) / (娣峰悎姘斾綋鐨勬昏川閲) = 17g / m 鍏舵锛屾垜浠渶瑕佹眰鍑烘贩鍚堟皵浣撲腑CO2鍜孨H3鐨勬懇灏斿垎鏁般備负浜嗚绠楁懇灏斿垎鏁帮紝鎴戜滑闇瑕佸厛姹傚嚭娣峰悎姘斾綋涓瑿O2鍜孨H3鐨勬懇灏旇川閲忋傚亣璁炬贩鍚堟皵浣撲腑CO2鐨勬懇灏旇川閲忎负M1锛孨H3鐨勬懇灏旇川閲忎负M2锛屽垯鏈夛細M1 = (CO2鐨勮川閲) / (CO2鐨勬懇灏旇川閲) = 44g /...
绛旓細璐ㄩ噺鍒嗘暟=璇ユ皵浣撹川閲/娣峰悎姘斾綋鎬昏川閲 鎽╁皵缁勫垎=璇ユ皵浣撶墿璐ㄧ殑閲/娣峰悎姘斾綋鎬荤墿璐ㄧ殑閲 鐗╄川鐨勯噺鍙堢О鎽╁皵鏁帮紝鍗曚綅mol 鎽╁皵璐ㄩ噺鍙堢О鐩稿鍒嗗瓙璐ㄩ噺 鍗曚綅g/mol 姣斿H2O鐨勬懇灏旇川閲忎负18
绛旓細浣撶Н鍒嗘暟鐨勮绠楀叕寮:浣撶Н鍒嗘暟=娣峰悎姘斾綋涓煇鐗╄川鐨勪綋绉/娣峰悎姘斾綋鐨勪綋绉*100%璐ㄩ噺鍒嗘暟鍏紡鏄绠楄川閲忓垎鏁扮殑鍏紡锛岃川閲忓垎鏁版槸鎸囨煇鐗╄川涓煇绉嶆垚鍒嗙殑璐ㄩ噺涓庤鏍峰搧涓荤墿璐ㄨ川閲忎箣姣旂殑鐧惧垎鏁帮紝濡傚湪婧舵恫涓憾璐ㄨ川閲忎笌婧舵恫璐ㄩ噺涔嬫瘮鐨勬憾璐ㄨ川閲忓垎鏁般佸湪娣峰悎鐗╀腑鏌愮鎴愬垎鐨勮川閲忓垎鏁般佸湪鍖栧寮忎腑鏌愮鍏冪礌鐨勮川閲忓垎鏁扮瓑銆
绛旓細瑙ｏ細璁娣峰悎姘斾綋鐨勮川閲涓100m 姘ф皵鐨勭墿璐ㄧ殑閲弉(O2)=100m*32%/32g/mol=m mol 姘皵鐨勭墿璐ㄧ殑閲弉(N2)=100m*28%/28g/mol=m mol 浜屾哀鍖栫⒊鐨勭墿璐ㄧ殑閲弉(CO2)=100m*22%/44g/mol=0.5m mol 鐢茬兎鐨勭墿璐ㄧ殑閲弉(CH4)=100m*16%/16g/mol=m mol 姘㈡皵鐨勭墿璐ㄧ殑閲弉(H2)=100m*2%/2g/mol=m mol...
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绛旓細鍋囪鏈100鍏嬫皵浣擄紝鍒欐皵浣撶殑鎬荤墿璐ㄧ殑閲忎负锛32/32+28/28+22/44+16/16+2/2=4.5mol 鍒娣峰悎姘斾綋鐨鎽╁皵璐ㄩ噺锛100/4.5g/mol 娣峰悎姘斾綋瀵规阿姘旂殑鐩稿瀵嗗害涓猴細100/(4.5*2)=100/9=11.11 B 鏄鐨勩
绛旓細璐ㄩ噺鍒嗘暟=娣峰悎鐗╀腑鏌愮墿璐ㄧ殑璐ㄩ噺/娣峰悎鐗╃殑璐ㄩ噺*100 鐗╄川鐨勯噺鍒嗘暟=娣峰悎鐗╀腑鏌愮墿璐ㄧ殑鐗╄川鐨勯噺/娣峰悎鐗╃殑鐗╄川鐨勯噺*100 浣撶Н鍒嗘暟=娣峰悎姘斾綋涓煇鐗╄川鐨勪綋绉/娣峰悎姘斾綋鐨勪綋绉*100
