为什么1-cosx=o(sinx)(x趋于0)

\u5f53x\u8d8b\u5411\u4e8e0\u65f6\uff0cx/sinx * (1+cosx)/cosx \u7684\u6781\u9650\u600e\u4e48\u6c42\uff1f\u6025\uff01

\u5f53 x \u2192 0 \u65f6\uff0c
lim x/sinx * (1+cosx)/cosx
= lim x/sinx * lim[(1+cosx)/cosx]
= 1 * (2 / 1)
= 2

\u89e3\u7b54\u89c1\u56fe\uff1a


1-cosx=2sin平方(x/2)
lim (x-->0) 2sin平方(x/2)/sinx
=lim (x-->0) x平方/(2x)
=0

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