几道关于因式分解的题目，求帮忙
\u51e0\u9053\u56e0\u5f0f\u5206\u89e3\u7684\u9898\u76ee(a-b)3+(a+b)3-8a3
=2a^3+6ab^2-8a^3
=6ab^2-6a^3
=6a(b^2-a^2)
=6a(b+a)(b-a)
(x+y+z)3+(3x-2y-3z)3-(4x-y-2z)3
=(4x-y-2z)[(x+y+z)^2-2(x+y+z)(3x-2y-3z)+(3x-2y-3z)^2]-(4x-y-2z)3
=(4x-y-2z)[(x+y+z)^2-2(x+y+z)(3x-2y-3z)+(3x-2y-3z)^2-(4x-y-2z)^2]
=(4x-y-2z)[(x+y+z)((x+y+z)-(3x-2y-3z))+((3x-2y-3z)-(4x-y-2z))((3x-2y-3z)+(4x-y-2z))]
=(4x-y-2z)[(x+y+z)(-2x+3y+4z)+(-x-y-z)(7x-3y-5z)]
=(4x-y-2z)(x+y+z)[(-2x+3y+4z)-(7x-3y-5z)]
=(4x-y-2z)(x+y+z)(-9x+6y+9z)
=3(4x-y-2z)(x+y+z)(-3x+2y+3z)
a4+b4+c4-2a2b2-2b2c2-2c2a2
=(a^2-b^2-c^2)^2-4b^2c^2
=(a^2-b^2-c^2+2bc)(a^2-b^2-c^2-2bc)
=(a^2-(b-c)^2)(a^2-(b+c)^2)
=(a+b-c)(a-b+c)(a+b+c)(a-b-c)
1.x^2+2x-8
2.x^2+3x-10
3.x^2-x-20
4.x^2+x-6
5.2x^2+5x-3
6.6x^2+4x-2
7.x^2-2x-3
8.x^2+6x+8
9.x^2-x-12
10.x^2-7x+10
11.6x^2+x+2
12.4x^2+4x-3
\u89e3\u65b9\u7a0b\uff1a\uff08x\u7684\u5e73\u65b9+5x-6\uff09\u5206\u4e4b\u4e00=\uff08x\u7684\u5e73\u65b9+x+6\uff09\u5206\u4e4b\u4e00
\u5341\u5b57\u76f8\u4e58\u6cd5\u867d\u7136\u6bd4\u8f83\u96be\u5b66,\u4f46\u662f\u4e00\u65e6\u5b66\u4f1a\u4e86\u5b83,\u7528\u5b83\u6765\u89e3\u9898,\u4f1a\u7ed9\u6211\u4eec\u5e26\u6765\u5f88\u591a\u65b9\u4fbf,\u4ee5\u4e0b\u662f\u6211\u5bf9\u5341\u5b57\u76f8\u4e58\u6cd5\u63d0\u51fa\u7684\u4e00\u4e9b\u4e2a\u4eba\u89c1\u89e3\u3002
1\u3001\u5341\u5b57\u76f8\u4e58\u6cd5\u7684\u65b9\u6cd5\uff1a\u5341\u5b57\u5de6\u8fb9\u76f8\u4e58\u7b49\u4e8e\u4e8c\u6b21\u9879\u7cfb\u6570\uff0c\u53f3\u8fb9\u76f8\u4e58\u7b49\u4e8e\u5e38\u6570\u9879\uff0c\u4ea4\u53c9\u76f8\u4e58\u518d\u76f8\u52a0\u7b49\u4e8e\u4e00\u6b21\u9879\u7cfb\u6570\u3002
2\u3001\u5341\u5b57\u76f8\u4e58\u6cd5\u7684\u7528\u5904\uff1a\uff081\uff09\u7528\u5341\u5b57\u76f8\u4e58\u6cd5\u6765\u5206\u89e3\u56e0\u5f0f\u3002\uff082\uff09\u7528\u5341\u5b57\u76f8\u4e58\u6cd5\u6765\u89e3\u4e00\u5143\u4e8c\u6b21\u65b9\u7a0b\u3002
3\u3001\u5341\u5b57\u76f8\u4e58\u6cd5\u7684\u4f18\u70b9\uff1a\u7528\u5341\u5b57\u76f8\u4e58\u6cd5\u6765\u89e3\u9898\u7684\u901f\u5ea6\u6bd4\u8f83\u5feb\uff0c\u80fd\u591f\u8282\u7ea6\u65f6\u95f4\uff0c\u800c\u4e14\u8fd0\u7528\u7b97\u91cf\u4e0d\u5927\uff0c\u4e0d\u5bb9\u6613\u51fa\u9519\u3002
4\u3001\u5341\u5b57\u76f8\u4e58\u6cd5\u7684\u7f3a\u9677\uff1a1\u3001\u6709\u4e9b\u9898\u76ee\u7528\u5341\u5b57\u76f8\u4e58\u6cd5\u6765\u89e3\u6bd4\u8f83\u7b80\u5355\uff0c\u4f46\u5e76\u4e0d\u662f\u6bcf\u4e00\u9053\u9898\u7528\u5341\u5b57\u76f8\u4e58\u6cd5\u6765\u89e3\u90fd\u7b80\u5355\u30022\u3001\u5341\u5b57\u76f8\u4e58\u6cd5\u53ea\u9002\u7528\u4e8e\u4e8c\u6b21\u4e09\u9879\u5f0f\u7c7b\u578b\u7684\u9898\u76ee\u30023\u3001\u5341\u5b57\u76f8\u4e58\u6cd5\u6bd4\u8f83\u96be\u5b66\u3002
5\u3001\u5341\u5b57\u76f8\u4e58\u6cd5\u89e3\u9898\u5b9e\u4f8b\uff1a
1)\u3001 \u7528\u5341\u5b57\u76f8\u4e58\u6cd5\u89e3\u4e00\u4e9b\u7b80\u5355\u5e38\u89c1\u7684\u9898\u76ee
\u4f8b1\u628am²+4m-12\u5206\u89e3\u56e0\u5f0f
\u5206\u6790\uff1a\u672c\u9898\u4e2d\u5e38\u6570\u9879-12\u53ef\u4ee5\u5206\u4e3a-1\u00d712\uff0c-2\u00d76\uff0c-3\u00d74\uff0c-4\u00d73\uff0c-6\u00d72\uff0c-12\u00d71\u5f53-12\u5206\u6210-2\u00d76\u65f6\uff0c\u624d\u7b26\u5408\u672c\u9898
\u89e3\uff1a\u56e0\u4e3a 1 -2
1 \u2573 6
\u6240\u4ee5m²+4m-12=\uff08m-2\uff09\uff08m+6\uff09
\u4f8b2\u628a5x²+6x-8\u5206\u89e3\u56e0\u5f0f
\u5206\u6790\uff1a\u672c\u9898\u4e2d\u76845\u53ef\u5206\u4e3a1\u00d75,-8\u53ef\u5206\u4e3a-1\u00d78\uff0c-2\u00d74\uff0c-4\u00d72\uff0c-8\u00d71\u3002\u5f53\u4e8c\u6b21\u9879\u7cfb\u6570\u5206\u4e3a1\u00d75\uff0c\u5e38\u6570\u9879\u5206\u4e3a-4\u00d72\u65f6\uff0c\u624d\u7b26\u5408\u672c\u9898
\u89e3\uff1a \u56e0\u4e3a 1 2
5 \u2573 -4
\u6240\u4ee55x²+6x-8=\uff08x+2\uff09\uff085x-4\uff09
\u4f8b3\u89e3\u65b9\u7a0bx²-8x+15=0
\u5206\u6790\uff1a\u628ax²-8x+15\u770b\u6210\u5173\u4e8ex\u7684\u4e00\u4e2a\u4e8c\u6b21\u4e09\u9879\u5f0f\uff0c\u521915\u53ef\u5206\u62101\u00d715\uff0c3\u00d75\u3002
\u89e3\uff1a \u56e0\u4e3a 1 -3
1 \u2573 -5
\u6240\u4ee5\u539f\u65b9\u7a0b\u53ef\u53d8\u5f62\uff08x-3\uff09\uff08x-5\uff09=0
\u6240\u4ee5x1=3 x2=5
\u4f8b4\u3001\u89e3\u65b9\u7a0b 6x²-5x-25=0
\u5206\u6790\uff1a\u628a6x²-5x-25\u770b\u6210\u4e00\u4e2a\u5173\u4e8ex\u7684\u4e8c\u6b21\u4e09\u9879\u5f0f\uff0c\u52196\u53ef\u4ee5\u5206\u4e3a1\u00d76\uff0c2\u00d73\uff0c-25\u53ef\u4ee5\u5206\u6210-1\u00d725\uff0c-5\u00d75\uff0c-25\u00d71\u3002
\u89e3\uff1a \u56e0\u4e3a 2 -5
3 \u2573 5
\u6240\u4ee5 \u539f\u65b9\u7a0b\u53ef\u53d8\u5f62\u6210\uff082x-5\uff09\uff083x+5\uff09=0
\u6240\u4ee5 x1=5/2 x2=-5/3
2)\u3001\u7528\u5341\u5b57\u76f8\u4e58\u6cd5\u89e3\u4e00\u4e9b\u6bd4\u8f83\u96be\u7684\u9898\u76ee
\u4f8b5\u628a14x²-67xy+18y²\u5206\u89e3\u56e0\u5f0f
\u5206\u6790\uff1a\u628a14x²-67xy+18y²\u770b\u6210\u662f\u4e00\u4e2a\u5173\u4e8ex\u7684\u4e8c\u6b21\u4e09\u9879\u5f0f,\u521914\u53ef\u5206\u4e3a1\u00d714,2\u00d77, 18y²\u53ef\u5206\u4e3ay.18y , 2y.9y , 3y.6y
\u89e3: \u56e0\u4e3a 2 -9y
7 \u2573 -2y
\u6240\u4ee5 14x²-67xy+18y²= (2x-9y)(7x-2y)
\u4f8b6 \u628a10x²-27xy-28y²-x+25y-3\u5206\u89e3\u56e0\u5f0f
\u5206\u6790\uff1a\u5728\u672c\u9898\u4e2d\uff0c\u8981\u628a\u8fd9\u4e2a\u591a\u9879\u5f0f\u6574\u7406\u6210\u4e8c\u6b21\u4e09\u9879\u5f0f\u7684\u5f62\u5f0f
\u89e3\u6cd5\u4e00\u300110x²-27xy-28y²-x+25y-3
=10x²-\uff0827y+1\uff09x -\uff0828y²-25y+3\uff09 4y -3
7y \u2573 -1
=10x²-\uff0827y+1\uff09x -\uff084y-3\uff09\uff087y -1\uff09
=[2x -\uff087y -1\uff09][5x +\uff084y -3\uff09] 2 -\uff087y \u2013 1\uff09
5 \u2573 4y - 3
=\uff082x -7y +1\uff09\uff085x +4y -3\uff09
\u8bf4\u660e\uff1a\u5728\u672c\u9898\u4e2d\u5148\u628a28y²-25y+3\u7528\u5341\u5b57\u76f8\u4e58\u6cd5\u5206\u89e3\u4e3a\uff084y-3\uff09\uff087y -1\uff09\uff0c\u518d\u7528\u5341\u5b57\u76f8\u4e58\u6cd5\u628a10x²-\uff0827y+1\uff09x -\uff084y-3\uff09\uff087y -1\uff09\u5206\u89e3\u4e3a[2x -\uff087y -1\uff09][5x +\uff084y -3\uff09]
\u89e3\u6cd5\u4e8c\u300110x²-27xy-28y²-x+25y-3
=\uff082x -7y\uff09\uff085x +4y\uff09-\uff08x -25y\uff09- 3 2 -7y
=[\uff082x -7y\uff09+1] [\uff085x -4y\uff09-3] 5 \u2573 4y
=\uff082x -7y+1\uff09\uff085x -4y -3\uff09 2 x -7y 1
5 x - 4y \u2573 -3
\u8bf4\u660e:\u5728\u672c\u9898\u4e2d\u5148\u628a10x²-27xy-28y²\u7528\u5341\u5b57\u76f8\u4e58\u6cd5\u5206\u89e3\u4e3a\uff082x -7y\uff09\uff085x +4y\uff09,\u518d\u628a\uff082x -7y\uff09\uff085x +4y\uff09-\uff08x -25y\uff09- 3\u7528\u5341\u5b57\u76f8\u4e58\u6cd5\u5206\u89e3\u4e3a[\uff082x -7y\uff09+1] [\uff085x -4y\uff09-3].
\u4f8b7\uff1a\u89e3\u5173\u4e8ex\u65b9\u7a0b\uff1ax²- 3ax + 2a²\u2013ab -b²=0
\u5206\u6790\uff1a2a²\u2013ab-b²\u53ef\u4ee5\u7528\u5341\u5b57\u76f8\u4e58\u6cd5\u8fdb\u884c\u56e0\u5f0f\u5206\u89e3
\u89e3\uff1ax²- 3ax + 2a²\u2013ab -b²=0
x²- 3ax +\uff082a²\u2013ab - b²\uff09=0
x²- 3ax +\uff082a+b\uff09\uff08a-b\uff09=0 1 -b
2 \u2573 +b
[x-\uff082a+b\uff09][ x-\uff08a-b\uff09]=0 1 -\uff082a+b\uff09
1 \u2573 -\uff08a-b\uff09
\u6240\u4ee5 x1=2a+b x2=a-b
5-7(a+1)-6(a+1)^2
=-[6(a+1)^2+7(a+1)-5]
=-[2(a+1)-1][3(a+1)+5]
=-(2a+1)(3a+8);
-4x^3 +6x^2 -2x
=-2x(2x^2-3x+1)
=-2x(x-1)(2x-1);
6(y-z)^2 +13(z-y)+6
=6(z-y)^2+13(z-y)+6
=[2(z-y)+3][3(z-y)+2]
=(2z-2y+3)(3z-3y+2).
\u6bd4\u5982...x^2+6x-7\u8fd9\u4e2a\u5f0f\u5b50
\u7531\u4e8e\u4e00\u6b21\u5e42x\u524d\u7cfb\u6570\u4e3a6
\u6240\u4ee5\uff0c\u6211\u4eec\u53ef\u4ee5\u60f3\u5230\uff0c7-1=6
\u90a3\u6b63\u597d\u8fd9\u4e2a\u5f0f\u5b50\u7684\u5e38\u6570\u9879\u4e3a-7
\u56e0\u6b64\u6211\u4eec\u60f3\u5230\u5c06-7\u770b\u62107*\uff08-1\uff09
\u4e8e\u662f\u6211\u4eec\u4f5c\u5341\u5b57\u76f8\u6210
x +7
x -1
\u7684\u5230\uff08x+7\uff09\u00b7\uff08x-1\uff09
\u6210\u529f\u5206\u89e3\u4e86\u56e0\u5f0f
3ab^2-9a^2b^2+6a^3b^2
=3ab^2(1-3a+2a^2)
=3ab^2(2a^2-3a+1)
=3ab^2(2a-1)(a-1)
x^2+x+m=x^2-2nx+n^2
因为恒等，所以必须有-2n=1, m=n^2
n=-1/2
m=n^2=1/4
2.已知2x-y=1/3,xy=2,求2x^4y^3-x^3y^4的值
2x^4y^3-x^3y^4
=(xy)^3(2x-y)
=2^3*1/3
=8/3
3.若4x^2-4x+9y^2-12y+5=0,求6x+2/3y的值
4x^2-4x+9y^2-12y+5=0
(4x^2-4x+1)+(9y^2-12y+4)=0
(2x-1)^2+(3y-2)^2=0
上式成立必须有2x-1=0,x=1/2
3y-2=0,y=2/3
6x+2/3y
=6/2+2/3*2/3
=3+4/9
=31/9
你写错了吧，我看很可能是6x+3/2y,那样结果为4
1.x的平方+x+m=（x-n)平方，则m=，n=
解：x的平方+x+m=（x-n)平方
=x^2-2nx+n^2
所以-2n=1,m=n^2
m=1/4,n=-1/2
2.已知2x-y=1/3,xy=2,求2x^4y^3-x^3y^4的值
解：因为2x-y=1/3,xy=2
所以2x^4y^3-x^3y^4
=x^3y^3(2x-y)
=8*1/3=8/3
3.若4x^2-4x+9y^2-12y+5=0,求6x+2/3y的值
解：4x^2-4x+9y^2-12y+5=0
即：（2x-1）^2+(3y-2)^2=0
所以:x=1/2,y=2/3
6x+2/3y=6*1/2+2/(3*2/3)=3+1=4
(x^2-x-1)^2
(a-b)(x^2+x-1)
(x^2+x+6)(x^2+x-4)
s
绛旓細1.(1)=[2(x²+6x+1)+(x²+1)][(x²+6x+1)+2(x²+1)]=(2x²+12x+2+x²+1)(x²+6x+1+2x²+2)=(3x²+12x+3)(3x²+6x+3)=9(x²+4x+1)(x+1)²(2)=(x²+8x+7)(x²+8x+15)+15 ...
绛旓細(1) 鍘熷紡=(4x²+1)(4x²-1)=(4x²+1)(2x+1)(2x-1)(2) 鍘熷紡=-1/2(4x²-y²)=-1/2(2x+y)(2x-y)(3) 鍘熷紡=a(1-a^4)=a(1+a²)(1-a²)=a(1+a²)(1+a)(1-a)鑻ユ槸楂樹腑棰樼洰锛(1) 鍘熷紡=(4x²+1)(4x²...
绛旓細(1)3x^2锛6x锛3x(x-2)(2)49x^2锛25锛(7x+5)(7x-5)(3)6x^2锛13x锛5锛(2x-1)(3x-5)(4)x^2锛2锛3x锛(x-1)(x-2)(5)12x^2锛23x锛24锛(3x-8)(4x+3)(6)(x锛6)(x锛6)锛(x锛6)锛(x-6)(x+5)(7)3(x锛2)(x锛5)锛(x锛2)(x锛3)锛2(x-6)(x+2)(8...
绛旓細-[3(x-y)]²=(5x+5y+3x-3y)(5x+5y-3x+3y)=(8x+2y)(2x+8y)=8(4x+y)(x+4y)闂琛ュ厖锛氳繕鏈変竴涓 鍏鍒嗚В鍥犲紡锛鍐嶈绠 蟺R1^2+蟺R2^2+蟺R3^2,鍏朵腑R1=4 R2=8 R3=10 蟺鍙3.14 蟺R1^2+蟺R2^2+蟺R3^2 =蟺(R1^2+R2^2+R3^2)=3.14(16+64+100)=565.2 ...
绛旓細5.闂細褰搆涓轰綍鍊兼椂锛屽叧浜x,y鐨勫椤瑰紡kx^2-2xy-3y^2+3x-5y+2鍙互鍒嗚В涓轰袱涓竴娆鍥犲紡鐨涔樼Н锛熻杩欎袱涓竴娆″洜寮忕殑涔樼Н涓 (ax+by+c)(a'x+b'y+c')=kx^2-2xy+3y^2+3x-5y+2 褰搙=0鏃,鍘熷紡=(by+c)(b'y+c')=-3y^2-5y+2=-(3y-1)(y+2)(ax-3y+1)(a'x+y+2)=a'ax^...
绛旓細甯姪鐨勪汉:152涓 鎴戜篃鍘荤瓟棰樿闂釜浜洪〉 鍏虫敞 灞曞紑鍏ㄩ儴 渚1鍒嗚В鍥犲紡:x^15+m^12+m^9+m^6+m^3+1 瑙ｅ師寮=(x^15+m^12)+(m^9+m^6)+(m^3+1) =m^12(m^3+1)+m^6(m^3+1)+(m^3+1) =(m^3+1)(m^12+m^6++1) =(m^3+1)[(m^6+1)2-m^6] =(m^+1)(m^2-m^+1)...
绛旓細1.(x+y)²-4锛坸+y-1)=(x+y)²-4(x+y)+4 =(x+y)²-2脳2(x+y)+2²=(x+y-2)²2.(x-y)²+4xy =x²-2xy+y²+4xy =x²+2xy+y²=(x+y)²3.(x-1)(x+3)+1 =x²+2x+1-3 =(x+1)²-3...
绛旓細35.鍥犲紡鍒嗚Вx2锛25锛 銆36.鍥犲紡鍒嗚Вx2锛20x锛100锛 銆37.鍥犲紡鍒嗚Вx2锛4x锛3锛 銆38.鍥犲紡鍒嗚В4x2锛12x锛5锛 銆39.鍥犲紡鍒嗚В涓嬪垪鍚勫紡锛(1)3ax2锛6ax锛 銆(2)x(x锛2)锛峹锛 銆(3)x2锛4x锛峚x锛4a锛 銆(4)25x2锛49锛 銆(5)36x2锛60x锛25锛 銆(6)4x2锛12x锛9锛 銆(7)x2...
绛旓細1 9-6锛坅+b)+(a+b)^2=[3-(a+b)]²=(3-a-b)²2 4a^2b-4ab^2+b^3=b(4a²-4ab+b²)=b(2a-b)²璁＄畻棰 (a-b+3)(a+b-3)=[a-(b-3)][a+(b-3)]=a²-(b-3)²=a²-b²+6b-9 鍖栫畝 x(2x+1)(1-2x)...
绛旓細2銆佸崄瀛楃浉涔樻硶鐨勭敤澶:(1)鐢ㄥ崄瀛楃浉涔樻硶鏉鍒嗚В鍥犲紡銆(2)鐢ㄥ崄瀛楃浉涔樻硶鏉ヨВ涓鍏冧簩娆℃柟绋嬨 3銆佸崄瀛楃浉涔樻硶鐨勪紭鐐:鐢ㄥ崄瀛楃浉涔樻硶鏉ヨВ棰樼殑閫熷害姣旇緝蹇,鑳藉鑺傜害鏃堕棿,鑰屼笖杩愮敤绠楅噺涓嶅ぇ,涓嶅鏄撳嚭閿欍 4銆佸崄瀛楃浉涔樻硶鐨勭己闄:1銆佹湁浜棰樼洰鐢ㄥ崄瀛楃浉涔樻硶鏉ヨВ姣旇緝绠鍗,浣嗗苟涓嶆槸姣忎竴閬撻鐢ㄥ崄瀛楃浉涔樻硶鏉ヨВ閮界畝鍗曘2銆佸崄瀛楃浉涔...
