一道物理题,需要讲解的非常详细哦
\u4e00\u4e2a\u7269\u7406\u9898\uff0c\u8bf7\u8be6\u7ec6\u89e3\u6790\u4e00\u4e0b\u662fAB
B\u521a\u521a\u6f0f\u9009\u4e86 (\u53c2\u89c1\u4e0b\u9762\u5206\u6790\u4e2d\u7684\u6700\u540e\u4e24\u53e5)
\u5728\u9759\u6b62\u7684\u65f6\u5019\uff0c\u7531\u4e8e\u7269\u5757\u53d7\u529b\u5e73\u8861\uff0c\u6240\u4ee5\u7269\u5757\u53d7\u5230\u65b9\u5411\u5411\u53f3\u7684\u62c9\u529b5N,\u65b9\u5411\u5411\u5de6\u7684\u6469\u64e6\u529b5N\uff0c\u6700\u5927\u9759\u6469\u64e6\u529b\u5927\u4e8e\u7b49\u4e8e5N
\u5c0f\u8f66\u5411\u53f3\u52a0\u901f\u8fd0\u52a8\uff0c\u90a3\u4e48\u5982\u679c\u7269\u5757M\u76f8\u5bf9\u5c0f\u8f66\u4ecd\u9759\u6b62\uff0c\u5219\u6240\u9700\u5408\u529b=10*1=10N,\u65b9\u5411\u5411\u53f3
\u8fd9\u65f6\u5f39\u7c27\u53ef\u4ee5\u63d0\u4f9b\u65b9\u5411\u5411\u53f3\u7684\u62c9\u529b5N,\u4f46\u662f\u6240\u9700\u5408\u529b\u4e0d\u591f\uff0c\u8fd8\u970010-5=5N,\u56e0\u6b64\u7269\u5757\u76f8\u5bf9\u5c0f\u8f66\u6709\u5411\u5de6\u8fd0\u52a8\u7684\u8d8b\u52bf\uff0c\u7531\u4e8e\u9759\u6469\u64e6\u529b\u65b9\u5411\u4e0e\u7269\u4f53\u76f8\u5bf9\u8fd0\u52a8\u65b9\u5411\u76f8\u53cd\uff0c\u5219\u9759\u6469\u64e6\u529b\u65b9\u5411\u4e3a\u6c34\u5e73\u5411\u53f3\uff0c\u7531\u4e8e\u6700\u5927\u9759\u6469\u64e6\u529b\u5927\u4e8e\u7b49\u4e8e5N\uff0c\u800c\u6240\u9700\u6469\u64e6\u529b\u4e3a5N,\u56e0\u6b64\u9759\u6469\u64e6\u529b\u63d0\u4f9b\u5269\u4e0b\u76845N,\u521a\u597d\u4f7f\u7269\u5757\u5408\u529b\u8fbe\u523010N,\u56e0\u6b64\u7269\u5757M\u76f8\u5bf9\u5c0f\u8f66\u4ecd\u9759\u6b62
\u4f60\u7684\u505a\u6cd5\u6ca1\u9519...\u8fd9\u4e2a\u6b63\u786e\u7b54\u6848\u6709\u95ee\u9898\u554a...
(r^a)/(r^c)\uff1eb/d\u5230\u8fd9\u91cc\u6ca1\u95ee\u9898\uff0c\u4f46\u5728\u786e\u5b9ar\u7684\u5173\u7cfb\u7684\u65f6\u5019\u663e\u7136\u8981\u8003\u8651a-c\u7684\u6b63\u8d1f\u3002
\u5728\u73b0\u5b9e\u751f\u6d3b\u4e2d\uff0cf\u5f15\u6bd4f\u65a5\u8870\u51cf\u5f97\u6162\uff0c\u662f\u957f\u7a0b\u4f5c\u7528\u529b\uff0c\u800cf\u65a5\u4e00\u79cd\u77ed\u7a0b\u529b\uff0c\u6240\u4ee5\u5fc5\u7136\u6709c>a \u7684\u5173\u7cfb\uff0c\u5373 a-c<0\u3002\u663e\u7136a-c<0\u65f6r^(a-c)\u662f\u51cf\u51fd\u6570\uff0c\u4e3a\u6ee1\u8db3(r^a)/(r^c)\uff1eb/d\u5fc5\u7136\u6709r\uff1ca-c\u221ab/d\u3002
\u9009A\u6ca1\u9519
能量=电流^2 * 电阻
所以 电阻=100/(0.5^2)=400 欧
电压=电流*电阻=200 V
物理量没用符号表示
解:
I=Q/t=10C/20s=0.5A
W=UQ U=W/Q=100J/10C=10V
R=U/I=10V/0.5A=20欧
求电流:电流是每秒钟通过导体横截面的量I=Q/S,Q=10C,S=20S,所以I=10C/20S=0.5A。
求电压:已知电流做功W=UIT=100J,I=0.5A,T=20S,所以U=W/IT=100J/0.5A*20S=10V。
求电阻:R=U/I=10V/0.5A=20欧姆。
应该是吧,时间长拉,都忘拉怎么算拉,哈哈
t=20s,Q=10c,W=100J
I=Q/t
U=W/It
R=U/I
I=q/t=0.5A
Q=Uq
U=10v
R=U/I=20(omu)
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