求标准状况下224L二氧化碳的物质的量
\u6807\u51c6\u72b6\u51b5\u4e0b,\u4f53\u79ef\u4e3a11.2L\u7684CO2\u7684\u7269\u8d28\u7684\u91cf\u6c14\u4f53\u7269\u8d28\u7684\u91cf=\u4f53\u79ef/\u6469\u5c14\u4f53\u79ef=11.2/22.4=0.5mol\uff0c\u8d28\u91cf=\u7269\u8d28\u7684\u91cf*\u6469\u5c14\u8d28\u91cf=0.5*44=22g\uff0c\u4e00\u4e2aCO2\u5206\u5b50\u4e2d\u542b3\u4e2a\u539f\u5b50\uff0c\u6240\u4ee50.5molCO2\u4e2d\u542b0.5*3=1.5mol\u539f\u5b50\uff0c\u4e2a\u6570\u4e3a1.5NA\uff0c\u7ea69.03\u00d710^23\u4e2a
28.0L\u00f722 .4L/mol=1.25mol
224/22.4=10moln=V/Vm=224L/22.4mol/L=10mol
10mol
绛旓細甯告俯甯稿帇涓22.4L姘斾綋閮芥槸涓鎽╁皵鍒嗗瓙锛屼竴鎽╁皵鍒嗗瓙鍚6.021367脳10^23涓垎瀛
绛旓細涓嶅銆傚父娓╁父鍘涓22.4鍗浜屾哀鍖栫⒊鐨鐗╄川鐨勯噺瑕佸皬浜1鎽╁皵锛屾墍鍚簩姘у寲纰冲垎瀛愮殑鏁伴噺锛屼竴瀹氳灏忎簬NA.
绛旓細A銆鏍囧噯鐘跺喌涓锛22.4L娣峰悎姘斾綋鐨勭墿璐ㄧ殑閲忎负1mol锛1mol浜屾哀鍖栫⒊鍜屾哀姘旂殑娣峰悎姘斾綋涓惈鏈2mol姘у師瀛愶紝鍚湁鐨勬哀鍘熷瓙鏁颁负2NA锛屾晠A姝ｇ‘锛汢銆1mol閾佷笣瀹屽叏鍙嶅簲闇瑕佹秷鑰1.5mol姘皵锛屾墍浠ユ隘姘斾笉瓒筹紝1mol姘皵瀹屽叏鍙嶅簲杞Щ浜2mol鐢靛瓙锛岃浆绉荤殑鐢靛瓙鏁颁负2NA锛屾晠B閿欒锛汣銆佽鍙嶅簲涓哄彲閫嗗弽搴旓紝2mol浜屾哀鍖栫～鍜1mol...
绛旓細鈶 0.74g 鈶 896mL 鈶 m = V/224 褰撶敓鎴愭矇娣鍒氬ソ鏈澶ф椂 灏辨槸纰抽吀閽欏畬鍏ㄦ矇娣 CO2--- CaCO3 --- Ca(OH)2 22.4 74 224姣崌(0.224L) 0.74 姘㈡哀鍖栭挋璐ㄩ噺涓0.74g 娌夋穩鍒氬ソ婧惰В鏃讹紝灏辨槸鎵鏈夌殑OH-杞寲鎴愪簡HCO3- 姘㈡哀鍖栭挋鐨勭墿璐ㄧ殑閲忎负0.01mol KOH鐨勮川閲忎负1.86g - 0.74g...
绛旓細鍙嶅簲鏄疦a2O2涓殑O22-绂诲瓙鐨勬鍖栧弽搴斻2.24CO2鐨鐗╄川鐨勯噺涓0.1mol锛屾寜杩欎釜鍙嶅簲鏂圭▼寮2molCO2鍙嶅簲杞Щ2mol鐢靛瓙锛0.1molCO2鍙嶅簲杞Щ0.1mol鐢靛瓙銆
绛旓細1鎽╁皵浜屾哀鍖栫⒊鍒嗗瓙鍚湁璐ㄥ瓙鏁颁负锛6+8X2=22锛坢ol锛夋墍浠2.24鍗囦簩姘у寲纰冲惈鏈夎川瀛愭暟涓猴細2.24/22.4X22=2.2锛坢ol锛
绛旓細鏍囧噯鐘跺喌涓锛22銆4鍗囩殑姘斾綋灏辨湁1鎽╁皵鐗╄川鐨勯噺銆傜敤16銆8闄や互22銆4灏卞緱鍑烘槸0.75鎽╁皵銆浜屾哀鍖栫⒊鐨鎽╁皵璐ㄩ噺涓12鍔16涔樹互2绛変簬44g姣忔懇灏旀墍浠ワ紝鐢0.75涔樹互44鏈鍚庡緱鍑轰簩姘у寲纰崇殑瀵嗗害銆1銆佸湪鐩稿悓鏉′欢涓嬪瘑搴︽渶灏忕殑鏄阿姘旓紱2銆佷竴姘у寲纰宠兘璺熶汉浣撹绾㈣泲鐧界粨鍚堜娇浜虹己姘ф皵鑰屼腑姣掞紱3銆佺敱浜庝簩姘у寲纰充笉鐕冪儳銆佷笉鏀寔...
绛旓細1. 22.4:44=44.8:x x=88g CaCO3 +2HCl ===CaCl2 +CO2 + H2O 100 44 X 88 100/x=44/88 x=200g 2.婢勬竻鐭崇伆姘寸殑璐ㄩ噺鏄100g 鍙傚姞鍙嶅簲鐨浜屾哀鍖栫⒊璐ㄩ噺:104.4-100=4.4g CO2 + Ca(OH)2 ===CaCO3 +H2O 44 100 4.4 ...
绛旓細1,瑕佹眰鏍囧喌 2,鍚屼笂 3,SO3鏍囧喌鏄浐浣 4,瀵,32gO2灏辨槸1mol,璺熸潯浠舵棤鍏
绛旓細鍏ㄦ槸CO鏄28锛屽叏鏄CO2鏄44 36-28=8 44-36=8 鐢ㄥ樊閲忔硶鏄1锛1鎵浠ョ墿璐ㄧ殑閲忔瘮鏄1锛1鍗筹細浣撶Н姣旀槸1锛1锛岃川閲忔瘮鏄7锛11
