随机产生五十个一百以内的正整数放入数组中,输出这五十个整数(每行十个)求这50个数中的奇数及平均数 vb产生30个0~1000的随机整数,放入一个数组中,输出最...

\u968f\u673a\u4ea7\u751f\u4e94\u5341\u4e2a\u4e00\u767e\u4ee5\u5185\u7684\u6b63\u6574\u6570\u653e\u5165\u6570\u7ec4\u4e2d,\u8f93\u51fa\u8fd9\u4e94\u5341\u4e2a\u6574\u6570(\u6bcf\u884c\u5341\u4e2a)\u6c42\u8fd950\u4e2a\u6570\u4e2d\u7684\u5947\u6570\u5e73\u5747\u6570


#include#include#includeint main(){ int i,a[50],s=0,k=0; srand(time(0)); for(i=0; i<50; i++) { a[i]=rand()%100+1; if(a[i]%2) { s+=a[i]; k++; } printf("%4d",a[i]); if(i%10==9)printf("\n"); } printf("\n\u5947\u6570\u7684\u5e73\u5747\u6570=%.2f\n",(float)s/k); return 0;}

'\u5b9e\u73b0\u4ee3\u7801\u5982\u4e0bPrivate Sub Form_Click() Me.Cls Dim n(1 To 30) As Integer Dim i%,nMax% Dim str As String '\u4ea7\u751f30\u4e2a0-1000\u7684\u968f\u673a\u6570\u5e76\u5199\u5165\u6570\u7ec4 Randomize For i = 1 To 30 n(i) = Int((1000 - 0 + 1) * Rnd + 0) str = str & n(i) & " " If i Mod 10=0 Then str=str & vbCrLf Next i '\u627e\u6700\u5927\u503c nMax=n(1) For i = 1 To 30 If n(i)>nMax Then nMax=n(i) Next i Print str '\u7a97\u4f53\u663e\u793a\u968f\u673a\u6570 Print "\u6700\u5927\u503c\uff1a" & nMaxEnd Sub

#include<stdio.h>
#include<time.h>
#include<stdlib.h>
#define N 50
void main() { int a[N],i,n; float av;
  srand((unsigned int)time(NULL));
  for ( i=0;i<N;i++ ) a[i]=rand()%100;
  av=0; n=0;
  for ( i=0;i<N;i++ ) {
    printf("%d ",a[i]); if ( i%10==9 ) printf("
");
    if ( a[i]%2!=0 ) { av+=a[i]; n++; }
  }
  av/=n; printf("
%f
",av);
}


#include<stdio.h>
#include <time.h>
#include <stdlib.h>

int main(){
    int all[50];
    double sum = 0;
    int i;
    int count = 0;
    srand(time(NULL));
    printf("生成的50个随机数数是:
");
    for(i=0;i<50;i++){
        all[i] = rand()%99 + 1;
        printf("%d ", all[i]);
        if((i+1)%10 == 0){
            printf("
");
        }
    }
    printf("随机数中的奇数是:
");
    for(i=0;i<50;i++){
        if(all[i]%2 == 1){
            printf("%d ", all[i]);
            sum += 1.*all[i];
            count ++;
        }
    }
    printf("
");
    printf("平均值是%lf
", sum / count);
    return 0;
}


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