随机产生五十个一百以内的正整数放入数组中,输出这五十个整数(每行十个)求这 随机产生50个100以内的正整数放入数组中，输出这50个整数...
\u968f\u673a\u4ea7\u751f\u4e94\u5341\u4e2a\u4e00\u767e\u4ee5\u5185\u7684\u6b63\u6574\u6570\u653e\u5165\u6570\u7ec4\u4e2d,\u8f93\u51fa\u8fd9\u4e94\u5341\u4e2a\u6574\u6570(\u6bcf\u884c\u5341\u4e2a)\u6c42\u8fd9
#include#include#includeint main(){ int i,a[50]; srand(time(0)); for(i=0; i<50; i++) { a[i]=rand()%100+1; printf("%4d",a[i]); if(i%10==9)printf("\n"); } return 0;}
#include #include void print_arr (int* a, int n){ int i = 0; for (; i \u968f\u673a\u6570\u79cd\u5b50 int a[N], i; for (i = 0; i < N; i++) { a[i] = rand() % 100 + 100; } print_arr(a, N); return 0;}
\u8fd0\u884c\uff1a
打码不容易望采纳谢谢。。。
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#define random(x) (rand()%x)
/* run this program using the console pauser or add your own getch, system("pause") or input loop */
int main(int argc, char *argv[]) {
srand((unsigned) time(NULL)); //用时间做种，每次产生随机数不一样
int result[50];
printf("随机产生范围【1,99】内的正整数数组 :
");
int i=0;
int length=50;
for(;i<length;i++){
result[i]=random(89)+1;
printf("%d ",result[i]);
}
printf("
");
printf("每10个一行形式打印数组:
");
i=0;
for(;i<length;i++)
{
printf("%2d ",result[i]);
if((i+1)%10==0)
printf("
");
}
system("pause");
return 0;
}
把题目写完整好吗？
绛旓細include<stdio.h>#include#include<stdlib.h>#define N 50void main() { int a[N],i,n; float av; srand((unsigned int)time(NULL)); for ( i=0;i<N;i++ ) a[i]=rand()%100; av=0; n=0; for ( i=0;i<N;i++ ) { printf("%d ",a[i]); if ( i%10==9...
绛旓細a[50],s=0,k=0; srand(time(0)); for(i=0; i<50; i++) { a[i]=rand()%100+1; if(a[i]%2) { s+=a[i]; k++; } printf("%4d",a[i]); if(i%10==9)printf("\n"); } printf
绛旓細include<stdio.h>#include<stdlib.h>#includeint main(){ int i,a[50]; srand(time(0)); for(i=0; i<50; i++) { a[i]=rand()%100+1; printf("%4d",a[i]); if(i%10==9)printf("\n"); } return 0;} ...
绛旓細姣忔浜х敓闅忔満鏁颁笉涓鏍穒nt result[50];printf("闅忔満浜х敓鑼冨洿銆1,99銆鍐呯殑姝ｆ暣鏁鏁扮粍 :\n");int i=0;int length=50;for(;i<length;i++){result[i]=random(89)+1;printf("%d ",result[i]);}printf("\n");
绛旓細1鍒100鐨勬暣鏁鏈夛細4銆6銆8銆9銆10銆12銆14銆15銆16銆18銆20銆21銆22銆24銆25銆26銆27銆28銆30銆32銆33銆34銆35銆36銆38銆3940銆42銆44銆45銆46銆48銆49銆50銆51銆52銆54銆55銆56銆57銆58銆60銆62銆63銆64銆65銆66銆68銆69銆70銆72銆74銆75銆76銆77銆78銆80銆81銆82銆84銆85銆...
绛旓細9銆16銆23銆30銆37銆44銆51銆58銆65銆72銆79銆86銆93銆100
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绛旓細瑙ｏ細璁捐兘琚叚鏁撮櫎鐨勬暟=6k,k:Z 100浠ュ唴鐨勬鏁存暟鐨勮寖鍥1<=x<100,Z+ x=6k,1<=6k<100 1/6<=k<100/6 1/6<=k<50/3 [1/6,50/3)k=1,2,3...16 k鑳藉彇1,2,3锛...16 16涓暟 x=6,12,18,24,30,36,42,48,54,60,66,72,78,84,90,96 ...
绛旓細100浠ュ唴鐨濂囨暟锛1銆3銆5銆7銆9銆11銆13銆15銆17銆19銆21銆23銆25銆27銆29銆31銆33銆35銆37銆39銆41銆43銆45銆47銆49銆51銆53銆55銆57銆59銆61銆63銆65銆67銆69銆71銆73銆75銆77銆79銆81銆83銆85銆87銆89銆91銆93銆95銆97銆99 100浠ュ唴鐨勫伓鏁帮細2銆4銆6銆8銆10銆12銆14銆16銆18...
