函数f(x)=sin2x-cos2x是
\u51fd\u6570f\uff08x\uff09=sin2x\u00b7cos2x\u662ffx=\uff08sin4x\uff09/2
sin\uff084x+2\u03c0\uff09=sin\uff084\uff08x+\u03c0/2\uff09\uff09=sin4x\u6240\u4ee5\u5468\u671f\u662f\u03c0/4
sin4x=-sin-4x \u6240\u4ee5\u662f\u5947\u51fd\u6570
\u6240\u4ee5\u662fD
\u4e09\u89d2\u51fd\u6570\uff01\u7528\u516c\u5f0f\u89e3\uff01\u4e8c\u500d\u89d2\u516c\u5f0f\uff01\u624b\u673a\u4e0a\u9762\u4e0d\u597d\u89e3\uff01
f(x)=sin²x-cos²x = -cos(2x)是偶函数,最小正周期是π
D正确
用辅助角公式 根号2sin(2x 3派/4) 选D
C f(x)= 根号2正弦(2x-四分之 )
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绛旓細瑙d箣寰 - 蟺 3 +k蟺鈮鈮 蟺 6 +k蟺 锛坘鈭圸锛夛紝鈭鍑芥暟f锛坸锛鐨勯掑鍖洪棿鏄 [- 蟺 3 +k蟺锛 蟺 6 +k蟺] 锛宬鈭圸锛庯紙鈪★級鐢眆锛坸锛夆墺2锛屽緱 2sin(2x+ 蟺 6 )+1鈮2 锛坘鈭圸锛夛紝鍗 sin(2x+ 蟺 6 )鈮 1 2 ...
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绛旓細2sinx(cosx-sinx) cosx-sinx =sin2x 锛屸埓f锛坸锛夌殑鏈灏忔鍛ㄦ湡涓合锛7鍒嗭級锛堚叀锛夆埖 cos( 蟺 4 +x)= 3 5 鈭 f(x)=sin2x=-cos(2x+ 蟺 2 )=-2co s 2 (x+ 蟺 4 )+1 = -2脳 9 25 +1= 7 25 锛
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