(2013?房山区二模)某同学要探究浸入水中金属圆柱体所受测力计的拉力与浸在水中深度的关系.装置如图所

\u5c0f\u738b\u4e3a\u4e86\u63a2\u7a76\u7269\u4f53\u5b58\u6c34\u4e2d\u4e0d\u540c\u6df1\u5ea6\u6240\u53d7\u6d6e\u529b\u53d8\u5316\u60c5\u51b5\uff0c\u5982\u56fe1\u6240\u793a\uff0c\u5c06\u4e00\u6302\u5728\u5f39\u7c27\u6d4b\u529b\u8ba1\u4e0b\u7684\u5706\u67f1\u4f53\u91d1\u5c5e\u5757\u7f13\u6162\u6d78

\u5c06\u539f\u9898\u76ee\u91cd\u65b0\u6574\u7406\u5982\u4e0b\uff0c\u5e76\u89e3\u7b54\u5982\u4e0b\uff1a
\u5c0f\u738b\u4e3a\u4e86\u63a2\u7a76\u7269\u4f53\u5b58\u6c34\u4e2d\u4e0d\u540c\u6df1\u5ea6\u6240\u53d7\u6d6e\u529b\u53d8\u5316\u60c5\u51b5\uff0c\u5982\u56fe1\u6240\u793a\uff0c\u5c06\u4e00\u6302\u5728\u5f39\u7c27\u6d4b\u529b\u8ba1\u4e0b\u7684\u5706\u67f1\u4f53\u91d1\u5c5e\u5757\u7f13\u6162\u6d78\u5165\u6c34\u4e2d\uff08\u6c34\u8db3\u591f\u6df1\uff09\uff0c\u5728\u5706\u67f1\u4f53\u63a5\u89e6\u5bb9\u5668\u5e95\u4e4b\u524d\uff0c\u5206\u522b\u8bb0\u4e0b\u5706\u67f1\u4f53\u4e0b\u8868\u9762\u6240\u5904\u7684\u4e0d\u540c\u6df1\u5ea6h\u548c\u5f39\u7c27\u6d4b\u529b\u8ba1\u76f8\u5e94\u7684\u793a\u6570F\uff0c\u5b9e\u9a8c\u6570\u636e\u5982\u4e0b\u8868\uff1a
\u6b21\u6570 1 2 3 4 5 6 7
h(cm) 0 2 4 6 8 10 12
F(N) 6.75 6.25 5.75 5.25 4.75 4.25 4.25
\uff081\uff09\u5206\u6790\u8868\u4e2d\u5b9e\u9a8c\u6570\u636e\uff0c\u53ef\u4ee5\u5f97\u51fa\u7269\u4f53\u91cd(6.75)N\uff0c\u7b2c4\u6b21\u5b9e\u9a8c\u65f6\uff0c\u7269\u4f53\u53d7\u5230\u7684\u6d6e\u529b(1.5)N\uff1b
\uff082\uff09\u5206\u6790\u8868\u4e2d\u7b2c1\u5217\u5230\u7b2c5\u5217\u6570\u636e\uff0c\u8bf4\u660e(\u7269\u4f53\u6240\u53d7\u5230\u7684\u6c34\u7684\u6d6e\u529b\u4e0e\u6d78\u6ca1\u6c34\u4e2d\u7684\u6df1\u5ea6\u6709\u5173\uff0c\u6d78\u5165\u8d8a\u6df1\u53d7\u5230\u7684\u6d6e\u529b\u8d8a\u5927\uff09\uff1b
\uff083\uff09\u5206\u6790\u8868\u4e2d\u7b2c6\u5217\u5230\u7b2c7\u5217\u6570\u636e\uff0c\u8bf4\u660e\uff08\u7269\u4f53\u5df2\u5b8c\u5168\u6d78\u6ca1\u4e8e\u6c34\u4e2d\u540e\uff0c\u5176\u6240\u53d7\u7684\u6d6e\u529b\uff0c\u4e0e\u6d78\u6ca1\u4e8e\u6c34\u7684\u6df1\u5ea6\u65e0\u5173\uff0c\u5373\u6240\u53d7\u5230\u7684\u6d6e\u529b\u662f\u4e00\u4e2a\u5b9a\u503c\uff09\u3002

\u5907\u6ce8\uff1a\u62ec\u53f7\u5185\u586b\u5199\u7684\u5185\u5bb9\uff0c\u5373\u4e3a\u539f\u9898\u6a2a\u7ebf\u4e0a\u5e94\u8be5\u586b\u5199\u7684\u5185\u5bb9\u3002

\u89e3\uff1a\u7531\u7b2c\u4e00\u7ec4\u6570\u636e\u53ef\u77e5\uff1a\u5728\u7a7a\u6c14\u4e2d\u5706\u67f1\u4f53\u7684\u91cd\u529b\u4e3a3N\uff0c\u800c\u7b2c\u4e94\u7ec4\u6570\u636e\u4ee5\u540e\u6d4b\u529b\u8ba1\u793a\u6570\u4e0d\u518d\u53d8\u5316\uff0c\u8bf4\u660e\u5706\u67f1\u4f53\u5df2\u7ecf\u5b8c\u5168\u6d78\u6ca1\u5728\u6db2\u4f53\u4e2d\uff08\u5373\u5706\u67f1\u4f53\u7684\u9ad8\u662f2.4cm\uff0c\u5373h=0.024m\u3002\uff09
\u7531\u4ee5\u4e0a\u4e24\u7ec4\u6570\u636e\u53ef\u77e5F\u6d6e=G1-G5=0.6N\uff0c\u518d\u6839\u636e\u963f\u57fa\u7c73\u5fb7\u539f\u7406\u6709\uff1aF\u6d6e=\u03c1\u6db2gV\u6392=0.6N
\u56e0\u6c34\u7684\u5bc6\u5ea6\u4e3a1.0*10^3 Kg|m3 , g=10N/Kg,
\u5219\u53ef\u4ee5\u6c42\u5f97V\u6392=6*10 ^ -5m3
\u5373\u5706\u67f1\u4f53\u7684\u4f53\u79ef\u4e3a6*10 ^ -5m3
\u800c\u524d\u9762\u77e5\u9053\u5706\u67f1\u4f53\u7684\u91cd\u529b\u4e3a3N\uff0c\u5219\u5b83\u7684\u8d28\u91cfm=G/g=0.3 Kg
\u518d\u6839\u636e\u5bc6\u5ea6\u516c\u5f0f\u03c1=m/V=0.3 Kg / 6*10 ^ -5 m3=5*10^3 kg|m3
\u4e0d\u77e5\u697c\u4e3b\u80fd\u770b\u61c2\u4e0d\uff1f

由表格中数据知,深度每增大0.01m,拉力减小2N,由此可得△F=
2N
0.01m
=200N/m;当深度为0时,拉力为20N.
则金属圆柱体所受到拉力 F 大小与浸入水中深度 h 的关系式为F=20N-200N/m?h.
故答案为:F=20N-200N/m?h.

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