标准状况下,将224L的HCL气体溶于815ml水中（p=1.00g/cm3),您好 刚才忘加一个条件
\u6807\u51c6\u72b6\u51b5\u4e0b,\u5c06224L\u7684HCL\u6c14\u4f53\u6eb6\u4e8e815ml\u6c34\u4e2d\uff08p=1.00g/cm3),\u6240\u5f97\u76d0\u9178\u7684\u5bc6\u5ea6\u662f1.18g/cm3\u7406\u8bba\u4e0a\u6765\u8bf4\uff0c\u8fd9\u662f\u96be\u4ee5\u8ba1\u7b97\u7684\uff1a\u4e00\u662f\u56e0\u4e3a\u4e24\u4e0d\u540c\u7684\u6eb6\u6db2\u6df7\u5408\u540e\u7684\u4f53\u79ef\u4e0d\u662f\u539f\u4e24\u6eb6\u6db2\u4f53\u79ef\u7b80\u5355\u76f8\u52a0\u3002\u4e8c\u662f\u56e0\u4e3aH2SO4\u5728\u6c34\u6eb6\u6db2\u4e2dH+\u4e0d\u662f\u5b8c\u5168\u7535\u79bb\u51fa\u6765\u7684\uff0c\u8981\u8ba1\u7b97H+\u6d53\u5ea6\u5c31\u8fd8\u5f97\u77e5\u9053\u5176\u7535\u79bb\u5e38\u6570\uff0c\u8ba1\u7b97\u8d77\u6765\u76f8\u5f53\u590d\u6742\u3002\u5982\u679c\u4e0d\u8003\u8651\u8fd9\u4e9b\u56e0\u7d20\uff0c\u90a3\u8ba1\u7b97\u5c31\u5f88\u7b80\u5355\uff1a\u53ea\u8981\u8ba1\u7b97\u51fa\u603b\u7684H+\u7269\u8d28\u7684\u91cf\uff0c\u7136\u540e\u9664\u4ee5\u4e24\u6eb6\u6db2\u4f53\u79ef\u4e4b\u548c\u5c31\u884c\u4e86\u3002
HCl\u7684\u7269\u8d28\u7684\u91cf 224/22.4=10(mol)
HCl\u7684\u8d28\u91cf10*36.5\uff1d365\uff08g\uff09
\u6eb6\u6db2\u7684\u8d28\u91cf365+635*1\uff1d1000\uff08g\uff09
HCl\u7684\u8d28\u91cf\u5206\u6570365/1000\u00d7100\uff05\uff1d36.5\uff05
c\uff08HCl\uff09\uff1d1000*1.19*36.5%/36.5=11.9(mo/L)
\u7a00\u91ca\u540e\u6d53\u5ea6 11.9*10\uff1d1190c \uff0cc\uff1d0.1\uff08mol/L\uff09
n(HCl)=224/22.4=10mol; n(H2SO4)=430*1.14*20%/98;注意盐酸溶液体积=溶液质量/密度
V(盐酸)=[m(HCl)+m(H2O)]/1.18=[224*36.5/22.4+815*1]/1.18
V（溶液）=V(盐酸)+V(H2SO4),V(H2SO4)=430ml.
将数据带进去算就行了。
绛旓細n=224/22.4=10mol 婧舵恫浣撶Н涓篤 V=m梅瀵嗗害 m=婧惰川+婧跺墏=10*36.5+635*1.0=1000g c=n/V=10梅[锛1000梅1.18锛*10^-3]=11.8mol/L 鐢ㄥ瘑搴︾畻鍑烘潵鐨勪綋绉崟浣嶆槸ml 鎹㈢畻鎴怢 鎵浠ヤ箻浠10^-3
绛旓細锛1锛塶锛HCl锛=224L22.4L/mol=10mol锛宮锛圚Cl锛=10mol脳36.5g?mol-1=365g锛屾憾娑茬殑浣撶НV=365g+635g1.18g/cm3=847ml=0.847L锛岀█鐩愰吀鐨勭墿璐ㄧ殑閲忔祿搴=10mol0.847L=11.8mol/L锛涜绋閲婂悗寰楃洂閰哥殑娴撳害涓篶1锛岀敱绋閲婂畾寰嬪彲寰楋細11.8mol/L脳0.1L=c1脳1.18L锛岃В寰楋細c1=1mol/L锛屾晠...
绛旓細锛1锛224L姘寲姘姘斾綋鐗╄川鐨勯噺涓224L22.4L/mol=10mol锛屾晠HCl鐨璐ㄩ噺=10mL脳36.5g/mol=365g锛屾按鐨勮川閲忎负635mL脳1g/mL=635g锛岃婧舵恫璐ㄩ噺鍒嗘暟涓365g365g+635g脳100%=36.5%锛岀瓟锛氳鐩愰吀涓憾璐ㄧ殑璐ㄩ噺鍒嗘暟鏄36.5%锛涳紙2锛夎鐩愰吀鐨勭墿璐ㄧ殑閲忔祿搴︿负1000脳1.18脳36.5%36.5mol/L=11.8mol/L锛屼护...
绛旓細锛1锛224L姘寲姘姘斾綋鐗╄川鐨勯噺涓224L22.4L/mol=10mol锛岀瓟锛氭墍寰楃洂閰镐腑婧惰川鐗╄川鐨勯噺鏄10mol锛涳紙1锛夋晠HCl鐨璐ㄩ噺=10mL脳36.5g/mol=365g锛屾按鐨勮川閲忎负635mL脳1g/mL=635g锛岃婧舵恫璐ㄩ噺鍒嗘暟涓365g365g+635g脳100%=36.5%锛岀瓟锛氳鐩愰吀涓憾璐ㄧ殑璐ㄩ噺鍒嗘暟鏄36.5%锛涳紙3锛夎鐩愰吀鐨勭墿璐ㄧ殑閲忔祿搴︿负1000...
绛旓細锛1锛塶锛HCl锛=224L22.4L/mol=10mol锛宮锛圚Cl锛=10mol脳36.5g?mol-1=365g锛635mL姘寸殑璐ㄩ噺涓635mL脳1g/mL=635g锛岀洂閰哥殑璐ㄩ噺鍒嗘暟w=365g365g+635g脳100%=36.5%锛宑锛圚Cl锛=1000蟻蠅M=1000脳1.18脳36.5%36.5mol/L=11.8mol/L锛岀瓟锛氭墍寰楃洂閰哥殑鐗╄川鐨勯噺娴撳害涓11.8mol/L锛涳紙2锛...
绛旓細婧惰川姘寲姘鐨勬懇灏旀暟鏄細224L/(22.4L/mol=10.0mol 锛涙隘鍖栨阿婧朵簬姘村悗寰楀埌鐨勬憾娑茶川閲忔槸锛10.0mol*36.5g/mol+635ml*1.00g/ml =365g+635g=1000g 锛涙隘鍖栨阿姘存憾娑茬殑浣撶Н鏄細1000g/(1.18g/ml)=847ml 锛涙墍寰楃洂閰哥殑鐗╄川閲忔祿搴︽槸锛(10.0mol/847ml)*1000ml/L=11.8mol/L 銆
绛旓細1.224HCL鍗10molHCl m(HCl)=10mol*36.5g/mol=365g 婧舵恫鎬昏川閲365g+635g=1000g 鍗847.46mL=0.84746L C(HCL)==10mol/0.84746L=11.8mol/L 鎵浠ユ憾浜庢按婧舵恫鐗╄川鐨勯噺娴撳害涓11.8mol/L 10.0ml涓湁HCl 0.118mol C(绋閲)=0.118mol/1.45L=0.0813mol/L 2.纰抽吀閽犵墿璐ㄧ殑閲忎负0.0026...
绛旓細锛1锛12.0 mol路 L -1 锛2锛26.9 L33.6 g 锛1锛塶(HCl)="224" L/22.4 L路 mol -1 ="10.0" molm(HCl婧舵恫)="635" g+10.0 mol脳36.5 g路 mol -1 =1.00脳10 3 gc(HCl)= =" 12.0 " mol 路 L -1 锛2锛塇Cl+NaHCO 3 ===NaCl+H 2 O+CO 2 鈫1 mol ...
绛旓細224L 10mol 10mol * 36.5g/mol =365g 635ml姘=635g 鎬昏川閲=365+635=1000g 浣撶Н=1000/1.18ml 鐩愰吀10.0ml 鍒欏彇鍑hcl =10*锝10/锛1000/1.18锛夛綕=0.118mol 鐗╄川閲忔祿搴=0.118/14.5=0.008138mol/L
绛旓細n(hcl)=10mol C(hcl)=11.8mol/L v(娑)=[(635g+10molx36.5g/mol)x10^-3L/mL]/1.18g/mol=0.85L C(hcl)=11.8mol/L C(hcl绋)=n/v=[C(hcl)x10x10^-3L/ml]/1.45L=0.08mol/L 鑷繁鍋氱殑锛岀瓟妗堝簲璇ユ槸瀵圭殑銆傛墦寰楃湡绱晩銆
