怎样用Mathematica柱坐标系CylindricalPlot3D画圆锥和半球体?? mathematica 画圆锥

\u5229\u7528\u67f1\u9762\u5750\u6807\u7cfb\u753b\u51fa\u9525\u9762\u548c\u7403\u9762\u4e0a\u534a\u90e8\u5206\u6784\u6210\u7684\u56fe\u5f62\uff08mathematica\uff09

RegionPlot3D[
z >= 3*Sqrt[x^2 + y^2] &&(*\u4e0e\u7403\u9762 \u6539\u4e86\u7403\u5fc3\u4f4d\u7f6e\uff0c\u5426\u5219\u7a7a\u56fe\uff01\uff0c\u81ea\u5df1\u6309\u9700\u8981\u518d\u6539\u53c2\u6570*)x^2 + y^2 + (z - 3)^2 <= 9, {x, -3,
3}, {y, -3, 3}, {z, 0, 9}, PlotPoints -> 35, PlotRange -> All]

ParametricPlot3D[{v*Cos[u], v*Sin[u], v}, {u, 0, 2 \[Pi]}, {v, -2, 0}]

在8.0中验证下面的代码通过:
RevolutionPlot3D[r, {r, 0, 1}, {\[Theta], 0, 2 \[Pi]},
AspectRatio -> 1]
RevolutionPlot3D[Sqrt[1 - r^2], {r, 0, 1}, {\[Theta], 0, 2 \[Pi]},
AspectRatio -> 1]
如果是5.2,把RevolutionPlot3D换成CylindricalPlot3D应该能通过。你试试先加载
<< Graphics`ParametricPlot3D`;
再运行上面的命令。

一、柱坐标系的作图函数好像是RevolutionPlot3D。。。
二、你用柱坐标画球体好像不是很方便。。。。
三、圆锥面RevolutionPlot3D[-r, {r, 0, 1}]
四、半球面SphericalPlot3D[1, {x, 0, Pi}, {y, 0, Pi}]
五、以上三、四得到的图像是曲面的图像,并非“圆锥体”,“圆锥面”

Plot[Sin[x], {x, -Pi, Pi}, Axes -> True, AxesLabel -> {"x", "y"}]

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