C程序随机输入一个字符串,统计该串中每个数字字符(0,1,2,3,4,5,6,7, 8,9)出现的次

\u8f93\u5165\u4e00\u4e2a\u5b57\u7b26\u4e32\uff0c\u8ba1\u7b97\u5176\u4e2d\u6240\u6709\u6570\u5b57\u5b57\u7b26\u6240\u4ee3\u8868\u6570\u5b57\u7684\u548c\u3002(\u7f16C\u7a0b\u5e8f)

#include
#define SIZE 80

int main()
{
char str[SIZE];
int index, sum = 0;
printf("Input a string:\n");
scanf("%s", str);

for( index = 0; str[index] != '\0'; ++index )
{
if ( str[index] >= '0' && str[index] <= '9' )
sum += ( str[index] - '0' );
}

printf("The result is %d", sum);
return 0;
}

#include
#include
void main()
{
char s[100];
int i;
static int num[10];
scanf("%s",s);
for(i=0;i<strlen(s);i++)
if(s[i]>='0'&&s[i]<='9')
num[s[i]-'0']++;
for(i=0;i<=9;i++)
printf("%d\u51fa\u73b0\u7684\u6b21\u6570\u4e3a\uff1a%d\n",i,num[i]);
}

#include <stdio.h>
typedef struct
{
unsigned int num0;
unsigned int num1;
unsigned int num2;
unsigned int num3;
unsigned int num4;
unsigned int num5;
unsigned int num6;
unsigned int num7;
unsigned int num8;
unsigned int num9;
}NUMCOUNT;

NUMCOUNT NumCount;
int main(void)
{
char buf[100];
memset(buf,0,100);
mmeset(&NumCount.num0,0,sizeof(NumCount));
printf("请输入一个字符串:\n");
scanf("%s",buf);
for(int i=0;i<strlen(buf);i++)
{
switch(buf[i]){
case 0:
NumCount.num0++;
break;
case 1:
NumCount.num0++;
break;
case 2:
NumCount.num0++;
break;
case 3:
NumCount.num0++;
break;
case 4:
NumCount.num0++;
break;
case 5:
NumCount.num5++;
break;
case 6:
NumCount.num6++;
break;
case 7:
NumCount.num7++;
break;
case 8:
NumCount.num8++;
break;
case 9:
NumCount.num9++;
break;
default:
break;
}
}

printf("0的个数:%d\n",NumCount.num0);
printf("1的个数:%d\n",NumCount.num1);
printf("2的个数:%d\n",NumCount.num2);
printf("3的个数:%d\n",NumCount.num3);
printf("4的个数:%d\n",NumCount.num4);
printf("5的个数:%d\n",NumCount.num5);
printf("6的个数:%d\n",NumCount.num6);
printf("7的个数:%d\n",NumCount.num7);
printf("8的个数:%d\n",NumCount.num8);
printf("9的个数:%d\n",NumCount.num9);

}

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