初二一道与因式分解有关的难题
\u521d\u4e8c\u7684\u8d85\u96be\u9898!!!(\u56e0\u5f0f\u5206\u89e3)\u7684\u786e\u5f88\u6709\u96be\u5ea6\u5440
=X(Y-1)-(Y-1)
=(X-1)(Y-1)
(4x²-4x+1)+(9y²-12y+4)=0
(2x-1)²+(3y-2)²=0
x=1/2\uff0cy=2/3.
\u7531\u4e8e\u4e0d\u77e5\u90532/3y\u8868\u793a\u662f\uff082/3\uff09y\u5462\uff0c\u8fd8\u662f2/\uff083y\uff09,\u56e0\u6b64\u5206\u4e24\u79cd\u60c5\u51b5\u5206\u89e3\uff1a
6x+\uff082/3)y=6*1/2+2/3*2/3=31/9
6x+2/\uff083y\uff09=6*1/2+2/(3*2/3)=4
(a-b)^2+(b-c)^2+(a-c)^2=0
所以a=b=c
因此是等边三角形
a^2+b^2+c^2=ab+bc+ca
2(a^2+b^2+c^2)=2(ab+bc+ca)
2a^2+2b^2+2c^2-2ab-2bc-ca=0
(a-b)^2+(b-c)^2+(a-c)^2=0
a=b=c
是等腰三角形
用因式分解的方法解下面一道题 7931×7931-7930×7932-7934×7937+7935×原式=7931*7931-(7931-1)*(7931+1)-(7935-1)*(7936+1)+7935×7936
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