sin2X-cos2X可以被化简成什么 y=sin2x-cos2x怎么化简
sin2X-cos2X\u53ef\u4ee5\u88ab\u5316\u7b80\u6210\u4ec0\u4e48
\u4ec5\u4f9b\u53c2\u8003
y
=sin2x-cos2x
=\u221a2.sin(2x-\u03c0/4)
sin2X-cos2X=√2sin2Xcosπ/4-√2cos2Xsinπ/4=√2sin(2x-π/4)可以化简了,由书上公式还可以化成√2cos(2x+π/4)。答案√2sin(2x-π/4)正确√2cos(2x+π/4)也正确
sin2x-cos2x=根号2*sin(2x-派/4)
绛旓細sin2X-cos2X=鈭2sin2Xcos蟺/4-鈭2cos2Xsin蟺/4=鈭2sin锛2x-蟺/4锛夊彲浠ュ寲绠浜嗭紝鐢变功涓婂叕寮忚繕鍙互鍖栨垚鈭2cos锛2x+蟺/4锛夈傜瓟妗堚垰2sin锛2x-蟺/4锛夋纭垰2cos锛2x+蟺/4锛変篃姝g‘
绛旓細sin2x-cos2x鍖栫畝寰椻垰2.sin(2x-蟺/4)銆傝繖涓槸涓夎鍑芥暟寰楀寲绠銆備笁瑙掑嚱鏁版槸鍩烘湰鍒濈瓑鍑芥暟涔嬩竴锛屾槸浠ヨ搴︿负鑷彉閲忥紝瑙掑害瀵瑰簲浠绘剰瑙掔粓杈逛笌鍗曚綅鍦嗕氦鐐瑰潗鏍囨垨鍏舵瘮鍊间负鍥犲彉閲忕殑鍑芥暟銆備篃鍙互绛変环鍦扮敤涓庡崟浣嶅渾鏈夊叧鐨勫悇绉嶇嚎娈电殑闀垮害鏉ュ畾涔夈備笁瑙掑嚱鏁板湪鐮旂┒涓夎褰㈠拰鍦嗙瓑鍑犱綍褰㈢姸鐨勬ц川鏃舵湁閲嶈浣滅敤锛屼篃鏄爺绌跺懆鏈熸х幇...
绛旓細sin2X-cos2X =鈭2sin2Xcos蟺/4-鈭2cos2Xsin蟺/4 =鈭2sin锛2x-蟺/4锛夊嶈鍗婅鍏紡锛歴in ( 2伪 ) = 2sin伪 路 cos伪 sin ( 3伪 ) = 3sin伪 - 4sin & sup3 ; ( 伪 ) = 4sin伪 路 sin ( 60 + 伪 ) sin ( 60 - 伪 )sin ( 伪 / 2 ) = 卤 鈭( ( 1 - cos伪...
绛旓細y =sin2x-cos2x =鈭2.sin(2x-蟺/4)
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