运用平方差公式分解因式 什么条件下可以用平方差公式进行因式分解
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1. x^2-9y^2=(x-3y)(x+3y)2. 36-25x^2=(6-5x)(6+5x)
3. x^2y-xy^2=xy(x-y)
4. mn^2-m =m(n²-1)=m(n-1)(n+1)
5 2x^3-8x=2x(x²-4)=2x(x-2)(x+2)
6. 2x^3-8x=2x(x²-4)=2x(x-2)(x+2)
7. ax^2-ay^2=a(x²-y²)=a(x-y)(x+y)
8.2x^3y-2xy^3=2xy(x²-y²)=2xy(x-y)(x+y)
1. x^2-9y^2
=(x-3y)(x+3y)
2. 36-25x^2
=(6-5x)(6+5x)
3. x^2y-xy^2
=xy(x-y)
4. mn^2-m
=m(n^2-1)
=m(n+1)(n-1)
5 2x^3-8x
=2x(x^2-4)
=2x(x+2)(x-2)
6. 2x^3-8x
=2x(x^2-4)
=2x(x+2)(x-2)
7. ax^2-ay^2
=a(x^2-y^2)
=a(x+y)(x-y)
8.2x^3y-2xy^3
=2xy(x^2-y^2)
=2xy(x+y)(x-y)
1.(X-3Y)(X+3Y)
2.(6-5X)(6+5X)
3.(X-Y）XY
4.M(N-1)(N+1)
5.6.2X(X-1)(X+1)
7.A(X-Y)(X+Y)
8.2XY(X-Y)(X+Y)
2x3y-ay2
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绛旓細=(2X+Y-Z)(Y+Z)
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绛旓細1. x^2-9y^2=(x-3y)(x+3y)2. 36-25x^2=(6-5x)(6+5x)3. x^2y-xy^2=xy(x-y)4. mn^2-m =m(n²-1)=m(n-1)(n+1)5 2x^3-8x=2x(x²-4)=2x(x-2)(x+2)6. 2x^3-8x=2x(x²-4)=2x(x-2)(x+2)7. ax^2-ay^2=...
绛旓細1. (x-y+z锛夌殑骞虫柟-(x-y-z)鐨勫钩鏂 = [ (x - y + z) + (x - y - z) ]* [ (x - y + z) - (x - y - z)]=(2x - 2y) * 2z = 4z(x - y)2. a-锛坅鐨5娆℃柟锛= - A (A^4 - 1)= - A (A² + 1)(A² - 1)= -A(A + 1)(A - 1)...
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绛旓細鍥炵瓟锛<a2-b2>=a2-b2+2ab
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